Constructing Models (College Board AP® Precalculus): Study Guide

Roger B

Written by: Roger B

Reviewed by: Mark Curtis

Updated on

Polynomial models

How can a model be constructed from a contextual scenario?

  • A model is a function that represents a real-world situation mathematically

  • A model can be constructed based on restrictions identified in a mathematical or contextual scenario

    • These restrictions come from the given information, such as

      • specific data values

      • initial conditions

      • or known behaviors of the quantities involved

  • The general approach is

    • Identify the appropriate function type

    • Use the given data or conditions to set up equations involving the unknown constants in the function

    • Solve the system of equations to find the values of the constants

How do you construct a polynomial model from data points?

  • If you are given data points and told to use a polynomial model of a specific form (e.g. D left parenthesis t right parenthesis equals a t squared plus b t plus c)

    • you can find the unknown constants by substituting each data point into the equation

    • Each data point left parenthesis x comma y right parenthesis gives you one equation

    • You need as many data points as there are unknown constants

  • E.g. a quadratic a t squared plus b t plus c has 3 unknowns (a, b, c),

    • so you need 3 data points to set up 3 equations

  • A linear model y = mx + b has 2 unknowns

    • so you need 2 data points

  • Once you have the system of equations

    • solve for the unknown constants

  • You can solve algebraically (substitution, elimination)

    • or you can use a graphing calculator to solve the system

How can a model be constructed using transformations?

  • A model of a data set or a contextual scenario can be constructed using transformations of a parent function

  • If you recognize that a data set or scenario follows the shape of a known parent function (e.g. x^2, x^3), you can apply transformations to fit the data

    • Vertical and horizontal translations (shifts)

    • Vertical and horizontal dilations (stretches/compressions)

  • E.g. if data appears to follow a parabola with its vertex at (3, 5), opening upward

    • you might model it as space f left parenthesis x right parenthesis equals a left parenthesis x minus 3 right parenthesis squared plus 5

    • and use a data point to find a

How can technology be used to construct a model?

  • A model of a data set can be constructed using technology and regressions

  • A regression uses an algorithm to find the function of a given type that best fits the data

  • Available regression types for polynomial models include:

    • Linear regression

      • fits a model of the form y = ax + b

    • Quadratic regression

      • fits a model of the form y = ax^2 + bx + c

    • Cubic regression

      • fits a model of the form y = ax^3 + bx^2 + cx + d

    • Quartic regression

      • fits a model of the form y = ax^4 + bx^3 + cx^2 + dx + e

  • To perform a regression on a graphing calculator

    • Enter the data into lists

    • Select the appropriate regression type

    • The calculator will output the values of the constants

Examiner Tips and Tricks

On the exam, if you are asked to write equations that can be used to find the constants in a model, make sure you show the equations before solving them.

  • This is often a separate scoring point from actually finding the values of the constants

On a calculator part of the exam, you can use your graphing calculator to solve systems of equations.

  • So even if you struggle with the algebra, you can still earn the point for finding the correct values

Worked Example

A town's population, in thousands, is recorded at three different times. At time t equals 0 years, the population was 12 thousand. At t equals 3 years, the population was 15.6 thousand. At t equals 6 years, the population was 16.8 thousand.

The population can be modeled by the function P given by P left parenthesis t right parenthesis equals a t squared plus b t plus c, where P(t) is the population, in thousands, and t is the number of years since the population was first recorded.

(a) Use the given data to write three equations that can be used to find the values for constants a, b, and c in the expression for P left parenthesis t right parenthesis.

Answer:

Substitute each data point into P(t) = at^2 + bt + c

P(0) = 12
a left parenthesis 0 right parenthesis squared plus b left parenthesis 0 right parenthesis plus c equals 12
c equals 12

P(3) = 15.6
a left parenthesis 3 right parenthesis squared plus b left parenthesis 3 right parenthesis plus c equals 15.6
9a + 3b + c = 15.6

P(6) = 16.8
a left parenthesis 6 right parenthesis squared plus b left parenthesis 6 right parenthesis plus c equals 16.8
36a + 6b + c = 16.8

(b) Find the values for a, b, and c as decimal approximations.

