Constants of Integration (Edexcel IGCSE Further Pure Maths): Revision Note

Exam code: 4PM1

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Finding the Constant of Integration

What is the constant of integration? 

  • The constant of integration is the c used when finding an indefinite integral 

    • e.g. (3x25) dx=x35x+c

    • c can be any constant

  • Integration and differentiation are inverse operations

    • That means if you differentiate your answer to an integral...

      • ...it should turn back into the original function you integrated

    • The 'problem' is that the derivative of a constant is zero

      • ddx(x35x)=3x25

      • ddx(x35x+7)=3x25

      • ddx(x35x498)=3x25

    • So x35x plus or minus any constant is a valid solution to (3x25) dx

  • But consider the graph of y=x35x+c

    • Different values of c represent different vertical translations of the graph

    • If we know one point on that graph we can work out the value of c

How do I find the constant of integration?

  • On an exam you may be given a derivative dydx or f'(x)

    • You can integrate that to find y or f(x) in '+c' form

      • dydxdx=y+c

      • f'(x) dx=f(x)+c

  • If you are also given a point on the graph of y or of y=f(x)

    • you can use this to find the value of c

    • Substitute the values you know into y+c or f(x)+c

      • Then solve for c

  • The extra information doesn't have to be a point on a graph

    • As long as you know the value of f(x) for one value of x

      • you can substitute and solve to find c

Examiner Tips and Tricks

  • An exam question probably won't tell you to 'find the constant of integration'

    • Instead you'll be given the derivative of a function

      • and one value of the function or a point on its graph

    • Be sure to recognise this as a 'constant of integration' question!

Worked Example

The graph of y=f(x) passes through the point (3,4).  The derivative of f(x) is given by f'(x)=3x24x4.

Find f(x).

Integrate f'(x) to find f(x) in '+c' form

f(x)=(3x24x4) dx=3(x2+12+1)4(x1+11+1)4x+c=x32x24x+c


We also know the curve of y=f(x) goes through (3, 4)

That means the function is equal to 4 when x=3

(3)32(3)24(3)+c=4


Solve for c

271812+c=4c3=4c=1


f(x)=x32x24x1


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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.