Shapes of Molecules (Cambridge (CIE) A Level Chemistry): Flashcards

Exam code: 9701

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  • Define VSEPR theory.

Cards in this collection (9)

  • Define VSEPR theory.

    VSEPR theory (Valence Shell Electron Pair Repulsion theory) states that electron pairs around a central atom repel each other and arrange themselves as far apart as possible to minimise repulsion, determining the shape of the molecule.

  • State the three key rules of VSEPR theory.

    1. All electron pairs (bonding and lone pairs) spread out as far apart as possible.

    2. Lone pairs repel more strongly than bonding pairs.

    3. Multiple bonds behave like a single electron domain when determining shape.

  • True or False?

    Lone pairs repel neighbouring electron pairs more strongly than bonding pairs do.

    True.

    Lone pairs are held closer to the nucleus and spread over a larger region of space, causing greater repulsion. This reduces bond angles compared to the regular geometry.

  • NH3 has a .......... shape with a bond angle of .......... because one lone pair repels the bonding pairs, reducing the angle from 109.5°.

    NH3 has a trigonal pyramidal shape with a bond angle of 107° because one lone pair repels the bonding pairs, reducing the angle from 109.5°.

  • What shape and bond angle does SF6 adopt, and why?

    SF6 adopts an octahedral shape with bond angles of 90°. Sulfur forms 6 single bonds with no lone pairs, so all six bonding pairs repel each other equally.

  • True or False?

    CO2 has a bent shape because of lone pairs on the carbon atom.

    False.

    CO2 is linear (180°). Carbon has no lone pairs and forms two double bonds, each counted as one electron domain. The two domains arrange linearly.

  • PCl5 has a .......... shape with bond angles of .......... (equatorial) and .......... (axial).

    PCl5 has a trigonal bipyramidal shape with bond angles of 120° (equatorial) and 90° (axial).

  • Why does H2O have a bond angle of 104.5° rather than the tetrahedral angle of 109.5°?

    Oxygen in H2O has two lone pairs in addition to two bonding pairs. The lone pairs repel more strongly than bonding pairs, compressing the H-O-H bond angle from 109.5° to 104.5°.

  • True or False?

    BF3 has a trigonal planar shape with bond angles of 120°.

    True.

    Boron forms 3 bonding pairs and has no lone pairs. The three electron domains arrange with trigonal planar geometry, giving bond angles of 120°.

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