DNA & Gene Expression (Edexcel International A Level (IAL) Biology): Exam Questions

Exam code: YBI11

56 mins6 questions
1
8 marks

This drug is a double-stranded RNA molecule.

(i) The diagram shows part of the base sequence on one of the RNA strands. Complete the diagram to show the base sequence on the other RNA strand.

(2)

q6b-unit-1-oct-2021-edexcel-ial-biology

(ii) Describe the bonding in this double-stranded RNA molecule.

(3)

(iii) In AHP, toxic porphyrin molecules build up.

The synthesis of the haem component of haemoglobin involves several steps.

Each step in the synthesis of haem is catalysed by a different enzyme.

This drug works by interfering with the mRNA copies from the gene coding for one of these enzymes.

Explain how the action of this drug helps patients with AHP.

(3)

2a
3 marks

The polynucleotide DNA is composed of mononucleotides linked together.

Two polynucleotides form a DNA molecule.

The diagram shows part of a DNA molecule.

q4a-unit-1-oct-2020-edexcel-ial-biology

(i)Draw a circle around one mononucleotide that includes the base labelled R.

(1)

(ii) Which row of the table identifies the bonds labelled S, T and U?

(1)

 

S

T

U

A

hydrogen

phosphodiester

covalent

B

hydrogen

covalent

phosphodiester

C

phosphodiester

hydrogen

covalent

D

phosphodiester

covalent

hydrogen

(iii) The base labelled P is adenine.

Which is the base labelled Q?

(1)

☐

A

cytosine

☐

B

guanine

☐

C

thymine

☐

D

uracil

2b
6 marks

Meselson and Stahl carried out experiments that provided evidence for the semi‐conservative replication of DNA.

Heavy nitrogen (N15) and light nitrogen (N14) were used in these experiments.

The flow chart summarises part of one experiment performed by Meselson and Stahl.

q4b-unit-1-oct-2020-edexcel-ial-biology

After each stage, a sample of DNA was taken from the bacteria and the DNA molecules separated using a density gradient in a tube.

The heavier DNA molecules form bands lower down the gradient than the lighter DNA molecules.

The height of each band is proportional to the percentage of DNA molecules in the sample.

(i) Complete the diagram to show the results of this experiment.

Use the dotted lines to help you to position the bands on the diagram.

The first one has been done for you.

(5)

q4bi-unit-1-oct-2020-edexcel-ial-biology

(ii) The experiments of Meselson and Stahl disproved the dispersive theory of DNA replication.

The diagram shows the expected results if the dispersive theory was correct.

q4bii-unit-1-oct-2020-edexcel-ial-biology

Which diagram would show the bands of DNA molecules on the density gradient at stage 2, if the dispersive theory was correct?

(1)

q4bii-2-unit-1-oct-2020-edexcel-ial-biology
3a
3 marks

An average‐sized human chromosome contains a DNA molecule with about 300 million nucleotides, arranged in pairs.

Describe the structure of a nucleotide pair.

3b
2 marks

Before a cell can divide, the DNA molecule has to replicate. This takes place in the S phase of the cell cycle.

Human DNA replicates at a rate of 50 nucleotides per second.

Calculate how long it would take, to the nearest hour, for 150 million nucleotides to replicate.

Assume that replication starts at one end of the molecule and continues to the other end.

3c
5 marks

In human cells, replication of DNA occurs at several sites along the molecule.

These sites are called replication bubbles.

The image shows a replication bubble.

edexcel-ial-unit-1-jan-2022-q3c

The diagram shows how the DNA is replicated in one replication bubble.

q3c-2-unit-1-january-2022-edexcel-ial-biology

(i) Explain the role of DNA polymerase in a replication bubble.

Use the information in the diagram and your own knowledge to support your answer.

(2)

(ii) In human cells, S phase lasts about 10 hours.

Suggest why each DNA molecule is replicated using many replication bubbles

(3)

4a
6 marks

A gene contains the genetic code for the sequence of amino acids in a polypeptide chain.

The table shows the genetic codes found in DNA.