Answer:

From the first equation

c = 12

Substitute into the other two equations:

9 a plus 3 b plus 12 equals 15.6 space space rightwards double arrow space space 9 a plus 3 b equals 3.6 space space space space space circle enclose 1

36 a plus 6 b plus 12 equals 16.8 space space rightwards double arrow space space 36 a plus 6 b equals 4.8 space space space space space circle enclose 2

Multiplying equation 1 by 2

2 cross times open parentheses 9 a plus 3 b close parentheses equals 2 cross times 3.6

18 a plus 6 b equals 7.2 space space space space space circle enclose 3

Subtracting equation 3 from equation 2

space space space space space space 36 a plus 6 b equals 4.8
minus open parentheses 18 a plus 6 b equals 7.2 close parentheses
minus negative negative negative negative negative negative negative negative
space space space space space space space space space space space space 18 a space equals negative 2.4

a equals negative fraction numerator 2.4 over denominator 18 end fraction equals negative 2 over 15 equals negative 0.133333...

Substitute that value of a into one of the original equations and solve for b

  • E.g., substituting into equation 1 gives

table row cell 9 open parentheses negative 2 over 15 close parentheses plus 3 b end cell equals cell 3.6 end cell row cell 3 b minus 1.2 end cell equals cell 3.6 end cell row cell 3 b end cell equals cell 4.8 end cell end table

b equals fraction numerator 4.8 over denominator 3 end fraction equals 1.6

Those are the three answers you are looking for

  • Round the answer for a to 3 decimal places, to give the decimal approximation

a equals negative 0.133 space open parentheses 3 space straight d. straight p. close parentheses, b equals 1.6, c = 12

Piecewise-defined models

What is a piecewise-defined function model?

  • A piecewise-defined function model can be constructed through a combination of modeling techniques

  • A piecewise-defined model is appropriate when a data set or contextual scenario demonstrates different characteristics over different intervals

    • E.g. a quantity might increase linearly for a period, then remain constant, then decrease

    • Each 'piece' of the model captures the behavior over one interval

How do you construct a piecewise-defined model?

  • Identify the intervals where the behavior changes

    • Look for points where the pattern or trend shifts

  • Choose an appropriate function type for each interval

    • One interval might be best modeled by a linear function, another by a quadratic, etc.

  • Construct each piece separately

    • Use the techniques for polynomial models, above

    • I.e. substituting data points, using transformations, or regression

  • Combine the pieces into a single piecewise-defined function

    • Be sure to specify the domain for each piece

      • Make sure the domain intervals do not overlap

      • Pay attention to whether endpoints use \leq or <

  • Depending on the context, the pieces may or may not need to connect at the boundary points

    • In many real-world models, the function value is expected to be the same from both sides at the join point

Worked Example

A city's water reservoir is being filled. For the first 5 hours (0 \leq t \leq 5), water flows in at a constant rate, and the volume of water in the reservoir, in thousands of gallons, is given by V(t) = 8t + 10.

After 5 hours, the flow rate decreases. At t = 5, t = 7, and t = 9, the volumes are 50, 58, and 62 thousand gallons respectively.

(a) Determine a quadratic model of the form Q left parenthesis t right parenthesis equals a t squared plus b t plus c for the volume of water in the reservoir for the interval 5 \leq t \leq 9.

Answer:

Substitute each data point into Q(t) = at^2 + bt + c

Q(5) = 50:

25 a plus 5 b plus c equals 50 space space space space space circle enclose 1

Q(7) = 58:

49 a plus 7 b plus c equals 58 space space space space space circle enclose 2

Q(9) = 62:

81 a plus 9 b plus c equals 62 space space space space space circle enclose 3

Subtracting equation 1 from equation 2 gives

24 a plus 2 b equals 8 space space space space space circle enclose 4

Subtracting equation 2 from equation 3 gives

32 a plus 2 b equals 4 space space space space space circle enclose 5

Equations 4 and 5 are simultaneous equations in a and b only

Subtracting equation 4 from equation 5 gives

8 a equals negative 4

a equals fraction numerator negative 4 over denominator 8 end fraction equals negative 1 half equals negative 0.5

