Deducing Kp Expressions (Edexcel A Level Chemistry): Revision Note
Exam code: 9CHO
Kp Expressions
We have seen previously that equilibrium reactions can be quantified by reference to an equilibrium expression and equilibrium constant
The equilibrium expression links the equilibrium constant, Kc, to the concentrations of reactants and products at equilibrium taking the stoichiometry of the equation into account
So, for a given reaction:
aA + bB ⇌ cC + dD
Kc is defined as follows:
Kc = [C]c[D]d[A]a[B]b
Where:
[A] and [B] = the equilibrium reactant concentrations (mol dm-3)
[C] and [D] = the equilibrium product concentrations (mol dm-3)
a, b, c and d = the number of moles of the respective reactants and products
Solids are ignored in equilibrium expressions
The Kc of a reaction is constant and only changes if the temperature of the reaction changes
Homogeneous reactions
In the generic example above, if all the substances are gases, we can show the equation with that state symbol
aA (g) + bB (g) ⇌ cC (g) + dD (g)
We can write a different equilibrium expression in terms of the partial pressure of the gases
This equilibrium constant is called Kp and is defined as follows
Kp = pcC (g)eqm×pdD (g)eqmpaA (g)eqm×pbB (g)eqm
Where:
p = the equilibrium partial pressure of each gas in atm
a, b, c and d = the coefficients in the balanced equation.
Heterogeneous reactions
For heterogenous reactions, solids and liquids are ignored in Kp equilibrium expressions
The Kp of a reaction is constant and only changes if the temperature of the reaction changes
Worked Example
Write a Kp expression for the following equilibria and deduce the units of Kp :
N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
CaCO3 (s) ⇌ CaO (s) + CO2 (g)
Answer 1
Kp = p2NH3 (g)eqmpN2 (g)eqm×p3H2 (g)eqm
Units = atm2atm×atm3 = atm-2
Answer 2
Kp = pCO2(g)
Units = atm
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