Redox Equilibria (Edexcel International A Level (IAL) Chemistry): Exam Questions

Exam code: YCH11

1 hour17 questions
1
1 mark

The standard hydrogen electrode uses an electrode of platinum coated in a finely divided form of the metal called platinum black.

What is the purpose of this coating?

  • to increase the rate of the equilibrium between the hydrogen gas and the hydrogen ions

  • to provide an inert protective coating for the electrode

  • to increase the electrical conductivity of the electrode

  • to ensure that the conditions remain standard

1a
1 mark

The apparatus shown was used to measure the standard electrode potential for the reduction of Cr2O72 ions to Cr3+ ions in acid solution:

Cr2O72(aq) + 14H+(aq) + 6e→ 2Cr3+(aq) + 7H2O(l)

q1-paper-5-oct-2021-edexcel-ial-chemistry

Which material should be used for each electrode?


 

Electrode 1

Electrode 2

A

Na2Cr2O7

Cr2O3

B

H2

Cr

C

Pt

Cr

D

Pt

Pt

    1b
    1 mark

     Solution 1 is

    • 0.33 mol dm–3 H3PO4 (aq)

    • 0.50 mol dm–3 H2SO4 (aq)

    • 1.00 mol dm–3 HCl (aq)

    • 1.00 mol dm–3 CH3COOH (aq)

    1c
    Sme Calculator
    1 mark

    Solution 2 contains 14.71g of K2Cr2O7 .

    What mass of Cr2(SO4)3⋅18H2O should also be used?

    [Mr values: K2Cr2O7 = 294.2 Cr2(SO4)3⋅18H2O = 716.3]

    • 8.95 g

    • 17.91 g

    • 19.62 g

    • 35.82 g

    1d
    1 mark

    Solution 2 is best acidified with

    • H2SO4

    • HCl

    • HBr   

    • H2CrO4

    2a
    1 mark

    A hydrogen‐oxygen fuel cell is used to provide electrical energy for an electric motor in a car.

    The electrolyte in the fuel cell is acidic. What is the half‐equation at the anode?

    • 1⁄2O2 (g) + 2H+ (aq) + 2e→ H2O (l)

    • H2O (l) → 1⁄2O2 (g) + 2H+ (aq) + 2e

    • H2 (g) → 2H+ (aq) + 2e

    • 2H+ (aq) + 2e→ H2 (g)

    2b
    1 mark

    Hydrogen‐oxygen fuel cells have advantages over methanol‐oxygen fuel cells in vehicles.

    Which of these is an advantage of the hydrogen‐oxygen fuel cell?

    • more energy is released per mole of fuel used

    • emissions do not contribute to climate change

    • hydrogen is easier to store than methanol

    • only hydrogen can be obtained from renewable resources

    3
    1 mark

    The equation for a redox reaction is

    5Fe2+(aq) + MnO4(aq) + 8H+(aq) → 5Fe3+(aq) + Mn2+(aq) + 4H2O(l)

    Which is the correct cell diagram to measure Eθcell for this reaction?

    • Fe | Fe2+, Fe3+ || [MnO4 + 8H+], [Mn2+ + 4H2O] | Mn

    • Fe | Fe2+, Fe3+ || [Mn2+ + 4H2O], [MnO4 + 8H+] | Mn

    • Pt | Fe2+, Fe3+ || [MnO4 + 8H+], [Mn2+ + 4H2O] | Pt

    • Pt | Fe2+, Fe3+ || [Mn2+ + 4H2O], [MnO4+ 8H+] | Pt

    4a
    Sme Calculator
    1 mark

    This question is about the reaction

    2Fe3+ (aq) + Ti (s) → 2Fe2+ (aq) + Ti2+ (aq)        Ecell = +2.40V

    The electrode potential for the Fe3+/ Fe2+ electrode system is +0.77 V.

    What is the electrode potential for the Ti2+/Ti electrode system?

