Acids, Bases & Buffers (OCR A Level Chemistry A): Flashcards

Exam code: H432

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  • Define Brønsted acid

Cards in this collection (37)

  • Define Brønsted acid

    A Brønsted acid is a species that can donate a proton (H+ ion). For example, HCl donates H+ to form Cl-.

  • Why do a conjugate acid and its conjugate base differ by exactly one H+ ion?

    When an acid donates a proton, the species left behind is its conjugate base, which has one fewer H+. The two are therefore always related by one proton transfer.

  • Define Brønsted base

    A Brønsted base is a species that can accept a proton (H+ ion). For example, OH- accepts H+ to form water.

  • Acids are classified by the number of ionisable hydrogen atoms they can donate. HCl is .......... (one H+), H2SO4 is .......... (two H+) and H3PO4 is .......... (three H+).

    Acids are classified by the number of ionisable hydrogen atoms they can donate. HCl is monobasic (one H+), H2SO4 is dibasic (two H+) and H3PO4 is tribasic (three H+).

  • Why are spectator ions cancelled when writing ionic equations for acid reactions?

    Spectator ions appear unchanged on both sides of the equation and play no part in the reaction, so cancelling them reveals the active species actually involved in the chemical change.

  • True or False?

    A dibasic acid contains two ionisable hydrogen atoms per molecule and ionises in two steps.

    True.

    A dibasic acid such as H2SO4 has two ionisable H atoms and undergoes ionisation in two separate steps, donating one H+ at a time.

  • What three products form when an acid reacts with a metal carbonate?

    1. A salt

    2. Water

    3. Carbon dioxide gas

    The ionic equation shows H+ reacting with CO32- to give H2O and CO2.

  • Define weak acid

    A weak acid is an acid that only partially dissociates in aqueous solution, establishing an equilibrium between the undissociated acid and its ions.

  • Why does a larger Ka value indicate a stronger weak acid?

    A larger Ka means the equilibrium lies further to the right, so a greater proportion of the acid has dissociated and the concentration of H+ ions is higher.

  • Define acid dissociation constant (Ka)

    An acid dissociation constant (Ka) is the equilibrium constant for the partial dissociation of a weak acid HA, defined as Ka = [H+][A-] / [HA], with units mol dm-3.

  • pKa is calculated using the expression pKa = .......... Ka. A .......... pKa value corresponds to a stronger weak acid.

    pKa is calculated using the expression pKa = -log Ka. A lower pKa value corresponds to a stronger weak acid.

  • What is the definition of pH?

    pH = -log[H+], where [H+] is the concentration of hydrogen ions in mol dm-3. The scale is logarithmic with base 10.

  • True or False?

    The ionic product of water, Kw, equals 1 × 10-14 mol2 dm-6 at 298 K.

    True.

    Kw = [H+][OH-] and always equals 1 × 10-14 mol2 dm-6 at 298 K, reflecting the self-ionisation of water.

  • Why does pure water contain both H+ and OH- ions even though it is neutral?

    Water undergoes self-ionisation, where a small proportion of molecules donate a proton to another water molecule, producing equal concentrations of H+ and OH- so pH = 7 at 298 K.

  • Define strong acid

    A strong acid is one that is completely ionised in aqueous solution, so the concentration of H+ equals the initial concentration of the acid.

  • Why can the concentration of H+ be taken as equal to the concentration of a strong acid when calculating pH?

    Strong acids are fully ionised, so every mole of acid produces one mole of H+. The H+ contribution from water self-ionisation is negligible in comparison.

  • To find the pH of a strong base, first calculate [H+] using [H+] = .......... ÷ [OH-], then apply pH = .......... [H+].

    To find the pH of a strong base, first calculate [H+] using [H+] = Kw ÷ [OH-], then apply pH = -log [H+].

  • Why is [H+] for a weak acid calculated as √(Ka × [HA]) rather than simply [HA]?

    A weak acid only partially dissociates, so [H+] is much smaller than [HA]. Setting [H+] = [A-] and combining terms in the Ka expression gives [H+]2 = Ka × [HA], hence the square root.

  • True or False?

    When calculating the pH of a weak acid, the initial concentration of the undissociated acid is assumed to remain constant at equilibrium.

    True.

    Because the degree of dissociation is very small, the change in [HA] is negligible, so the initial concentration is used as the equilibrium concentration in the Ka expression.

