Deciding the Quadratic Factorisation Method (Edexcel IGCSE Maths B): Revision Note

Exam code: 4MB1

Quadratics factorising methods

How do I know if an expression factorises?

  • The easiest way to check if ax2 + bx + c factorises is to check if you can find a pair of integers which:

    • Multiply to give ac

    • Sum to give b

    • If you can find integers to satisfy this, the expression must factorise

  • There are some alternate methods to check:

    • Method 1: Use a calculator to solve the quadratic expression equal to 0

      • Only some calculators have this functionality

      • If the solutions are integers or fractions (without square roots), then the quadratic expression will factorise

    • Method 2: Find the value under the square root in the quadratic formula

      • b2 – 4ac

      • If this number is a square number, then the quadratic expression will factorise

Which factorisation method should I use for a quadratic expression?

  • Does it have 2 terms only?

    • Yes, like x27x

      • Factorise out the highest common factor, x

      • x(x7)

    • Yes, like x29

      • Use the "difference of two squares" to factorise

      • (x+3)(x3)

Does it have 3 terms?

  • Yes, starting with x2 like x23x10

    • Use "factorising simple quadratics" by finding two numbers that add to -3 and multiply to -10

    • (x+2)(x5)

  • Yes, starting with ax2 like 3x2+15x+18

    • Check to see if the 3 in front of x2 is a common factor for all three terms (which it is in this case), then factorise it out of all three terms

    • 3(x2+5x+6)

    • The quadratic expression inside the brackets is now x2 +... , which factorises more easily

    • 3(x+2)(x+3)

  • Yes, starting with ax2 like 3x25x2

    • The 3 in front of x2 is not a common factor for all three term

    • Use "factorising harder quadratics", for example factorising by grouping or factorising using a grid

    • (3x+1)(x2)

What other expressions should I be able to factorise?

  • You may have a cubed term like x33x210x

    • Check to see if x is a common factor for all three terms (which it is in this case), so factorise it out of all three terms

    • x(x23x10)

    • The remaining quadratic can then be factorised

    • x(x+2)(x5)

  • It can also be useful to spot a quadratic in the form x2+2ax+a2

    • This factorises to (x+a)2

    • E.g. x2+6x+9 = (x+3)2

Examiner Tips and Tricks

A common mistake in the exam is to divide expressions by numbers, e.g. 2x2+4x+2 becomes x2+2x+1 (which is incorrect).

This can only be done with equations.

e.g. 2x2+4x+2=0 becomes x2+2x+1=0 (dividing "both sides" by 2).

Worked Example

Factorise  8x2+100x48.

Answer:

Spot the common factor of -4 and factorise it out

8x2+100x48=4(2x225x+12)

Check to see if the quadratic in the bracket will factorise using b24ac

(25)2(4×2×12)=62596=529

529 is a square number (232) so the expression will factorise

Factorise 2x225x+12

We require a pair of numbers which multiply to ac, and sum to b

a×c=2×12=24

The only numbers which multiply to 24 and sum to -25 are

-24 and -1

Split the 25x term into 24xx

2x224xx+12

Group and factorise the first two terms, using 2x as the common factor
Group and factorise the last two terms using 1 as the common factor

2x(x12)1(x12)

These factorised terms now have a common factor of (x12), so this can be factorised out

(2x1)(x12)

Recall that -4 was factorised out at the start

8x2+100x48=4(2x225x+12)=4(2x1)(x12)

4(2x1)(x12)

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