Properties of Indices (Edexcel IGCSE Further Pure Maths): Revision Note

Exam code: 4PM1

Dan Finlay

Written by: Dan Finlay

Reviewed by: Lucy Kirkham

Updated on

Laws of Indices

What laws of indices do I need to know?

  • In an expression like an 

    • a is known as the base

    • n is known as the index (also called the power or exponent)

  • The index laws you need to know and be able to use are summarised here:

    • am×an=am+n

    • am÷an=amn

      • Be careful!  The two laws above can only be used if the two terms on the left-hand side of the equation have the same base.

    • (am)n=amn

    • (ab)n=anbn

    • a1=a

    • a0=1

    • a1m=am

    • amn=amn=(an)m

    • am=1am

How do I work with laws of indices?

  • Laws of indices work with numerical and algebraic terms

  • These can be used to simplify expressions where terms are multiplied or divided

    • Deal with the number and algebraic parts separately

      • (3x7)×(6x4)=(3×6)×(x7×x4)=18x11

      • 3x76x4=36×x7x4=12x3

      • (3x7)2=(3)2×(x7)2=9x14

How can I solve equations when the unknown is in the index?

  • If two terms with indices are equal and the terms have the same positive base (other than 1) then the indices must be equal

    • If ax=ay then  x=y

      • Not valid if a0 or a=1

  • If the unknown is part of the index then write both sides with the same base number

    • Then ignore the base number, make the indices equal and solve that equation

52x=12552x=532x = 3x = 32

  • In more complicated questions you might have to use negative and fractional indices

    • You may also have to rewrite both sides with the same base number

8x=14(23)x=12223x=223x=2x=23

Worked Example

(a)table row cell blank to the power of blank end cell row blank end tableSimplify  (3x2)(2x3y2)(6x2y).


Multiply out the brackets in the numerator.
Rearrange the numerator so that you are multiplying the numbers together, the x terms together and the y terms together.

3×2×x2×x3×y26x2y

Simplify the numerator.
Multiply the constants together and add the powers of the x terms together.

6x5y26x2y

Divide the constants.
Subtract the power of the x term in the denominator from the x term in the numerator: x52=x3.
Subtract the power of the y term in the denominator from the y term in the numerator: y21=y1.

x3y

(b) Simplify  (54x72x4)13.

Simplify the expression inside the brackets.
Cancel down the constants.
Subtract the power of the x term in the denominator from the x term in the numerator: x74=x3.

(27x3)13

Apply the negative index outside the brackets by 'flipping' the fraction inside the brackets.

(127x3)13

Apply the fractional index outside the brackets to everything inside the brackets.

1132713x3×13

Simplify.

13x 

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Dan Finlay

Author: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.

Lucy Kirkham

Reviewer: Lucy Kirkham

Expertise: Content Creator

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.