Circles (Edexcel A Level Maths: Pure): Flashcards

Exam code: 9MA0

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Cards in this collection (27)

  • What is the equation of a circle with centre \left(a, b\right) and radius r?

    \left(x - a\right)^{2} + \left(y - b\right)^{2} = r^{2}

  • True or False?

    The circle \left(x + 12\right)^{2} + \left(y - 9\right)^{2} = 73 has centre \left(12, -9\right).

    False.

    The centre is \left(-12, 9\right). The numbers in the brackets have the opposite signs to the coordinates of the centre.

  • A circle with centre \left(-3, 2\right) and radius 7 has equation \left(x + 3\right)^{2} + \left(y - 2\right)^{2} = \_\_\_\_\_\_

    A circle with centre \left(-3, 2\right) and radius 7 has equation \left(x + 3\right)^{2} + \left(y - 2\right)^{2} = 49

  • True or False?

    The number on the right-hand side of a circle equation is the radius.

    False.

    It is the radius squared. Take the square root, so a right-hand side of 25 gives r = 5.

  • A circle has equation \left(x - 3\right)^{2} + \left(y + 1\right)^{2} = 16. What are its centre and radius?

    Centre \left(3, -1\right), radius 4.

  • What do you do when a circle equation is not in the form \left(x - a\right)^{2} + \left(y - b\right)^{2} = r^{2}?

    Rearrange it into that form, usually by completing the square. That is the form the centre and radius can be read off from.

  • Completing the square: x^{2} - 6x = \left(x - 3\right)^{2} - \_\_\_\_\_\_

    x^{2} - 6x = \left(x - 3\right)^{2} - 9

  • What is the general form of the equation of a circle?

    x^{2} + y^{2} + 2fx + 2gy + c = 0

  • From the general form x^{2} + y^{2} + 2fx + 2gy + c = 0, what are the centre and radius?

    Centre \left(-f, -g\right), radius \sqrt{f^{2} + g^{2} - c}

  • Find the centre and radius of the circle x^{2} - 6x + y^{2} + y - 15 = 0.

    Completing the square gives \left(x - 3\right)^{2} + \left(y + \frac{1}{2}\right)^{2} = \frac{97}{4}

    Centre \left(3, -\frac{1}{2}\right), radius \frac{\sqrt{97}}{2}

  • Define chord.

    A chord of a circle is a straight line segment between any two points on the circle.

  • What is the midpoint of the line segment joining \left(x_{1}, y_{1}\right) and \left(x_{2}, y_{2}\right)?

    \left(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}\right)

  • Define perpendicular bisector.

    The perpendicular bisector of a line segment is perpendicular to it and passes through its midpoint.

  • Complete the formula for the gradient of the perpendicular bisector of the line segment joining \left(x_{1} , y_{1}\right) and \left(x_{2} , y_{2}\right), by filling in the denominator:

    - \left(\frac{x_{2} - x_{1}}{\_\_\_\_\_\_}\right)

    -\left(\frac{x_{2} - x_{1}}{y_{2} - y_{1}}\right)

    The x and y differences swap places compared with the gradient of the segment itself.

  • What does the perpendicular bisector of a chord always pass through?

    The centre of the circle.

  • True or False?

    Every chord of a circle passes through its centre.

    False.

    Only a diameter does. A chord joins any two points on the circle, so most chords miss the centre.

  • How can you find the centre of a circle if you know three points on it?

    Draw any two chords between the points, then construct the perpendicular bisector of each. The two bisectors meet at the centre.

  • Define circumcircle.

    The circumcircle of a triangle is the unique circle passing through all three of its vertices.

  • What does the angle in a semicircle property say?

    Any angle at the circumference in a semicircle is a right angle.

    Equivalently, if a triangle is right-angled, its hypotenuse is a diameter of its circumcircle.

  • True or False?

    Every triangle has a circumcircle.

    True.

    It is always possible to draw a unique circle through the three vertices of any triangle.

  • Where is the centre of the circumcircle of a right-angled triangle?

    At the midpoint of the hypotenuse, because the hypotenuse is a diameter.

  • For a right-angled triangle, the radius of its circumcircle is \_\_\_\_\_\_ the length of the hypotenuse.

    For a right-angled triangle, the radius of its circumcircle is half the length of the hypotenuse.

  • How can you show that a triangle is right-angled?

    Two ways, depending on what you are given.

    If you know the side lengths, show that they satisfy Pythagoras' theorem.

    If the three vertices lie on a circle, show that one side is a diameter, since the angle in a semicircle is a right angle.

  • Define tangent (to a circle).

    A tangent is a line that touches a circle at a single point without cutting across it.

  • How is a tangent related to the radius at the point where it touches the circle?

    The tangent is perpendicular to that radius.

  • The gradient of a tangent to a circle is the negative \_\_\_\_\_\_ of the gradient of the radius at the point where the tangent touches.

    The gradient of a tangent is the negative reciprocal of the gradient of the radius at that point.

    For example, if the radius has gradient \frac{2}{3}, the tangent has gradient -\frac{3}{2}.

  • What do you need in order to write down the equation of a tangent at a point P on a circle?

    The gradient of the tangent, which is perpendicular to the radius at P, and the coordinates of P.

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