Functions (OCR GCSE Maths: Higher): Flashcards

Exam code: J560

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  • Define a function.

Cards in this collection (16)

  • Define a function.

    A function is a rule, made of one or more mathematical operations, that turns each input into an output.

    It can be thought of as a machine: numbers go in, the operations are applied, and new numbers come out.

  • Write the function x \rightarrow \boxed{\times 5} \rightarrow \boxed{+ 6} \rightarrow y as an equation.

    Apply the operations to x in the order shown, which gives this equation:

    y = 5x + 6

    The multiplication comes first, which is why it is 5x + 6 and not 5(x + 6).

  • Fill in the missing word:

    A diagram in which each input is joined by an arrow to its output is called a \_\_\_\_\_\_ diagram.

    The completed sentence is:

    A diagram in which each input is joined by an arrow to its output is called a mapping diagram.

    Turning inputs into outputs like this is called mapping.

  • Write the equation y = 2(x + 3) as a function machine with input x and output y.

    The bracket is worked out first, so the machine adds 3 and then multiplies by 2:

    x \rightarrow \boxed{+ 3} \rightarrow \boxed{\times 2} \rightarrow y

  • What is the output of \text{input} \rightarrow \boxed{\times 3} \rightarrow \boxed{- 8} \rightarrow \text{output} when the input is k?

    Put k in as the input and apply each operation in turn, which gives an output of 3k - 8.

    An input that is a letter produces an output that is an algebraic expression rather than a number.

  • Define a composite function.

    A composite function applies one function to the output of another.

    The input goes through the first function, and the result then becomes the input of the second function.

  • Function A is \boxed{\times 3} \rightarrow \boxed{- 8} and function B is \boxed{+ 5} \rightarrow \boxed{\times 2}. What is the output when 7 is put through A and then B?

    Function A gives 7 \times 3 - 8 = 13, and this output becomes the input to B.

    Function B then gives (13 + 5) \times 2 = 36, so the output is 36.

  • True or False?

    Putting x through the function \boxed{\times 2} and then the function \boxed{+ 5} gives a different output from putting it through \boxed{+ 5} first and then \boxed{\times 2}.

    True.

    The first order gives 2x + 5 but the second gives 2(x + 5) = 2x + 10, which is always 5 more.

    So in a composite function the order in which the two functions are applied matters.

  • Function P is \boxed{\times 4} and function Q is \boxed{- 3} \rightarrow \boxed{\times 2}. Find an expression for the output when x goes through P and then Q.

    Function P turns x into 4x, which then goes through Q to give (4x - 3) \times 2.

    So the output is 8x - 6.

  • Function A is \boxed{\times 3} \rightarrow \boxed{- 8} and function B is \boxed{+ 5} \rightarrow \boxed{\times 2}, and putting x through A and then B gives an output of 4x. Find the value of x.

    Putting x through A gives 3x - 8, and B then gives (3x - 8 + 5) \times 2 = 6x - 6.

    Setting 6x - 6 = 4x gives 2x = 6, so x = 3.

  • Define the inverse function of a function.

    The inverse function does the opposite of the original function, taking each output back to the input it came from.

    Putting a number through a function and then through its inverse gives back the number you started with.

  • What is the inverse of \text{input} \rightarrow \boxed{\times 6} \rightarrow \boxed{+ 4} \rightarrow \text{output}?

    The inverse function is:

    \text{input} \rightarrow \boxed{- 4} \rightarrow \boxed{\div 6} \rightarrow \text{output}

    For example, 5 goes through the original function to give 34, and the inverse takes 34 back to 5.

  • True or False?

    The inverse of the function \boxed{\times 2} \rightarrow \boxed{+ 3} is the function \boxed{\div 2} \rightarrow \boxed{- 3} as given here.

    False.

    The inverse must undo the operations in reverse order, so it is \boxed{- 3} \rightarrow \boxed{\div 2} instead.

    For example, the original function takes 1 to 5, and subtracting 3 then halving takes 5 back to 1, whereas halving then subtracting 3 gives -0.5 instead.

  • Fill in the gap to find the inverse of x \rightarrow \boxed{\times 4} \rightarrow \boxed{- 5} \rightarrow y algebraically by making x the subject:

    4x - 5 = y \Rightarrow x = \frac{\_\_\_\_\_\_}{4}

    The completed working is:

    4x - 5 = y \Rightarrow x = \frac{y + 5}{4}

    This shows that the inverse function adds 5 and then divides by 4.

  • The function \boxed{\times 3} \rightarrow \boxed{+ 2} gives an output of 17. Use its inverse to find the input.

    The inverse is \boxed{- 2} \rightarrow \boxed{\div 3}, so the input was (17 - 2) \div 3 = 5.

    Checking, 5 \times 3 + 2 = 17 as required.

  • When you find an inverse function by rearranging its equation to make x the subject, why do you then swap the letters x and y?

    Because after the rearrangement the input is y, and the inverse function is usually wanted with x as its input.

    Swapping the letters keeps the same operations but writes them with x going in, so for example \frac{y - 3}{2} becomes \frac{x - 3}{2}.

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