  • What are the two key assumptions made when using Ka to calculate the pH of a weak acid?

    First, [H+] = [A-] at equilibrium (H+ from water is negligible). Second, the initial concentration of the undissociated acid equals its equilibrium concentration because dissociation is so slight.

  • True or False?

    A stronger weak acid has a larger Ka value and a lower pKa value.

    True.

    A larger Ka means greater dissociation, giving more H+. Since pKa = -log Ka, a larger Ka produces a lower pKa.

  • How does the validity of the Ka approximation change as acid strength increases?

    As the acid becomes stronger, dissociation increases and the difference between initial [HA] and equilibrium [HA] grows, making the assumption that initial [HA] is unchanged less valid and introducing greater error.

  • Define buffer solution

    A buffer solution is one that resists changes in pH when small amounts of acid or alkali are added, by maintaining a near-constant concentration of H+ ions.

  • Why does a mixture of a weak acid and its conjugate salt act as a buffer?

    The mixture provides a large reservoir of both the undissociated weak acid (to react with added OH-) and the conjugate base (to react with added H+), keeping [H+] nearly constant.

  • The Henderson-Hasselbalch equation states: pH = p.......... + log10 ([.......... ] / [acid]).

    The Henderson-Hasselbalch equation states: pH = pKa + log10 ([salt ] / [acid]).

  • How does an ethanoic acid/sodium ethanoate buffer respond when H+ ions are added?

    The extra H+ reacts with CH3COO- to form CH3COOH, shifting the equilibrium left and consuming the added acid so pH remains almost constant.

  • True or False?

    If strong alkali is added in excess to a weak acid, a buffer solution is formed.

    False.

    For a buffer to form, the weak acid must be in excess so that both the acid and its conjugate salt are present. If the alkali is in excess, the weak acid is fully consumed and no buffer forms.

  • What two pieces of information must be stated to gain full marks when explaining how an acidic buffer forms from mixing excess weak acid with a strong alkali?

    You must state that the weak acid is in excess (partial neutralisation has occurred) and that both the weak acid and its conjugate salt are present in the resulting solution.

  • True or False?

    When OH- is added to an ethanoic acid buffer, the equilibrium shifts to the right, producing more CH3COO-.

    True.

    OH- reacts with H+ to form water, lowering [H+]. The equilibrium shifts right as CH3COOH dissociates further to replenish H+ and maintain a constant pH.

  • Why does HCO3- in blood act as a buffer against rising H+ concentration?

    Excess H+ reacts with HCO3- to shift the equilibrium CO2 + H2O ⇌ H+ + HCO3- to the left, removing H+ and preventing acidosis.

  • Define equivalence point

    An equivalence point (stoichiometric point) is the stage in a titration where the acid and base have reacted in exact molar ratio, located at the midpoint of the vertical section of the pH curve.

  • Why is there no suitable indicator for a weak acid-weak base titration?

    There is no sharp, vertical section on the pH curve, so no indicator has a colour-change range narrow enough to fall within the gradual pH change at the equivalence point.

  • Define acid-base indicator

    An acid-base indicator is a weak acid (HIn) whose undissociated form and conjugate base (In-) have different colours, allowing it to signal the endpoint of a titration by a colour change.

  • In a strong acid-strong base titration the pH changes from .......... to .......... at the end-point, so both methyl red and .......... are suitable indicators.

    In a strong acid-strong base titration the pH changes from 4 to 10 at the end-point, so both methyl red and phenolphthalein are suitable indicators.

  • Why does an indicator change colour gradually over a pH range rather than sharply at a single pH?

    The colour depends on the ratio of [HIn] to [In-], which shifts continuously as pH changes. The transition occurs over a range centred on the pKa of the indicator, not at a single abrupt point.

  • True or False?

    Phenolphthalein is suitable for weak acid-strong base titrations but not for strong acid-weak base titrations.

    True.

    For weak acid-strong base the pH range at the end-point is 7-10, which matches phenolphthalein (pKa ≈ 9.4). For strong acid-weak base the range is 4-7, so methyl red is required instead.

  • What is the criterion for choosing a suitable indicator for a given titration?

    The colour-change pH range of the indicator must fall within the steep, near-vertical section of the titration curve at the equivalence point. The indicator pKa should match the pH at the equivalence point.

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