Transformations of Graphs (Cambridge (CIE) IGCSE International Maths: Extended): Exam Questions

Exam code: 0607

29 mins14 questions
1
Sme Calculator
2 marks

Find the vector that translates the point (1, 5) to the point (1, 7).

2
Sme Calculator
1 mark

F is the point (5, 7).
The vector that maps F onto the point G is (1   3).

Find the coordinates of G.

(...................... , ......................)

3
Sme Calculator
2 marks

P is the point (3, 6).
Q is the point (0, 2).

Find the translation vector that maps the point P onto the point Q.

4
Sme Calculator
1 mark

(7, 13) is a point on the graph y=f(x).

Write down the coordinates of a point which must be on the graph of y=f(x)2.

5
Sme Calculator
1 mark
Graph of a parabola opening upwards, labelled "y = f(x)", crossing the y-axis at 0, and an identical parabola below it with the same point crossing the y axis at -5, on an xy coordinate plane.

A curve with equation  y = f(x)  is translated so that the point at (0, 0) is mapped to the point (0, 5).

Find the equation of the translated curve.

6
Sme Calculator
2 marks

The diagram shows a sketch of the graph of  y=j(x).

Graph of the function j(x) with x-axis from -10 to 10 and y-axis from -10 to 10, showing a curve with a minimum and a maximum.

On the same diagram, sketch the graph of  y=j(x+2).

1
Sme Calculator
2 marks

The graph with equation  y=x2+2 undergoes a translation of 3 units to the right.

Show that the equation of the translated graph simplifies to y=x26x+11.

2
Sme Calculator
2 marks

A curve with equation y = f(x) is translated so that the point at (0, 0) is mapped onto the point (4, 0).

(i) Find the translation vector.

[1]

(ii) Find the equation of the translated curve.

[1]

3
Sme Calculator
2 marks
Graph of a quadratic function y=f(x) with vertex at (3, -4). Axes are labelled x and y.

The diagram shows part of the curve with equation y=f(x).
The coordinates of the minimum point of this curve are (3,4)

Write down the coordinates of the minimum point of each of the curves below:

(i) y=f(x)+3

[1]

(ii) y=f(x+2)

[1]

4
Sme Calculator
3 marks

The graph with equation  y=x24x undergoes a translation of one unit in the negative x direction and five units in the positive y direction.

Find the equation of the translated graph.
Give your answer in the form y=ax2+bx+c.

1
Sme Calculator
2 marks

The graph of y=cos(x35) for 0°x360° crosses the x-axis at two points.

Write down the coordinates of the points where this occurs.

2a
Sme Calculator
2 marks

A curve with equation  y=f(x) has one minimum point at P(3,4).

Write down the coordinates of the minimum point of the curve with the equation  y = f(x5)+6.

2b
Sme Calculator
2 marks

Write down an equation of the graph if the minimum point is instead translated to the point (0, 0)

3
1 mark

The graph with equation  y=x2+ax+b undergoes a translation of two units in the positive x direction and four units in the negative y direction.

The equation of the translated graph is  y=x2x10.

Find the values of a and b.

4a
1 mark

The point P(3, 2) lies on the curve with equation  y=f(x).

On the graph of y=f(x)+a, where a is a constant, the point P is mapped to the point (3, 5).

Determine the value of  a.

4b
1 mark

On the graph of y=f(x+b), where b is a constant, the point P is mapped to the point (1, 2).

Determine the value of b.

4c
2 marks

A different function, g(x), is a cubic function of the form g(x)=ax3+bx2+cx+d.

The graph of y=g(x) is translated by the vector (50).

Write down the equation of the transformed graph in terms of a, b, c, d, and x.