Representing Inequalities as Regions (Edexcel IGCSE Maths B): Revision Note

Exam code: 4MB1

Finding regions using inequalities

What are 2D inequalities?

  • A 2D inequality involves two variables

    • E.g. y<x or x+y8

  • The solution to a 2D inequality is a region in the xy plane

  • The solution to a 1D inequality can also be represented as a region in the xy plane

    • E.g. y2 represents the region of points that lie on or above the line y=2

How do we draw inequalities on a graph?

  • A set of 2D inequalities can be shown graphically using straight lines and shaded regions

  • To draw the correct lines:

    • Replace the inequality sign with “=” and draw that line

      • Use a solid line for ≤ or ≥ (to indicate the line is included)

      • Use dotted line for < or > (to indicate the line is not included)

  • To decide which side of the line is the wanted side:

    • if "y ≤ ..." or "y < ..." then the wanted region is below the line

    • if "y ≥ ..." or "y > ..." then the wanted region is above the line

    • If you are unsure

      • substitute the coordinates from a point on one side of the line into the inequality

      • determine whether or not the inequality holds true on that side

    • For vertical lines:

      • the wanted region for x<k is to the left of x=k

      • the wanted region for x>k is to the right of x=k

  • To do the shading:

    • Shade the unwanted sides of each line (unless the question says otherwise)

      • You are shading away any parts you don't want

      • This will leave behind a clear region that is the wanted region (rather than trying to look for the wanted region under multiple shades)

      • Label the wanted region R (unless the question says otherwise)

Worked Example

Show, graphically, the region that is satisfied by all three inequalities below:

3x+2y12       y<2x       x<3

Label this region R.

Answer:

First draw the three straight lines: 3x+2y=12y=2x and x=3

Use your knowledge of Straight Line Graphs, y=mx+c
You may wish to rearrange 3x+2y=12 to the form y=mx+c first

2y=3x+12y=32x+6

The line 3x+2y12 is a solid line because of the "≥"

The lines y<2x and x<3 are dotted lines because of the "<"

Graphing showing a solid line for the equation 3x+2y=12 and dotted lines for the equations x=3 and y=2x.

Now we need to shade the unwanted regions

For 3x+2y12 (or y32x+6), the unwanted region is below the line
We can check this with the point (0, 0)

"3(0)+2(0)12" is false therefore (0, 0) does lie in the unwanted region for 3x+2y12

For y<2x, the unwanted region is above the line
Check with another point, for example (1, 0)

"0<2(1)" is true, so (1, 0) lies in the wanted (i.e. unshaded) region for y<2x

For x<3, shade the unwanted region to the right of x=3
If unsure, check with a point

Finally, don't forget to label the region R

V90dxvma_2-19-1-2-graphing-inequalities

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Jamie Wood

Author: Jamie Wood

Expertise: Curriculum Expert

Jamie graduated in 2014 from the University of Bristol with a degree in Electronic and Communications Engineering. He has worked as a teacher for 8 years, in secondary schools and in further education; teaching GCSE and A Level. He is passionate about helping students fulfil their potential through easy-to-use resources and high-quality questions and solutions.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.