Speed-Time Graphs (Cambridge (CIE) IGCSE Co-ordinated Sciences (Double Award): Physics): Revision Note

Exam code: 0654 & 0973

Speed-time graphs

  • A speed-time graph is used to describe the speed of an object and calculate its acceleration

Constant acceleration on a speed-time graph

  • If an object is moving at a constant acceleration, the speed-time graph will be a straight line

    • If the constant acceleration is zero, the line will be horizontal

    • If the constant acceleration is non-zero, the line will have a gradient

  • If an object has an acceleration of zero, the object is travelling at a constant velocity

    • Its velocity is not changing over time

    • If the constant speed is zero, then the object is stationary

Motion on a speed-time graph

1-2-4-speed-time-graph-2-cie-igcse-23-rn

This image shows how to interpret the slope of a speed-time graph

 

  • The gradient of a speed-time graph represents the object's acceleration

    • A steeper slope, or a higher gradient, represents a greater acceleration

    • A shallower slope, or a lower gradient, represents a slower acceleration

  • If the gradient is positive, the line slopes upward

    • A positive gradient represents an increasing speed, or acceleration

  • If the gradient is negative, the line slopes downward

    • A negative gradient represents a decreasing speed, or deceleration

Speeding up and slowing down on a speed-time graph

1-2-4-speed-time-graph-cie-igcse-23-rn

Both of these objects are moving at a constant acceleration, because the lines are straight. The positive gradient represents an increasing speed or positive acceleration. The negative gradient represents a decreasing speed or negative acceleration.

Examiner Tips and Tricks

For CIE IGCSE Physics, you may be asked plot a graph of your own, or to interpret information given to you in a graph. You can read more about graph skills in the article Graph skills in GCSE Physics

Calculating distance from speed-time graphs

  • Speed-time graphs can also be used to determine the distance travelled by an object

The area under a speed-time graph

  • The area under a speed-time graph represents the distance travelled

area-under-speed-time-graph

The area under a speed-time graph represents the distance travelled

 

  • If the area of a section of the speed-time graph forms a triangle, the area can be calculated using:

 AT = 12bh

  • If the area of a section of the speed-time graph forms a rectangle, the area can be determined using:

 AR = bh

  • Where:

    • AT = area of a triangle

    • AR = area of a rectangle

    • b = base

    • h = height

  • The total distance travelled can be determined by finding the total area under the speed-time graph

  • The distance travelled for part of the journey can be determined by finding the area under the graph for a specific time interval

Area under a speed-time graph split into sections

Determining Distance on a V-T graph

The area under a speed-time graph can split into triangular and rectangular sections

Worked Example

The speed-time graph below shows a car journey that lasts for 160 seconds.

1-2-4-worked-eg-1-cie-igcse-23-rn

Calculate the total distance travelled by the car on this journey.

Answer:

Step 1: Recall that the area under a velocity-time graph represents the distance travelled

  • In order to calculate the total distance travelled, the total area underneath the line must be determined

Step 2: Identify each enclosed area

  • In this example, there are five enclosed areas under the line

  • These can be labelled as areas 1, 2, 3, 4 and 5, as shown in the image below:

1-2-4-worked-eg-2-cie-igcse-23-rn

Step 3: Calculate the area of each enclosed shape under the line

  • Area 1 = area of a triangle

A1 = 12bh

A1 = 12 × 40 × 17.5

A1 = 350 m

  • Area 2 = area of a rectangle

A2 = bh

A2 = 30 × 17.5

A2 = 525 m

  • Area 3 = area of a triangle

A3 = 12bh

A3 = 12 × 20 × 7.5

A3 = 75 m

  • Area 4 = area of a rectangle

A4 = bh

A4 = 20 × 17.5

A4 = 350 m

  • Area 5 = area of a triangle

A5 = 12bh

A5 = 12 × 70 × 25

A5 = 875 m

Step 4: Calculate the total distance travelled by finding the total area under the line

  • Add up each of the five areas enclosed:

total distance = A1 + A2 + A3 + A4 + A5

total distance = 350 + 525 + 75 + 350 + 875

total distance = 2175 m

Examiner Tips and Tricks

Some areas will need to be split into a triangle and a rectangle to determine the area for a specific time interval, like areas 3 & 4 in the worked example above.

If you are asked to find the distance travelled for a specific time interval, then you just need to find the area of the section above that time interval.

For example, the distance travelled between 70 s and 90 s is the sum of Area 3 + Area 4

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