Solving Equations Graphically (Edexcel IGCSE Further Pure Maths): Revision Note

Exam code: 4PM1

Dan Finlay

Written by: Dan Finlay

Reviewed by: Lucy Kirkham

Updated on

Solving Equations Graphically

How can I solve equations graphically?

  • A graph can be used to to help solve an equation like  f(x)=g(x)

    • Draw the graphs of  y=f(x) and  y=g(x)

    • The solutions are the x-coordinates of the points of intersection

  • This can be used when an equation is difficult or impossible to solve algebraically

    • The solutions found will usually be approximations rather than exact answers

    • The more accurate the graph, the more accurate the approximation

How can I estimate a solution by drawing a line on a graph?

  • An exam question my ask you to estimate a solution by drawing a 'suitable' (or 'appropriate') straight line on a graph

  • Often this will be a horizontal line

    • For example solving f(x)=k for some constant k

      • On a graph of y=f(x), draw the line y=k

      • The solutions are the x-coordinates of any points of intersection

    • Finding roots by seeing where a graph crosses the x-axis is a special case of this

      • The x-axis is the horizontal line with equation  y=0

  • Sometimes it will be the line  y=x

    • Draw this on the graph of y=f(x) to find the solution(s) of f(x)=x

  • But sometimes determining the line to draw will be more challenging

    • For example, 'By drawing an appropriate straight line on the graph of y=3+2e2x, estimate the root of the equation  ln(x3)3=6x'

    • We need to rewrite the equation in the form  g(x)=3+2e2x, where y=g(x) is the equation of a straight line

    • Take the exponential of both sides ('exp cancels log')

      • (x3)3=e6x

    • Take the cube root of both sides

      • x3=e2x

    • Multiply both sides by 2

      • 2x6=2e2x

    • Add 3 to both sides

      • 2x3=3+2e2x

    • That equation is equivalent to  ln(x3)3=6x

      • it will have the same solutions

    • So we need to draw the line  y=2x3  on the graph of  y=3+2e2x

      • the x-coordinates of the points of intersection will give the solution(s) for  2x3=3+2e2x

      • But those are the same as the solution(s) for  ln(x3)3=6x

Examiner Tips and Tricks

  • Be extra careful when drawing graphs on 'estimate solutions by using a graph' questions

    • The accuracy of your answer will depend on the accuracy of your drawing

    • Use a ruler for straight lines

Worked Example

A graph of  y=2(x3+1)1  in the interval  0x6  is shown in the following diagram

Graph of exponential function

By drawing a suitable straight line on the grid, show that the equation  log2(3x1)223x=2  has a root in the interval  0x6, and obtain an estimate for the value of that root.

Be careful here – we cannot just draw the horizontal line y=2
That would only work if we had the graph of  y=log2(3x1)223x

Instead we must work on rearranging the equation
Start by getting the logarithm alone on the left-hand side

log2(3x1)2=23x+2

Use laws of logarithms to bring the power down in front of the logarithm
Then divide both sides of the equation by 2

2log2(3x1)=23x+2log2(3x1)=x3+1

Now take both sides to the power of 2
This will cancel the logarithm on the left-hand side ('exp cancels log')

3x1=2(x3+1)

Finally subtract 1 from both sides

3x2=2(x3+1)1

Now the right-hand side is the function that is graphed on the diagram
So we need to draw the straight line  y=3x2
We can estimate the root by considering the x-coordinate of the point of intersection

Solution graph for question


root:  x1.2

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Dan Finlay

Author: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.

Lucy Kirkham

Reviewer: Lucy Kirkham

Expertise: Content Creator

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.