Genetic code

Amino acid

Genetic code

Amino acid

Genetic code

Amino acid

Genetic code

Amino acid

AAA AAG

Lysine

CAA CAG

Glutamine

GAA GAG

Glutamic acid

TAC TAT

Tyrosine

AAC AAT

Asparagine

CAT CAC

Histidine

GAC GAT

Aspartate

TCA TCC TCG TCT

Serine

ACA ACC ACG ACT

Threonine

CCA CCC CCG CCT

Proline

GCA GCC GCG GCT

Alanine

TGG

Tryptophan

AGA AGG

Arginine

CGA CGC CGG CGT

Arginine

GGA GGC GGG GGT

Glycine

TGC TGT

Cysteine

AGC AGT

Serine

CTA CTC CTG CTT

Leucine

GTA GTC GTG GTT

Valine

TTA TTG

Leucine

ATA ATC ATT

Isoleucine

 

TTC TTT

Phenylalanine

ATG

Methionine

 

The genetic codes TAA, TAG and TGA are stop codons, that do not code for amino acids.

Explain the nature of the genetic code.

Use information in the table to support your answer.

4b
6 marks

The diagram shows the sequence of nucleotide bases in part of a DNA template (antisense) strand.

Number

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

Base

A

T

G

G

C

T

T

G

C

C

C

G

A

T

C

C

T

A

(i) Give the sequence of amino acids that is coded for by these bases.

(1)

(ii) Explain the possible effects on a protein if there is a substitution mutation in the 9th base in this DNA strand.

Use information in the table to support your answer.

(5)

5a
3 marks

(i) Name the bonds present between the bases of a DNA molecule.

[1]

(ii) Describe the bonds named in (i).

[2]

5b
1 mark

State one structural difference between DNA and RNA.

5c
2 marks

DNA is replicated in cells during a process known as semi-conservative replication.

Describe the role of DNA polymerase in semi-conservative replication.

5d
3 marks

DNA can also be broken down by enzymes.

DNase I is an enzyme that catalyses the hydrolysis of bonds in DNA. An investigation was carried out to determine the effect of pH on the activity of DNase I.

The results are shown in the table below.

pH

Initial rate of reaction (arbitrary units)

4

0.3

5

1.1

6

3.8

7

6.2

8

7.4

9

4.1

10

0.8

Describe and explain the effect of pH on the initial rate of DNase I activity.

5e
1 mark

In another experiment, bacteria were grown in a medium containing heavy nitrogen (15N). The bacteria were then transferred to a medium containing only light nitrogen (14N) and allowed to undergo two rounds of DNA replication.

Which of the following correctly describes the DNA molecules produced after two rounds of replication?

  • All DNA molecules contain one 15N strand and one 14N strand

  • Half the DNA molecules contain one 15N strand and one 14N strand, and half contain only 14N

  • All DNA molecules contain only 14N

  • Half the DNA molecules contain only 15N and half contain only 14N

6a
3 marks

Both DNA and RNA are polynucleotides.

The table shows how the components of polynucleotides can be represented.

q1a-unit-1-january-2021-edexcel-ial-biology

(i) Which diagram shows a mononucleotide?

(1)

q1ai-unit-1-january-2021-edexcel-ial-biology

(ii) Which diagram shows two components joined by a phosphodiester bond?

q1aii-unit-1-january-2021-edexcel-ial-biology

(1)

(iii) Which diagram shows complementary base pairing?

(1)

q1aiii
6b
4 marks

The diagram shows a sequence of bases in a DNA template (antisense) strand.

A

T

T

G

G

C

G

A

G

A

A

C

(i) The table shows some statements about the new complementary DNA strand and the mRNA strand synthesised using this sequence of bases.

For each statement, put one cross × in the appropriate box, in each row, to show the correct statement about these strands.

(3)

Statement

Both the new complementary DNA strand and the mRNA strand

Only the new complementary DNA strand

Only the mRNA strand

Neither strand

The number of guanines will be the same as in the template strand

 

 

 

 

The number of thymines will be the same as the number of adenines in the template strand

 

 

 

 

There will be no adenine present

 

 

 

 

(ii) Name the process that synthesises a mRNA strand using the DNA template strand.

(1)