    • −3.17V

    • −1.63V

    • +1.63V

    • +3.17V

    4b
    1 mark

    What metals should be used for the electrodes in the cell for this reaction?

     

     

    Metals used for the electrode

     

     

    Fe3+/ Fe2+ electrode system

    Ti2+/ Ti electrode system

    A

    iron

    titanium

    B

    iron

    platinum

    C

    platinum

    titanium

    D

    platinum

    platinum

      4c
      Sme Calculator
      1 mark

      The half-cell for the Fe3+/ Fe2+ electrode system is prepared by mixing equal volumes of solutions of iron(II) sulfate, FeSO4, and iron(III) sulfate, Fe2(SO4)3.

      What concentrations of the original solutions are needed for the resulting mixture to be standard?

       

       

      Concentration of the original solution

       

       

      FeSO4

      Fe2(SO4)3

      A

      1 mol dm–3

      0.5 mol dm–3

      B

      1 mol dm–3

      1 mol dm–3

      C

      2 mol dm–3

      1 mol dm–3

      D

      2 mol dm–3

      2 mol dm–3

        5a
        1 mark

        An electrochemical cell is set up to measure Ecell for the reaction

        Fe (s) + Sn2+ (aq) → Fe2+ (aq) + Sn (s)

        What is the cell diagram for this cell?

        • Fe(s) | Fe2+(aq) || Sn(s) | Sn2+(aq)

        • Fe2+(aq) | Fe(s) || Sn2+(aq) | Sn(s)

        • Fe(s) | Fe2+(aq) || Sn2+(aq) | Sn(s)

        • Fe2+(aq) | Fe(s) || Sn(s) | Sn2+(aq)

        5b
        Sme Calculator
        1 mark

        The standard electrode potential for the Fe / Fe2+ electrode system is −0.44 V and Ecell for the reaction is +0.30 V.

        What is the standard electrode potential for the Sn / Sn2+ electrode system?

        • −0.74 V

        • −0.14 V

        • +0.14 V

        • +0.74 V

        6
        1 mark

        Hydrogen-oxygen fuel cells can operate in acidic or alkaline conditions.

        What is the reaction at the anode in an alkaline hydrogen-oxygen fuel cell?

        • O2 (g) + 2H2O (l) + 4e → 4OH(aq)

        • 4OH(aq) → O2 (g) + 2H2O (l) + 4e

        • 2H2O (l) + 2e → H2 (g) + 2OH(aq)

        • H2 (g) + 2OH(aq) → 2H2O (l) + 2e

        7
        Sme Calculator
        1 mark

        Which of these species is the strongest oxidising agent?

        Half-equation

        E° / V

        Cu2+ (aq) + 2e- → Cu (s)

        +0.34

        Fe3+ (aq) + e- → Fe2+ (aq)

        +0.77

        I2 (aq) + 2e- → 2I- (aq)

        +0.54

        Zn2+ (aq) + 2e- → Zn (s)

        −0.76

        • Fe2+

        • Fe3+

        • Zn

        • Zn2+

        8
        Sme Calculator
        1 mark

        Which of these is the correctly balanced half-equation for the reduction of MnO4- (aq) to Mn2+ (aq) in acidic solution?

        • MnO4- + 4H+ + 3e- → Mn2+ + 2H2O

        • MnO4- + 8H+ + 5e- → Mn2+ + 4H2O

        • MnO4- + 8H+ + 7e- → Mn2+ + 4H2O

        • MnO4- + 14H+ + 5e- → Mn2+ + 7H2O

        1a
        1 mark

        An electrochemical cell is made from the electrode systems shown by these half‐equations.

           Ag(aq) + e       ⇌  Ag (s)      E = +0.80V

          VO2+ (aq) + 2H(aq) + e−       ⇌  VO2+ (aq) + H2O (l)   E= +1.00V

        The apparatus used to measure the value for  Ecell  under standard conditions is shown.

        q3-paper-5-jan-2022-edexcel-ial-chemistry

        Which silver compound could be used as the electrolyte in the left‐hand half‐cell?

