Proof by Induction (Edexcel International A Level (IAL) Further Maths: Further Pure 1): Exam Questions

Exam code: YFM01

2 hours13 questions
1a
5 marks

A sequence of positive numbers is defined by

     u1=5un+1=3un+2,  n≥1

Prove by induction that, for n∈ℤ+ ,

un=2×(3)n−1

1b
6 marks

Prove by induction that, for n∈ℤ+,

∑r=1n4r3r=3−(3+2n)3n

2a
4 marks

Prove by induction that for n∈ℤ+

(1r02)n=(1(2n−1)r02n)

where r is a constant.

2b
3 marks

M=(4005) N=(1−202)4

The transformation represented by matrix M followed by the transformation represented by matrix N is represented by the matrix B

(i) Determine N in the form (abcd) where a, b, c and d are integers.

[1]

(ii) Determine B

[2]

2c
2 marks

Hexagon S is transformed onto hexagon S' by matrix B

Given that the area of S' is 720 square units, determine the area of S

3
6 marks

Prove by induction that for n∈ℤ+

f(n)=7n−1+82n+1

is divisible by 57

4a
5 marks

Prove by induction that for n∈ℤ+

(5−141)n=3n−1(2n+3−n4n3−2n)

4b
5 marks

Prove by induction that for n∈ℤ+

f(n)=82n+1+62n−1

is divisible by 7

5
5 marks

Prove, by induction, that for n∈ℤ, n⩾2

4n+6n−10

is divisible by 18

6
6 marks

Prove by induction that for all positive integers n

∑r=1nlog(2r−1)=log ((2n)!2n n!)

7a
5 marks

A sequence of numbers is defined by

u1=3

un+1=2un−2n+1    n⩾1

Prove by induction that, for n∈ℕ

un=5×2n−1−n×2n

7b
5 marks

Prove by induction that, for n∈ℕ

f(n)=5n+2−4n−9

is divisible by 16

8a
5 marks

Prove by induction that, for n∈ℕ

∑r=1nr3=14n2(n+1)2

8b
4 marks

Using the standard summation formulae, show that

∑r=1nr(r+1)(r−1)=14n(n+A)(n+B)(n+C)

where A, B and C are constants to be determined.

8c
1 mark

Determine the value of n for which

3∑r=1nr(r+1)(r−1)=17∑r=n2nr2

9a
5 marks

A sequence of numbers is defined by

u1=0    u2=−6

un+2=5un+1−6un    n≥1

Prove by induction that, for n∈ℤ+

un=3×2n−2×3n

9b
5 marks

Prove by induction that, for all positive integers n,

f(n)=33n−2+24n−1

is divisible by 11

10a
5 marks

Prove by induction that for n∈ℕ

∑r=1nr2=n6(n+1)(2n+1)

10b
4 marks

Hence show that

∑r=1n(r2+2)=n6(an2+bn+c)

where a, b and c are integers to be found.

10c
2 marks

Using your answers to part (b), find the value of

∑r=1025(r2+2)

11
6 marks

Prove by induction that 4n+2+52n+1 is divisible by 21 for all positive integers n.

12a
6 marks

A sequence of numbers u1, u2, u3,....is defined by

un+1=13(2un−1),    u1=1

Prove by induction that, for n∈ℤ+

un=3(23)n−1

12b
6 marks

f(n)=2n+2+32n+1

Prove by induction that, for n∈ℤ+ , f(n) is a multiple of 7.

13a
6 marks

(i) Prove by induction that, for n∈ℤ+

∑r=1n2r2−1r2(r+1)2=n2(n+1)2

[6]

(ii) Prove by induction that, for n∈ℤ+

f(n)=12n+2×5n−1

is divisible by 7.

[6]

13b
6 marks

Prove by induction that, for n∈ℤ+

f(n)=12n+2×5n−1

is divisible by 7.