Graphs of Functions (Edexcel IGCSE Maths B): Flashcards

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  • What is a quadratic graph's shape called, and what is its turning point called?

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  • What is a quadratic graph's shape called, and what is its turning point called?

    The shape is a parabola, a smooth curve with a vertical line of symmetry.

    Its turning point is called the vertex, which is a minimum on a u-shape and a maximum on an n-shape.

  • True or False?

    A quadratic with a negative number in front of x^{2} gives a u-shaped curve.

    False.

    A negative number in front of x^{2} gives an n-shaped curve, which has a maximum point.

    It is a positive number in front of x^{2} that gives the u-shape, with a minimum point.

  • How many times can a quadratic graph cross each axis?

    It crosses the y-axis exactly once, whatever the quadratic is.

    It crosses the x-axis twice, once, or not at all, and those crossing points are the roots.

  • Fill in the coordinates of the vertex of this curve.

    y = a \left(x - p\right)^{2} + q \text{ has vertex } \left(\_\_\_\_\_\_ , \_\_\_\_\_\_\right)

    The completed statement is:

    y = a \left(x - p\right)^{2} + q \text{ has vertex } \left(p , q\right)

    Watch the sign change on the x-coordinate: the curve y = \left(x + 3\right)^{2} + 2 has its vertex at \left(- 3 , 2\right).

  • True or False?

    The curves y = \left(x - 3\right)^{2} + 2 and y = 5 \left(x - 3\right)^{2} + 2 have the same vertex.

    True.

    The number in front of the bracket changes the shape of the curve, not the position of its vertex.

    Both have their vertex at \left(3 , 2\right), and both are u-shaped because that number is positive.

  • A quadratic graph has roots at x = 2 and x = 3 and passes through \left(0 , 24\right). How do you find its equation?

    Use the form y = a \left(x - x_{1}\right) \left(x - x_{2}\right) to write y = a \left(x - 2\right) \left(x - 3\right), then substitute the other point into it.

    That gives 24 = 6 a, so a = 4 and the equation is y = 4 \left(x - 2\right) \left(x - 3\right).

  • A quadratic graph has vertex \left(9 , - 16\right) and passes through \left(2 , 82\right). How do you find its equation?

    Use the form y = a \left(x - p\right)^{2} + q to write y = a \left(x - 9\right)^{2} - 16, then substitute the other point into it.

    That gives 82 = 49 a - 16, so a = 2 and the equation is y = 2 \left(x - 9\right)^{2} - 16.

  • When is the vertex alone enough to find a quadratic's equation?

    Only when you already know that a = 1, so the equation is simply y = \left(x - p\right)^{2} + q.

    Otherwise a second point on the curve is needed as well, to pin down the value of a.

  • Define a cubic.

    A cubic is a function of the form a x^{3} + b x^{2} + c x + d, which is a polynomial of degree 3.

    The constants b, c and d may each be zero, but a cannot be zero.

  • True or False?

    A cubic whose x^{3} coefficient is negative starts in the bottom left and ends in the top right.

    False.

    That describes a positive cubic, one where the coefficient of x^{3} is greater than zero.

    A negative cubic runs the other way, starting in the top left and ending in the bottom right.

  • How many turning points can a cubic graph have?

    Up to two, one maximum and one minimum.

    Some cubics have none at all: y = x^{3} and y = - x^{3} have no maximum or minimum, and each meets the x-axis only once, at x = 0.

  • Why does a cubic need to be in factorised form before you can sketch it?

    Because the factors give you the roots directly, and the roots fix where the curve meets the x-axis.

    Simple cubics factorise at once, such as x^{3} - 4 x = x \left(x - 2\right) \left(x + 2\right), while harder ones need the factor theorem and algebraic division.

  • What are the roots of y = \left(x - 2\right) \left(x - 3\right) \left(x + 5\right)?

    The roots are x = 2, x = 3 and x = - 5.

    A cubic written \left(x - p\right) \left(x - q\right) \left(x - r\right) has roots at p, q and r, so each one is read off by changing the sign inside its own bracket.

  • True or False?

    The graph of y = \left(x - 2\right)^{2} \left(x + 1\right) crosses the x-axis at x = 2.

