Equations & Identities (Edexcel IGCSE Further Pure Maths): Exam Questions

Exam code: 4PM1

2 hours9 questions
1a
6 marks

straight f space left parenthesis x right parenthesis space equals space 2 x to the power of 3 space end exponent plus space p x squared space plus space q x space plus space 12 space space space space space p comma space q space element of space straight integer numbers

Given that space left parenthesis x space plus space 3 right parenthesis is a factor of straight f space left parenthesis x right parenthesis and that when straight f ʹ left parenthesis x right parenthesis is divided by left parenthesis x space plus space 3 right parenthesis the remainder is 37

show that p space equals space 1 spaceand find the value of q

1b
2 marks

straight f space left parenthesis x right parenthesis space equals space 2 x to the power of 3 space end exponent plus space p x squared space plus space q x space plus space 12 space space space space space p comma space q space element of space straight integer numbers

Given that space left parenthesis x space plus space 3 right parenthesis is a factor of straight f space left parenthesis x right parenthesis and that when straight f ʹ left parenthesis x right parenthesis is divided by left parenthesis x space plus space 3 right parenthesis the remainder is 37

hence factorise straight f space left parenthesis x right parenthesis spacecompletely

1c
2 marks

show that the equation space straight f space left parenthesis x right parenthesis space equals space 0 has only one real root.

2a
2 marks

straight f open parentheses x close parentheses space equals space 6 x cubed space minus space 13 x squared space plus space a x space minus 10 where a is a constant

Given that open parentheses 3 x space minus space 2 close parentheses is a factor of straight f left parenthesis x right parenthesis space

show that a space equals space 21

2b
4 marks

Hence show algebraically that the curve y space equals space straight f left parenthesis x right parenthesis has only one intersection with the x-axis.

3a
4 marks

straight f open parentheses x close parentheses equals 3 minus 4 x minus 9 x squared

Given that straight f open parentheses x close parenthesescan be expressed in the form A minus B open parentheses x plus C close parentheses squared where A, B and C are positive constants

find the value of A, the value of Band the value of C

3b
1 mark

straight f open parentheses x close parentheses equals 3 minus 4 x minus 9 x squared

Given that straight f open parentheses x close parenthesescan be expressed in the form A minus B open parentheses x plus C close parentheses squared where A, B and C are positive constants

Hence write down the maximum value of straight f open parentheses x close parentheses

3c
6 marks

The equation straight f open parentheses x close parentheses equals 0 has roots alpha and beta

Without solving the equation straight f open parentheses x close parentheses equals 0, form a quadratic equation, with integer coefficients, that has roots fraction numerator 3 alpha over denominator beta end fraction and fraction numerator 3 beta over denominator alpha end fraction

3d
1 mark

Show that left parenthesis x plus y right parenthesis cubed equals x cubed plus y cubed plus 3 x y left parenthesis x plus y right parenthesis

3e
6 marks

g open parentheses x close parentheses equals 3 x squared plus q x plus r where qand r are constants

The equation straight g left parenthesis x right parenthesis space equals space 0 has roots alpha squared minus beta and beta squared minus alpha where alpha and betaare the roots of the equation straight f open parentheses x close parentheses equals 0

Using your answer to part (d), find in simplified exact form, the value of q and the value of r

4a
2 marks

Use the factor theorem to show that open parentheses 4 x minus 1 close parentheses is a factor of

straight f open parentheses x close parentheses equals 64 x cubed minus 64 x squared plus 3

4b
4 marks

Use the factor theorem to show that open parentheses 4 x minus 1 close parentheses is a factor of

straight f open parentheses x close parentheses equals 64 x cubed minus 64 x squared plus 3

Hence, or otherwise, find the exact roots of the equation

straight f open parentheses x close parentheses equals 0

4c
3 marks

A geometric series G has first term a and common ratio r
The third term of G is 9 and the sum to infinity of G is 192

Show that 64 r cubed minus 64 r squared plus 3 equals 0

4d
1 mark

A geometric series G has first term a and common ratio r
The third term of G is 9 and the sum to infinity of G is 192

Given that r is a rational number

write down the value of r

4e
2 marks

A geometric series G has first term a and common ratio r
The third term of G is 9 and the sum to infinity of G is 192

show that a =144

4f
4 marks

The sum to n terms of G is S subscript n

Using logarithms, find the least value of n such that S subscript n greater than 191.9

5
9 marks

straight f apostrophe left parenthesis x right parenthesis equals 18 x squared minus 2 x plus 13

Given that open parentheses 2 x minus 1 close parentheses is a factor of straight f open parentheses x close parentheses

show that the curve with equation y equals straight f open parentheses x close parentheseshas only one intersection with the x-axis.

6a
5 marks

straight g apostrophe left parenthesis x right parenthesis equals m x squared minus 10 x minus 37 where m is an integer

The curve y equals straight g open parentheses x close parentheses passes through the point with coordinates open parentheses 1 comma 20 close parentheses

Given that open parentheses x minus 5 close parenthesesis a factor of straight g open parentheses x close parentheses

show that straight g left parenthesis x right parenthesis equals 2 x cubed minus 5 x squared minus 37 x plus 60

6b
3 marks

straight g apostrophe left parenthesis x right parenthesis equals m x squared minus 10 x minus 37 where m is an integer

The curve y equals straight g open parentheses x close parentheses passes through the point with coordinates open parentheses 1 comma 20 close parentheses

Given that open parentheses x minus 5 close parenthesesis a factor of straight g open parentheses x close parentheses

Hence, or otherwise, use algebra to solve the equation straight g open parentheses straight x close parentheses equals 0

7a
4 marks

The point A has coordinates (–5, 3), the point B has coordinates (4, 0) and the point C has coordinates (–1, 5).

The line l passes through C and is perpendicular to A B.

Find an equation of l .
Give your answer in the form a x plus b y plus c equals 0 where a, b and c are integers.

7b
3 marks

The line l intersects A B at the point D.

Show that the coordinates of D are (-2, 2).

7c
2 marks

The point A has coordinates (–5, 3), the point B has coordinates (4, 0) and the point C has coordinates (–1, 5).

Show that l is not the perpendicular bisector of A B.

7d
4 marks

Find the value of tan space angle A B C.
Give your answer in its simplest form.

8a
6 marks

straight f left parenthesis x right parenthesis equals x cubed plus p x squared plus q x plus 6 where p and q are constants.

Given that open parentheses x minus 1 close parentheses is a factor of straight f open parentheses x close parentheses and that when straight f open parentheses x close parentheses is divided by open parentheses x plus 1 close parentheses the remainder is 8

(i) show that p equals negative 2

(ii) find the value of q

8b
3 marks

Hence, solve the equation straight f open parentheses x close parentheses equals 0

9a
4 marks
Graph showing a circle, \(x^2 + y^2 = 11\), and parabola, \(y = x^2 + 1\). Shaded area R between curves. Points A, B, and centre O marked. Diagram not to scale.

The region R, shown shaded in Figure 2, is bounded by the curve with equation y equals x squared plus 1and the curve with equation x squared plus y squared equals 11

The two curves intersect at the point A and at the point B.

Find the xcoordinate of the point Aand the x coordinate of the point B.

9b
5 marks

The region R is rotated through 360° about the x‑axis.

Use algebraic integration to find the volume, to 2 decimal places, of the solid generated.