Introduction to Differentiation (Cambridge (CIE) IGCSE Additional Maths): Revision Note

Exam code: 0606

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Written by: Amber

Reviewed by: Dan Finlay

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Definition of gradient

What is the gradient of a curve?

  • At a given point the gradient of a curve is defined as the gradient of the tangent to the curve at that point

  • A tangent to a curve is a line that just touches the curve at one point but doesn't cut the curve at that point

Def Grad Illustr 1, A Level & AS Maths: Pure revision notes
  • A tangent may cut the curve somewhere else on the curve

Def Grad Illustr 2, A Level & AS Maths: Pure revision notes
  • It is only possible to draw one tangent to a curve at any given point

  • Note that unlike the gradient of a straight line, the gradient of a curve is constantly changing

Examiner Tips and Tricks

  • If a question asks for the "rate of change of ..." then it is asking for the "gradient"

Worked Example

The diagram shows the curve with equation y=x32x2x+3. The tangent, T, to the curve at the point A(2, 1) is also shown.

definition-of-gradient-we

Using the diagram, calculate the gradient of the curve at A.

The gradient of the curve at the point A is the same as the gradient of the tangent T. Calculate the gradient of the line.

definition-of-gradient-ma

4(2)31

The gradient is 3

Definition of derivatives

What is a derivative?

  • Calculus is about rates of change

    • the way a car’s position on a road changes is its speed (velocity)

    • the way the car’s speed changes is its acceleration

  • The gradient (rate of change) of a (non-linear) function varies with x

  • The derivative of a function is a function that relates the gradient to the value of x

    • For example, the derivative of  y=x2  is  2x

      • This means that when x=1, the gradient of y=x2  is  2(1)=2

      • And when x=5, the gradient of y=x2  is  2(5)=10

  • The derivative is also called the gradient function

Worked Example

The derivative of y=x32x2x+3 is 3x24x1.

Use the derivative to find the gradient of y=x32x2x+3 at the point A(2, 1).

Substitute x=2 into the derivative, 3x24x1

3(2)24(2)1=1281

gradient = 3

Note that the answer is the same as in the method above

Differentiating powers of x

What is differentiation?

  • Differentiation is the process of finding an expression for the derivative (gradient function) from the equation of a curve

    • The equation of the curve is written y=... and the gradient function is written dydx=...

How do I differentiate powers of x?

  • Powers of x are differentiated according to the following formula:

    • If y=axn then dydx=anxn1

      • e.g.  If y=4x3 then dydx=4×3×x31=12x2

      • you "bring down the power" then "subtract one from the power"

  • Don't forget these two special cases:

    • If y=ax thendydx=a

      • e.g.  If y=6x then dydx=6

    • If y=a thendydx=0

      • e.g.  If y=5 then dydx=0

    • These allow you to differentiate linear terms in x and constants

  • Functions involving fractions with denominators in terms of x will need to be rewritten as negative powers of x first

    • e.g.  If y=4x then rewrite as y=4x1 and differentiate

How do I differentiate sums and differences of powers of x?

  •  The formulae for differentiating powers of x work for a sum or difference of powers of x

    • e.g.  If y=5x4+3x2+4 then dydx=5×4x41+3×(2)x21+0 dydx=20x36x3

    • This is sometimes referred to differentiating 'term-by-term'

  • Products and quotients (divisions) cannot be differentiated in this way so they need expanding/simplifying first

    • e.g.  If y=(2x3)(x24) then expand to y=2x33x28x+12 which is a sum/difference of powers of x and can then be differentiated

What can I do with derivatives (gradient functions)?

  • The derivative can be used to find the gradient of a function at any point

    • The gradient of a function at a point is equal to the gradient of the tangent to the curve at that point

    • A question may refer to the gradient of the tangent

Examiner Tips and Tricks

  • Don't try to do too many steps in your head; write the expression in a format that you can differentiate before you actually differentiate it

    • e.g. y=1x4+2x3 can be rewritten as y=x4+2x3 which is then far easier to differentiate

Worked Example

Find the derivative of 

(a)y=5x3+2x+3x2+8

Rewrite the 3x2 term

y=5x3+2x+3x2+8

Apply the rule for differentiating powers (y=axn, dydx=anxn1) and apply the special cases for the terms 2x and 8 (y=ax, dydx=a and y=a, dydx=0)

dydx=15x2+26x3

Unless a question specifies there is not usually a need to rewrite/simplify the answer

dydx=15x2+26x3

 

(b) y=(2x+3)2

This is a product of two (equal) brackets so cannot be differentiated directly Expand the brackets to get an expression in powers of x Take time to get the expansion correct, writing stages out in full if necessary

y=(2x+3)(2x+3)y=4x2+6x+6x+9y=4x2+12x+9

Differentiate 'term-by-term', looking out for those special cases

dydx=8x+12

There is a factor of 4 but there is no demand to factorise the final answer in the question

dydx=8x+12

 

(c) y=8x6x32x4

This is a quotient so cannot be differentiated directly Spot the single denominator which means we can split the fraction by the two terms on the numerator

y=8x62x4x32x4

Simplify using the laws of indices

y=4x6412x34y=4x212x1

Each term is now a power of x, so differentiate 'term-by-term'

dydx=8x+12x2

There is demand to simplify or write the answer in a particular form

dydx=8x+12x2

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Amber

Author: Amber

Expertise: Maths Content Creator

Amber gained a first class degree in Mathematics & Meteorology from the University of Reading before training to become a teacher. She is passionate about teaching, having spent 8 years teaching GCSE and A Level Mathematics both in the UK and internationally. Amber loves creating bright and informative resources to help students reach their potential.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.