    False.

    A repeated root makes the graph touch the x-axis and turn back, rather than cross it, so at x = 2 it touches.

    It does cross at x = - 1, where the root is not repeated.

  • A positive cubic touches the x-axis at x = 3 and crosses it at x = \frac{1}{2}. Where must its two turning points lie?

    One is a minimum at x = 3 itself, because the curve touches the axis there and turns back upwards.

    The other is a maximum somewhere between the two roots, so between x = \frac{1}{2} and x = 3.

  • What form does a reciprocal graph take?

    A reciprocal graph has the form y = \frac{a}{x} or y = \frac{a}{x^{2}}.

    The two simplest are y = \frac{1}{x} and y = \frac{1}{x^{2}}, where a = 1.

  • True or False?

    The graph of y = \frac{3}{x} never crosses either axis.

    True.

    It has no roots and no y-intercept, so it meets neither axis anywhere.

    Instead it approaches both axes without ever reaching them, which is what its two asymptotes describe.

  • Define an asymptote.

    An asymptote is a line that a curve gets closer and closer to but never touches.

    Asymptotes may be horizontal or vertical lines.

  • Why does y = \frac{1}{x} have a vertical asymptote at x = 0?

    Because x = 0 would mean dividing by zero, which has no value, so the curve can never reach that line.

    The horizontal asymptote y = 0 arises the other way round: as x grows large in either direction, \frac{1}{x} shrinks towards zero without ever getting there.

  • Why do both branches of y = \frac{1}{x^{2}} lie above the x-axis?

    Because x^{2} is positive for every non-zero value of x, whether x itself is positive or negative.

    That is what makes it differ from y = \frac{1}{x}, whose two branches sit on opposite sides of the axis.

  • In y = \frac{a}{x}, what do the sign and the size of a each change?

    The sign of a decides where the two branches sit.

    A positive a puts them in the top-right and bottom-left, and a negative a puts them in the top-left and bottom-right.

    The size of a decides how steep they are, and the closer a is to zero the more L-shaped they become.

  • Fill in the equations of the two asymptotes of y = \frac{5}{x} + 6.

    \text{horizontal: } y = \_\_\_\_\_\_

    \text{vertical: } x = \_\_\_\_\_\_

    The completed equations are:

    \text{horizontal: } y = 6

    \text{vertical: } x = 0

    Adding 6 shifts the whole curve up by 6 and takes the horizontal asymptote with it, while the vertical asymptote stays on the y-axis.

  • True or False?

    You should always use a ruler when plotting the graph of a function.

    False.

    You should only use a ruler if a graph is linear (and for drawing the axes if they are not given).

    For curves, draw a single smooth freehand curve.

  • How would you find the y-intercept of a graph using its equation?

    To find the y-intercept of a graph, you would substitute x equals 0 into the equation.

  • True or False?

    The solutions to x cubed minus 4 x equals 0 are the value(s) where the graph of y equals x cubed minus 4 x crosses the y-axis.

    False.

    The solutions to x cubed minus 4 x equals 0 are not the value(s) where the graph of y equals x cubed minus 4 x crosses the y-axis.

    x cubed minus 4 x equals 0 when y equals 0 which is the x-axis. Therefore the solutions are the values where the graph crosses the x-axis.

  • The solutions of x cubed plus x squared minus 3 equals x minus 2 are the x values of the intersections between y equals x cubed plus x squared minus 3 and which other graph?

    The solutions of x cubed plus x squared minus 3 equals x minus 2 are the x values of the intersections between y equals x cubed plus x squared minus 3 and bold italic y bold equals bold italic x bold minus bold 2.

  • True or False?

    The x values of the intersections of the two graphs y equals x plus 1 and y equals x squared plus 5 x plus 4 are the solutions of x squared plus 4 x plus 3 equals 0.

    True.

    The x values of the intersections of the two graphs y equals x plus 1 and y equals x squared plus 5 x plus 4 are the solutions of x squared plus 4 x plus 3 equals 0.

    Set the equations equal to each other and rearrange: x squared plus 5 x plus 4 equals x plus 1.

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