Integration (Edexcel IGCSE Further Pure Maths): Exam Questions

Exam code: 4PM1

1 hour5 questions
1
8 marks
Graph showing a curve crossing the x-axis at points (-1,0), O, (b,0), and (a,0) with shaded area between (-1,0) and (b,0). Diagram not accurately drawn.

Figure 3 shows a sketch of the curve with equation y space equals space straight f left parenthesis x right parenthesis, which passes through the points with coordinates space left parenthesis negative 1 comma space 0 right parenthesis comma space left parenthesis b comma space 0 right parenthesis and left parenthesis a comma space 0 right parenthesis where 0 space less than space b space less than space a.

Given that straight f apostrophe left parenthesis x right parenthesis space equals space 6 x squared space – space 26 x space plus space 12 find,

(i) the value of a,

(ii) the value of b.

2a
2 marks

Show that cos left parenthesis A space – space B right parenthesis space – space cos left parenthesis A space plus space B right parenthesis space equals space 2 sin space A space sin space B

2b
1 mark

Hence express space 2 sin space 5 x space sin space 3 x in the form cos space m x space – space cos space n x spacewhere m and n are integers, giving the value of m and the value of n,

2c
4 marks

(i) Find integral 4 sin space 5 theta space sin 3 theta space straight d theta

(ii) Hence evaluate integral subscript 0 superscript straight pi over 6 end superscript 4 sin space 5 theta space sin 3 theta space straight d theta, giving your answer in the form fraction numerator a square root of b over denominator c end fraction where a, b and c are integers.

3a
4 marks

Using formulae (opens in a new tab), show that

(i) cos space 2 A space equals space 2 space cos to the power of 2 space space end exponent A space minus space 1

(3)

(ii) sin space 2 space A space equals space 2 sin space A space cos space A

(1)

3b
4 marks

Show that cos cubed space A space equals space fraction numerator cos space 3 A space plus space 3 space cos space A space over denominator 4 end fraction

3c
4 marks

Hence, or otherwise, solve, giving exact values in terms of pi

8 space cos cubed space open parentheses theta over 2 close parentheses space minus space 6 space cos space open parentheses theta over 2 close parentheses space minus space 1 space equals space 0 for 0 space less-than or slanted equal to space theta space less-than or slanted equal to space 2 straight pi

3d
4 marks

use algebraic integration to find the exact value of

integral subscript 0 superscript straight pi over 6 end superscript open parentheses 4 space cos cubed space theta space minus space sin space 2 theta close parentheses space straight d theta

4a
2 marks

Using a formula (opens in a new tab), show that

cos space 2 theta equals 2 space cos squared space theta minus 1

4b
4 marks

Using a formula (opens in a new tab), show that

cos space 2 theta equals 2 space cos squared space theta minus 1

Hence show that

integral subscript pi over 3 end subscript superscript fraction numerator 3 pi over denominator 4 end fraction end superscript open parentheses 2 space cos to the power of 2 space end exponent theta minus 1 close parentheses   d theta equals negative fraction numerator a plus square root of b over denominator c end fraction

where a, b and c are integers to be found.

4c
8 marks
Graph with two curves, \(C_1\) and \(C_2\), intersecting x-axis at O. Shaded region R between points A and B on horizontal axis \(θ\). Diagram not to scale.

Figure 3 shows part of the curve C subscript 1 with equation y equals 2 space cos squared space theta minus 1and part of the curve C subscript 2 with equation y equals negative cos space theta

Point B is the intersection of C subscript 1 and C subscript 2 as shown in Figure 3

Point Aopen parentheses fraction numerator 3 straight pi over denominator 4 end fraction comma 0 close parentheses is the intersection of C subscript 1 with the theta-axis as shown in Figure 3

Point E open parentheses pi over 2 comma 0 close parentheses is the intersection of C subscript 2 with the theta-axis as shown in Figure 3

The finite region R, shown shaded in Figure 3, is bounded by the theta-axis, C subscript 1 and C subscript 2

Use calculus to find, in its simplest form, the exact area of R

5a
3 marks

Using formulae (opens in a new tab) , show that

(i) sin space 2 A equals 2 space sin space A space cos space A

(ii) cos space 2 A equals 2 cos squared space A minus 1

5b
4 marks

f open parentheses theta close parentheses equals fraction numerator 2 tan theta over denominator 1 plus tan squared theta end fraction

Show that straight f left parenthesis theta right parenthesis equals sin space 2 theta

5c
6 marks

Solve, in radians to 3 significant figures, for negative pi over 2 less-than or slanted equal to x less-than or slanted equal to pi over 2, the equation

5 space tan open parentheses x plus pi over 6 close parentheses equals open square brackets 1 plus tan squared open parentheses x plus pi over 6 close parentheses close square brackets open square brackets 1 minus 2 space cos squared open parentheses x plus pi over 6 close parentheses close square brackets

5d
4 marks

Using calculus, find the exact value of

integral subscript 0 superscript pi over 2 end superscript open parentheses fraction numerator 4 space tan space theta over denominator 1 plus tan squared space theta end fraction minus cos space 5 theta plus 2 close parentheses   straight d theta