Laws of Logarithms (Cambridge (CIE) IGCSE Additional Maths): Revision Note

Exam code: 0606

Amber

Written by: Amber

Reviewed by: Dan Finlay

Updated on

Laws of logarithms

What are the laws of logarithms?

  • Laws of logarithms allow you to simplify and manipulate expressions involving logarithms

    • The laws of logarithms are equivalent to the laws of indices

  • The laws you need to know are, given a, x, y > 0:

    • logaxy= logax+ logay

      • This relates to ax× ay=ax+y

    • logaxy= logax  logay 

      • This relates to ax÷ ay=axy

    • logaxm= mlogax 

      • This relates to (ax)y=axy

The laws of logarithms
  • There are also some particular results these lead to

    • logaa=1

    • logaax=x

    • alogax=x

    • loga1=0

    • loga(1x)=logax

Properties of logarithms
  • Beware…

    • loga(x+y)  logax+logay

  • These results apply to ln x (logex) too

    • Two particularly useful results are

      • ln ex = x

      • elnx = x

How do I use the laws of logarithms?

  • Laws of logarithms can be used to …

    • … simplify expressions

    • … solve logarithmic equations

    • … solve exponential equations

Simplifying an expression using the laws of logarithms

Examiner Tips and Tricks

  • Remember to check whether your solutions are valid

    • log (x+k) is only defined if x > -k

    • You will lose marks if you forget to reject invalid solutions

Worked Example

a) Write the expression 2 log 4  log 2 in the form log k, where k  .

  

Using the law logaxm = mlogax we can rewrite 2 log 4 as log 42 = log 16.

  

2 log 4  log 2 = log 16  log 2

Using the law loga xy = loga x   loga y:

 

 log 16  log 2 = log 162 = log 8

2log 4  log 2 = log 8

b)   Hence, or otherwise, solve 2 log 4log 2=log 1x.

  

   

Rewrite the equation using the expression found in part (a).

2 log 4  log 2 = log 8

  

log 8 =  log 1x

Using the index law 1x = x1::

 

 log 8 =  log x1

Using the law logaxm = mlogax:

  

log 8=  log x(1) = log x

 

Compare the two sides.

 log 8= log x

x = 8

Change of base

How do I change the base of a logarithm?

  • The formula for changing the base of a logarithm is

logax= logbxlogba

  • The value you choose for b does not matter, however if you do not have a calculator, you can choose b such that the problem will be possible to solve

Why change the base of a logarithm?

  • The laws of logarithms can only be used if the logs have the same base

    • If a problem involves logarithms with different bases, you can change the base of the logarithm and then apply the laws of logarithms

  • Changing the base of a logarithm can be particularly useful if you need to evaluate a log problem without a calculator

    • Choose the base such that you would know how to solve the problem from the equivalent exponent

  • This formula had more use when calculators were less advanced

    • Some old calculators only had a button for logarithm of base 10

    • To calculate log57on these calculators you would have to enter

      • log107log105

  • The formula can be useful when evaluating a logarithm where the two numbers are powers of a common number

    • log48=log28log24=32

  • The formula can be useful when you are solving equations and two logarithms have different bases

    • For example, if you have log3k and log9n within the same equation

      • You can rewrite log9n as log3nlog39  which simplifies to 12log3n

      • Or you can rewrite log3k as log9klog93  which simplifies to 2log9k

  • The formula also allows you to derive and use a formula for switching the numbers:

logax=1logxa

  • Using the fact that logxx=1

Examiner Tips and Tricks

  • It is very rare that you will need to use the change of base formula

  • Only use it when the bases of the logarithms are different

Worked Example

By choosing a suitable value for b, use the change of base law to find the value of  log8 32 without using a calculator.

Note that 8 and 32 are both powers of 2, where 8 = 2 and 32 = 25.

Therefore we can choose b = 2 in the change of base formula. 

loga x = logb xlogb a

  

log832 = log232log28

If  23 = 8 then log2 8 = 3 and if  25 = 32 then log2 32 = 5.

 

 log232log28=53

log832 = 53= 123

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Amber

Author: Amber

Expertise: Maths Content Creator

Amber gained a first class degree in Mathematics & Meteorology from the University of Reading before training to become a teacher. She is passionate about teaching, having spent 8 years teaching GCSE and A Level Mathematics both in the UK and internationally. Amber loves creating bright and informative resources to help students reach their potential.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.