Uses of Prime Factor Decomposition (Edexcel IGCSE Maths B): Revision Note

Exam code: 4MB1

Uses of prime factor decomposition

How can I use PFD to identify a square or cube number?

  • If all the indices in the prime factor decomposition of a number are even, then that number is a square number

    • E.g. The prime factor decomposition of 7056 is 24 × 32 × 72

    • All powers are even so it must be a square number

      • It can be written as (22 × 3 × 7)2

  • If all the indices in the prime factor decomposition of a number are multiples of 3, then that number is a cube number

    • E.g. The prime factor decomposition of 1728000 is 29 × 33 × 53

    • All powers are multiples of 3 so it must be a cube number

      • It can be written as (23 × 3 × 5)3

How can I use PFD to find the square root of a square number?

  • Write the number in its prime factor decomposition

    • All the indices should be even if it is a square number

  • For example, to find the square root of 144 = 24 × 32

    • Halve all of the indices

      • 22 × 3

      • So 24×32=22×3

  • This is the prime factor decomposition of the square root of the number

    • To find it as an integer, multiply the prime factors together

    • 22 × 3 = 12, so the square root of 144 is 12

How can I use PFD to find the exact square root of a number?

  • If the number is not a square number, its exact square root can still be found using its prime factor decomposition

  • Write the number in its prime factor decomposition

    • 1440=25×32×5

  • Rewrite the prime factor decomposition with as many even indices as you can

    • E.g. 23 = 22 × 2, or 57 = 56 × 5

    • 1440=24×2×32×5

  • Collect the terms with even powers together

    • 1440=24×32×2×5

  • Square root both sides

    • 1440=24×32×2×5

  • Using the rule ab=ab, apply the square root to the terms with the even indices separately to the terms with odd indices

    • 1440=24×32×2×5

  • Simplify to find your answer, remembering that a2b2=ab

    • 1440=22×3×10

    • 1440=1210

    • 1210 is the exact square root of 1440

Worked Example

N=23×32×57 and AN=B where Ais an integer and B is a non-zero square number.

Find the smallest value of A.

Answer:

Substitute N = 23 × 32 × 57 into the formula AN = B

A(23 × 32 × 57 ) = B

To be a square number, the prime factors of AN must all have even powers

Consider the prime factors A needs to have to make all the values on the left hand side have even powers

(2 × 5) (23 × 32 × 57) = B

24 × 32 × 58 B

So A, when written as a product of its prime factors, is 2 × 5

Make sure you write A as an integer value in the answer

A = 10

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