Substitute that back into equation 4 and solve for b

table row cell 24 left parenthesis negative 0.5 right parenthesis plus 2 b end cell equals 8 row cell negative 12 plus 2 b end cell equals 8 row cell 2 b end cell equals 20 end table

table row b equals cell 20 over 2 equals 10 end cell end table

Substitute those values into equation 1 and solve for c

table row cell 25 left parenthesis negative 0.5 right parenthesis plus 5 left parenthesis 10 right parenthesis plus c end cell equals 50 row cell negative 12.5 plus 50 plus c end cell equals 50 row cell c plus 37.5 end cell equals 50 row c equals cell 12.5 end cell end table

Therefore

Q(t) = -0.5t^2 + 10t + 12.5

(b) Write a piecewise-defined function W(t) that models the volume of water in the reservoir for 0 \leq t \leq 9.

Answer:

Put the two pieces together

  • Be sure to indicate the correct, non-overlapping intervals for the two pieces

W open parentheses t close parentheses equals open curly brackets table row cell 8 t plus 10 comma space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 less or equal than t less or equal than 5 end cell row cell negative 0.5 t squared plus 10 t plus 12.5 comma space space space space space space space 5 less than t less or equal than 9 end cell end table close

Rational models

When is a rational function model appropriate?

  • Data sets and aspects of contextual scenarios involving quantities that are inversely proportional can often be modeled by rational functions

  • Two quantities are inversely proportional when

    • one quantity increases as the other decreases

    • and their product is constant

  • If bold italic y is inversely proportional to bold italic x,

    • then space y equals k over x for some constant k

  • More generally, y might be inversely proportional to a power of x

    • E.g. y is inversely proportional to x squared

      • in which case space y equals k over x squared

  • Examples of inverse proportionality in context:

    • The time to complete a job is inversely proportional to the number of workers

      • assuming each worker works at the same rate

    • The gravitational force between two objects is inversely proportional to the square of the distance between them

      • space F equals k over d squared

    • The electromagnetic force between two charged particles is also inversely proportional to the square of the distance between them

How do you construct a rational function model?

  • Identify that the relationship involves inverse proportionality

    • Look for language like "inversely proportional to"

    • or data where one quantity decreases as another increases

      • with their product roughly constant

  • Set up the general form of the model

    • E.g. space y equals k over x or space y equals k over x squared, depending on the relationship

    • More complex rational models may take the form space y equals fraction numerator a over denominator x minus h end fraction plus k (a transformed reciprocal function)

  • Use given data to find the unknown constant(s)

    • Substitute a known input-output pair and solve for the constant

Examiner Tips and Tricks

If a question describes a quantity that "varies inversely" with another, this is a direct signal to use a rational function model.

Remember that for an inversely proportional relationship space y equals k over x, the product xy = k is constant.

  • This is a quick way to verify that a data set is inversely proportional

Worked Example

A scientist is studying the intensity of a light source. The intensity I, measured in lumens per square meter, at a distance d meters from the source is inversely proportional to the square of the distance. At a distance of 2 meters, the intensity is measured to be 45 lumens per square meter.

(a) Construct a model for the intensity I as a function of the distance d.

Answer:

Since I is inversely proportional to d^2, you can write

I left parenthesis d right parenthesis equals k over d squared

Use the data point I(2) = 45 to find k

table row 45 equals cell k over 2 squared end cell row 45 equals cell k over 4 end cell row cell 4 cross times 45 end cell equals k end table

k = 180

Therefore

I(d) = \frac{180}{d^2}

(b) Use the model to predict the intensity at a distance of 5 meters from the source.

Answer:

Substitute d equals 5 into the answer from part (a)

table row cell I left parenthesis 5 right parenthesis end cell equals cell 180 over 5 squared end cell row blank equals cell 180 over 25 end cell row blank equals cell 7.2 end cell end table

The intensity at a distance of 5 meters is 7.2 lumens per square meter

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Roger B

Author: Roger B

Expertise: Maths Content Creator

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Mark Curtis

Reviewer: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.