Particles, Antiparticles & Photons (AQA AS Physics): Revision Note

Exam code: 7407

Katie M

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Antimatter

  • The Universe consists of matter in the form of particles i.e. protons, neutrons, electrons, etc.

  • All particles of matter have an antimatter counterpart

  • Antimatter particles are identical to their matter counterpart but have an opposite charge

    • This means if a particle is positive, its antimatter particle is negative, and vice versa

  • Common matter-antimatter pairs are shown in the table below:

Matter

Charge

Antimatter

Charge

Electron

-1

Positron

+1

Proton

+1

Anti-proton

-1

Neutron

0

Anti-neutron

0

Neutrino

0

Anti-neutrino

0

  • Apart from electrons, the corresponding antiparticle has:

    • The same name with the prefix ‘anti-’

    • A line above its corresponding matter particle symbol

Properties of antiparticles

  • Corresponding matter and antimatter particles have:

    • Opposite charges 

    • The same mass

    • The same rest mass-energy

  • The rest mass-energy of a particle is the energy equivalent to the mass of the particle when it is at rest

  • Some values of common particle masses and rest mass-energies are shown in the table below:

Particle and antiparticle

Mass / kg

Rest mass energy / MeV

Electron / positron

9.11 × 10−31

0.510999

Proton / anti-proton

1.67(3) × 10−27

938.257

Neutron / anti-neutron

1.67(5) × 10−27

939.551

Neutrino / anti-neutrino

0

0

Examiner Tips and Tricks

In the exam, don't forget that the datasheet provides masses in kg and rest-mass energies in MeV for a proton, neutron, electron and neutrino.

The photon model

  • Photons are fundamental particles which make up all forms of electromagnetic radiation

  • A photon is defined as:

A massless 'packet' or a 'quantum' of electromagnetic energy

  • This means that energy is not transferred continuously but as discrete packets of energy

  • In other words, each photon carries a specific amount of energy, or 'quanta', and transfers it all in one go, rather than supplying it consistently

Calculating photon energy

  • The energy of a photon can be calculated using the formula:

E = hf

  • Using the wave equation, photon energy can also be written:

E = hcλ

  • Where:

    • E = energy of the photon (J)

    • h = Planck's constant (J s)

    • c = the speed of light (m s-1)

    • f = frequency (Hz)

    • λ = wavelength (m)

  • This equation tells us:

    • The higher the frequency of EM radiation, the higher the energy of the photon

    • The energy of a photon is inversely proportional to the wavelength

    • A long-wavelength photon of light has a lower energy than a shorter-wavelength photon

Diagram of a photon as an electromagnetic wave, with shorter wavelength and higher frequency represented by closer oscillations; the equation “E equals h f” appears below.
The energy of a photon is linked to the frequency of the light wave by the Planck constant, h

Worked Example

Light of wavelength 490 nm is incident normally on a surface, as shown in the diagram.

Three parallel light rays labelled “Light wavelength 490 nm” strikes a shaded surface perpendicularly, with right-angle markers indicating normal incidence.

The power of the light is 3.6 mW. The light is completely absorbed by the surface.

Calculate the number of photons incident on the surface in 2.0 s.

[3]

Answer:

Step 1: Write down the known quantities

  • Wavelength, λ = 490 nm = 490×10−9 m

  • Power, P = 3.6 mW = 3.6×10−3 W

  • Time, t = 2.0 s

Step 2: Write down the equations for wave speed and photon energy

Wave speed: c = fλ   →   f = cλ

Photon energy: E = hf   →   E = hcλ

Step 3: Calculate the energy of one photon

E = hcλ = (6.63 × 10−34)(3.0 × 108)490 × 10−9

E = 4.06 × 10−19 J [1 mark]

Step 4: Calculate the number of photons hitting the surface each second

photons hitting surface per second = power of light sourceenergy of one photon

photons hitting surface per second = 3.6 × 10−34.06 × 10−19

photons hitting surface per second = 8.9 × 1015 s−1 [1 mark]

Step 5: Calculate the number of photons that hit the surface in 2.0 s

number of photons = (8.9 × 1015) × 2

number of photons = 1.8 × 1016 [1 mark]

Examiner Tips and Tricks

Make sure you learn the definition for a photon: discrete quantity / packet / quantum of electromagnetic energy are all acceptable definitions. The values of Planck’s constant and the speed of light will always be available on the datasheet, however, it helps to memorise them to speed up calculation questions.

Annihilation & pair production

  • Two important interactions involving particles, antiparticles and photons are:

    • Annihilation 

    • Pair production

Annihilation

  • When a particle meets its corresponding antiparticle, the two will annihilate

  • Annihilation is defined as:

The destruction of a particle-antiparticle pair when they collide and convert their mass into two gamma-ray photons

  • The two most common particle-antiparticle pairs that are seen are:

    • Proton-antiproton annihilation

    • Electron-positron annihilation

An electron labelled negative and a positron labelled positive horizontally collide, producing two gamma-ray photons labelled γ that travel vertically in opposite directions.
When an electron and positron collide, their mass is converted into energy in the form of two photons emitted in opposite directions
  • The minimum energy of one photon after annihilation is the total rest mass energy of one of the particles:

Emin = hfmin = E

  • Where:

    • Emin = minimum energy of one of the photons produced (J)

    • h = Planck's Constant (J s)

    • fmin = minimum frequency of one of the photons produced (Hz)

    • E = rest mass energy of one of the particles (J)

  • To conserve momentum, the two photons will move apart in opposite directions

  • As with all collisions, the mass and energy is still conserved

Pair production

  • Pair production is the opposite of annihilation

  • It is defined as:

The creation of a particle-antiparticle pair when a high-energy photon spontaneously converts its energy into mass

  • To achieve pair production, a single photon must have enough energy to create both particles

A gamma photon enters a labelled nucleus, producing an electron labelled e⁻ and a positron labelled e⁺ that travel away in opposite directions.
When a photon with enough energy interacts with a nucleus it can produce an electron-positron pair
  • The minimum energy required for a photon to undergo pair production is equal to the total rest mass energy of the particles produced:

Emin = hfmin = 2E

  • Where:

    • Emin = minimum energy of the incident photon (J)

    • h = Planck's Constant (J s)

    • fmin = minimum frequency of the photon (Hz)

    • E = rest mass energy of one of the particles (J)

  • To conserve momentum, the particle and the antiparticle move apart in opposite directions

Worked Example

Calculate the maximum wavelength of one of the photons produced when a proton and antiproton annihilate each other.

[3]

Answer:

Step 1: Write down the known quantities

  • Rest mass of a proton (and antiproton) = 938.257 MeV

  • 1 MeV = 1.60×10−13 J

Step 2: Determine the total rest mass energy of the proton-antiproton pair

Etotal = 2 × 938.257 = 1876.514 MeV

Step 3: Determine the minimum energy of one of the photons in J

Emin = 1876.514 × (1.60 × 10−13)2 = 1.5012 × 10−10 J [1 mark]

  • Note: since the question asks for the energy of one of the photons, you could skip step 2 and simply use 938.257 MeV

Step 4: Write down the equation for minimum photon energy

Emin = hfmin = hcλmax

Step 5: Rearrange for the maximum photon wavelength

λmax = hcEmin

Step 6: Calculate the maximum photon wavelength

λmax = (6.63 × 10−34)(3.0 × 108)1.5012 × 10−10 [1 mark]

λmax = 1.32 × 10−15 m [1 mark]

Examiner Tips and Tricks

Since the Planck constant is in Joules (J) remember to always convert the rest mass-energy from MeV to J.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.