Determine an Empirical Formula (Edexcel GCSE Combined Science: Chemistry): Revision Note

Exam code: 1SC0

Stewart Hird

Written by: Stewart Hird

Reviewed by: Caroline Carroll

Updated on

Determine an Empirical Formula

Aim:

To determine the empirical formula of magnesium oxide by combustion of magnesium

Diagram:

Finding the Formula of Magnesium Oxide, downloadable IGCSE & GCSE Chemistry revision notes

Finding the empirical formula of magnesium oxide involves heating magnesium ribbon very strongly in a crucible. A lid is used to trap any smoke (not shown)

Method:

  • Measure mass of crucible with lid

  • Add sample of magnesium into crucible and measure mass with lid (calculate the mass of the metal by subtracting the mass of empty crucible)

  • Strongly heat the crucible over a Bunsen burner for several minutes

  • Lift the lid frequently to allow sufficient air into the crucible for the magnesium to fully oxidise without letting magnesium oxide smoke escape

  • Continue heating until the mass of crucible remains constant (maximum mass), indicating that the reaction is complete

  • Measure the mass of crucible and contents (calculate the mass of metal oxide by subtracting the mass of empty crucible)

Working out the empirical formula:

Step 1 - Calculate the masses of metal and oxygen:

  • Mass of metal:

    • Subtract the mass of the crucible from the mass of the crucible and magnesium

  • Mass of oxygen:

    • Subtract the mass of the crucible from the mass of the crucible and magnesium oxide

Step 2 – Divide each mass by the relative atomic mass (Ar)

Step 3 – Simplify the ratio

Step 4 – Write the empirical formula

Worked Example

A student heated a sample of magnesium in a crucible. The following masses were recorded:

Mass (g)

Crucible + lid

24.83

Crucible + lid + magnesium

25.07

Crucible + lid + magnesium oxide (after heating)

25.23

Step 1 - Calculate the masses of magnesium and oxygen:

mass of magnesium = 25.07 − 24.83 = 0.24 g

mass of magnesium oxide = 25.23 − 24.83 = 0.40 g

mass of oxygen gained = 0.40 − 0.24 = 0.16 g

Step 2 - Divide each mass by the relative atomic mass (Ar):

Magnesium

Oxygen

Mass (g)

0.24

0.16

Ar

24

16

Moles

0.2424 = 0.01

0.1616 = 0.01

Step 3 - Simplify the ratio:

Mg : O = 0.01 : 0.01

Mg : O = 1 : 1

Step 4 - Write the empirical formula:

The empirical formula is MgO

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Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.