Reverse Percentages (Edexcel GCSE Maths)

Revision Note

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

Updated on

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Reverse Percentages

What is a reverse percentage?

  • A reverse percentage question is one where we are given the value after a percentage increase or decrease and asked to find the value before the change

How do I solve reverse percentage questions?

  • You should think about the before quantity

    • even though it is not given in the question

  • Find the percentage change as a multiplier, p

    • This is the decimal equivalent of a percentage change

      • A percentage increase of 4% means p = 1 + 0.04 = 1.04

      • A percentage decrease of 5% means p = 1 - 0.05 = 0.95

  • Use before × p = after to write an equation

    • Get the order right: the percentage change happens to the "before", not to the "after"

  • Rearrange the equation to make the "before" quantity the subject

    • Divide the "after" quantity by the multiplier, p

What is a common mistake with reverse percentage questions?

  • Here is an example: a price of a mobile increases by 10% to £220

    • To find the price before, you do not apply a 10% decrease to £220

      • That would give 220 cross times 0.9 = £198 (incorrect)

    • Use before × p = after instead

      • before cross times 1.1 = 220

      • before = fraction numerator 220 over denominator 1.1 end fraction = £200 (correct)

  • You cannot turn a percentage increase into a decrease with reverse percentage questions

Examiner Tips and Tricks

  • To spot a reverse percentage question, see if you are being asked to find a quantity in the past

    • Find the old / original / before amount ...

Worked Example

Jennie has been working for a company for the last ten years.

She receives a pay rise of 5%.

Her new salary is £31 500 per year.

Find her salary before the pay rise.

Use "before" × p = "after" to write an equation

The "before" amount is unknown and the "after" amount is 31 500

"before" × 1.05 = 31 500

Find the multiplier, p (by writing 5% as a decimal and adding it to 1)

p = 1 + 0.05 = 1.05

Find the value of "before" (by dividing both sides by 1.05)

"before" = fraction numerator 31 space 500 over denominator 1.05 end fraction = 30 000

She was paid £30 000 before the pay rise

Jennie was paid £30 000 per year before the pay rise

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.