        • silver nitrate

        • silver hydroxide

        • silver chloride

        • silver carbonate

        1b
        1 mark

        The electrolyte in the right‐hand half‐cell is prepared using equal volumes of

        • 1 mol dm−3 acidified VO2(aq) and 1 mol dm−3 acidified VO2+ (aq)

        • 2 mol dm−3 acidified VO2+ (aq) and 2 mol dm−3 acidified VO2+ (aq)

        • 1 mol dm−3 VO2+ (aq) and 1 mol dm−3 HCl (aq)

        • 1 mol dm−3 VO2+ (aq) and 1 mol dm−3  HCl (aq)

        1c
        1 mark

        Which is the equation for the overall cell reaction under standard conditions?

        • VO2+(aq) + Ag+(aq) + H2O(l)  VO2+(aq) + Ag(s) + 2H+(aq)

        • VO2+(aq) + Ag(s) + 2H+(aq) VO2+(aq) + Ag+(aq) + H2O(l) 

        • VO2+(aq) + 3Ag(s) + 2H+(aq)  VO2+(aq) + 3Ag+(aq) + H2O(l)

        • VO2+(aq) + 3Ag+(aq) + H2O(l) VO2+(aq) + 3Ag(s) + 2H+(aq)

        1d
        Sme Calculator
        1 mark

        Which is the value of Ecell in volts?

        • −1.80

        • −0.20

        • +0.20

        • +1.80

        1e
        1 mark

        Which is the cell diagram for this cell, using the conventional representation of half‐cells?

        • Ag(s) | Ag+(aq) || [ VO2+(aq) + 2H+(aq)] | [VO2+(aq) + H2O(l)] | Pt(s)

        • Ag(s) | Ag+(aq) || [ VO2+(aq) + 2H+(aq)] , [VO2+(aq) + H2O(l)] | Pt(s)

        • Ag(s) | Ag+(aq) || [ VO2+(aq)  + H2O(l)] | [VO2+(aq) + 2H+(aq)] | Pt(s)

        • Ag(s) | Ag+(aq) || [ VO2+(aq)  + H2O(l)] , [VO2+(aq) + 2H+(aq)] | Pt(s)

        2
        1 mark

        Some standard electrode potentials are shown.

        Electrode system

        E / V

        Bk3+ + e ⇌ Bk2+

        –2.80

        Cu2+ + e ⇌ Cu+

        +0.15

        Bk4+ + e ⇌ Bk3+

        +1.67

        Au+ + e ⇌ Au

        +1.69

        Au2+ + e ⇌ Au+

        +1.80

        Ag3+ + e ⇌ Ag2+

        +1.80

        Ag2+ + e ⇌ Ag+

        +1.98

        Cu3+ + e– ⇌ Cu2+

        +2.40

        Which of these disproportionation reactions is thermodynamically feasible under standard conditions?

        • 2Bk3+ → Bk2+ + Bk4+

        • 2Cu2+ → Cu++ Cu3+

        • 2Au+ → Au + Au2+

        • 2Ag2+ → Ag++ Ag3+

        3
        1 mark

        Which is true of a hydrogen‐oxygen fuel cell?

        • the cathode has a more positive potential than the anode

        • hydrogen is oxidised at the cathode

        • oxygen is reduced at the negative electrode

        • the cell potential is different when operating under alkaline or acidic conditions

        4
        Sme Calculator
        1 mark

        Which half-equation correctly represents the reaction occurring at the anode of an alkaline hydrogen–oxygen fuel cell?

        • H2 (g) + 2OH- (aq) → 2H2O (l) + 2e-

        • O2 (g) + 2H2O (l) + 4e- → 4OH- (aq)

        • H2 (g) → 2H+ (aq) + 2e-

        • O2 (g) + 4H+ (aq) + 4e- → 2H2O (l)