Arithmetic Sequences & Series (Edexcel IGCSE Further Pure Maths): Revision Note

Exam code: 4PM1

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Arithmetic Sequences

What is an arithmetic sequence?

  • In an arithmetic sequence, the difference between consecutive terms in the sequence is constant

    • This means a common difference is added to each term to get the next term

  • The first term of the sequence is denoted by a

  • The common difference is denoted by d 

    • For example, 1, 4, 7, 10, … is an arithmetic sequence with the rule ‘start at one and add three to each number’

      • The first term, a, is 1

      • The common difference, d, is 3

  • An arithmetic sequence can be

    • increasing (positive common difference), or

    • decreasing (negative common difference)

  • Terms in an arithmetic sequence can be referred to

    • by the letter u with

    • a subscript corresponding to its place in the sequence

      • e.g.  u1=a is the first term, u9 is the ninth term, un is the nth term, etc.

Arithmetic Series

What is an arithmetic series?

  • When the terms of an arithmetic sequence are added together, that is known as an arithmetic series

    • The terms (1st term, 2nd term, 3rd term, etc.) are exactly the same in the sequence and series

    • But with series we're most interested in what happens when the terms are added together

How do I find a term in an arithmetic series?

  • The nth term formula for an arithmetic sequence is

un=a+(n1)d

  • Where a is the first term, and d is the common difference

  • This is not given on the exam formula sheet, so make sure you know it

  • The formula allows you to find any term in the arithmetic series

    • Enter the values of ar and n and calculate the value of un

  • Sometimes you will be given a term (un) and asked to find a or d

    • Substitute the information you have into the formula and solve the equation

  • Sometimes you will be given two terms and asked to find both a and d

    • Substitute the information into the formula and set up a pair of simultaneous equations

      • Then solve the simultaneous equations

How do I find the sum of an arithmetic series?

  • An arithmetic series is the sum of the terms in an arithmetic sequence

    • For the arithmetic sequence 1, 4, 7, 10, … the arithmetic series is 1 + 4 + 7 + 10 + …

  • Use the following formula to find the sum of the first n terms of an arithmetic series:

Sn=n2[2a+ (n1)d]   

  • a is the first term

  • d is the common difference

  • The formula is given on the exam formula sheet

    • So you don't need to remember it

    • But you do need to know how to use it!

  • A question will often give you the sum of a certain number of terms and ask you to find the value of a or d

    • Substitute the information you have into the formula and solve the equation

Examiner Tips and Tricks

  • The formula for the sum of an arithmetic series is on the exam formula sheet

    • But the nth term formula is not on the formula sheet

  • Simultaneous equations are often needed within arithmetic series questions

    • Make sure you are confident solving them!

Worked Example

The fourth term of an arithmetic series is 10 and the ninth term is 25.  Find the first term and the common difference of the series.

Put the information for the fourth and ninth terms into the nth term formula  un=a+(n1)d

For u4

a+(41)d=10a+3d=10

For u9

a+(91)d=25a+8d=25

That gives us two simultaneous equations in a and d
Subtract the u4 equation from the u9 equation to eliminate a

5d=15d=3

Substitute that value into the first equation to find a

a+3(3)=10a+9=10a=1

That is all the information we need to answer the question

a=1,   d=3

Worked Example

The sum of the first 10 terms of an arithmetic series is 630.

The first term is 18. 

a) Find the common difference, d, of the series.

Use the arithmetic series formula  Sn=n2[2a+(n1)d]

Here  n=10S10=630  and  a=18

Substitute in and solve for d

630=102[2(18)+(101)d]630=5[36+9d]630=180+45d450=45dd=450÷45

d=10

The sum of the first 10 terms of another arithmetic series is also 630.

The common difference is 11. 

b) Find the first term, a, of the series.

Here  n=10S10=630  and  d=11

630=102[2a+(101)11]630=5[2a+99]630=10a+495135=10aa=135÷10

a=13.5

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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.