Methods of Integration (College Board AP® Calculus AB): Exam Questions

1 hour37 questions
1
1 mark

∫3x2sin(x3+4) dx=

  • −cos(x3+4)+C

  • cos(x3+4)+C

  • −x3cos(x3+4)+C

  • x3cos(x3+4)+C

2
1 mark

∫4x−32x2−3x+7 dx=

  • ln|12x2−3x+7|+C

  • ln|4x−32x2−3x+7|+C

  • ln|2x2−3x+7|+C

  • 12x2−18x4x3−9x2+42x

3
1 mark

∫01(4x+6)(x2+3x−1)3 dx=

  • 20

  • 30

  • 40

  • 50

4
1 mark

∫13x2x3+1 dx=

  • 13ln3

  • 13ln14

  • ln3

  • ln14

5
1 mark

∫(cos(3x)+sin(3x))dx=

  • 13sin(3x)−13cos(3x)+C

  • −13sin(3x)+13cos(3x)+C

  • 3sin(3x)−3cos(3x)+C

  • −3sin(3x)+3cos(3x)+C

6
1 mark

∫02e−3xdx=

  • −e−63

  • −3e−6

  • e−6−1

  • 1−e−63

7
1 mark

Using the substitution u=3x+2, ∫28(3x+2)7dx is equivalent to

  • 13∫02u7du

  • 13∫826u7du

  • ∫02u7du

  • ∫826u7du

8
1 mark

∫01(2x−1)4dx=

  • 0

  • 15

  • 25

  • 45

1
1 mark

Using the substitution u=x, ∫49cosxx dx is equal to which of the following?

  • 12∫23cosu du

  • 2∫23cosu du

  • ∫49cosu du

  • 2∫49cosu du

2
1 mark

∫xx−1 dx=

  • x−ln|x|+C

  • −x−ln|x−1|+C

  • x+ln|x−1|+C

  • x2x2−2x+c

3
1 mark

∫π2πsinx1−cosxdx=

  • −2(2+1)

  • −2(2−1)

  • 2(2−1)

  • 2(2+1)

4
1 mark

∫1x2−6x+10dx=

  • arcsin(x−3)+C

  • arctan(x−3)+C

  • ln|x2−6x+10|+C

  • 1(x2−6x+10)2+C

5
1 mark

∫x3+2x2+2x+2x+1dx=

  • 3x3+8x2+12x+246x+12+C

  • 13x3+12x2+2x+C

  • 13x3+12x2+x+ln|x+1|+C

  • (14x4+23x3+x2+2x)·ln|x+1|+C

6
1 mark

∫x3x4−9dx=

  • −18(x4−9)2+C

  • 14ln|x4−9|+C

  • 4ln|x4−9|+C

  • 13arctan(x23)+C

7
1 mark

∫x3sin(x4)dx=

  • −14cos(x4)+C

  • 14cos(x4)+C

  • −x34cos(x4)+C

  • −x44cos(x55)+C

8
1 mark

∫x2dx5x3+1=

  • 130(5x3+1)12+C

  • 215(5x3+1)12+C

  • 23x3(5x3+1)12+C

  • 245(5x3+1)32+C

1
1 mark

∫x1−25x2 dx=

  • 15arcsin(5x)+C

  • x5arcsin(5x)+C

  • −1251−25x2+C

  • −125ln1−25x2+C

2
1 mark

Let f be a function such that ∫312f(3x)dx=9. Which of the following must be true?

  • ∫14f(t) dt=3

  • ∫14f(t) dt=27

  • ∫936f(t) dt=3

  • ∫936f(t) dt=27

3
1 mark

If f is a continuous function and if F'(x)=f(x) for all real numbers x, then ∫496xf(x2)dx=

  • F(3)6−F(2)6

  • 3F(3)−3F(2)

  • F(81)6−F(16)6

  • 3F(81)−3F(16)

4
1 mark

∫(1−cosx ∫0xcost dt) dx=

  • cosx1−cosx+C

  • (cosx−1)1−cosx+C

  • 32(1−cosx)+C

  • 23(1−cosx)32+C

5
1 mark

∫13+2x−x2dx=

  • arcsin(x−12)+C

  • 2arcsin(x−12)+C

  • arcsin(x−1)+C

  • 2arcsin(x−1)+C

6
1 mark

∫x4−2x3+x2−7x−2dx=

  • 14x4−23x3+12x2−7ln|x−2|+C

  • 14x4+12x2+2x−3ln|x−2|+C

  • x4+2x2+8x−12ln|x−2|+C

  • 3x4−8x3+6x2−84ln|x−2|+C