Kinetic & Gravitational Potential Energy (AQA AS Physics): Revision Note

Exam code: 7407

Katie M

Written by: Katie M

Reviewed by: Tim

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Kinetic & gravitational potential energy

Kinetic energy

  • Kinetic energy is the energy an object has due to its motion (or velocity)

    • The faster an object is moving, the greater its kinetic energy

  • When an object is falling, it is gaining kinetic energy since it is gaining speed

    • This energy is transferred from the gravitational potential energy it is losing

  • Kinetic energy can be calculated using the following equation:

Ek = 12mv2

  • Where:

    • Ek = kinetic energy (J)

    • m = mass (kg)

    • v = velocity (m s–1)

A moving car labelled “mass, m”, and a right-pointing arrow above it labelled “speed, v”.
A moving object has kinetic energy which increases with its speed

Worked Example

A body travelling with a speed of 12 m s-1 has kinetic energy 1650 J. The speed of the body is increased to 45 m s-1.

Determine the body's new kinetic energy.

[2]

Answer:

Step 1: Calculate the mass of the body

  • The mass of the body will not change, so it can be calculated from its initial kinetic energy

Ek = 12mv2

m = 2Ekv2 = 2 × 1650122 = 22.92 kg [1 mark]

Step 2: Calculate the new kinetic energy

Ek = 12 × 22.92 × (45)2

Ek = 23 200 J [1 mark]

Examiner Tips and Tricks

When using the kinetic energy equation, note that only the speed is squared, not the mass or the ½.

If a question asks about the ‘loss of kinetic energy’, remember not to include a negative sign since energy is a scalar quantity.

Gravitational potential energy

  • Gravitational potential energy is energy stored in a mass due to its position in a gravitational field

    • If a mass is lifted up, it will gain gravitational potential energy

    • If a mass falls, it will lose gravitational potential energy

  • The equation for gravitational potential energy for energy changes in a uniform gravitational field is:

∆Ep = mg∆h

  • Where:

    • ∆Ep = change in gravitational potential energy (J)

    • m = mass (kg)

    • g = gravitational field strength (9.81 N kg–1)

    • ∆h = change in height (m)

A person lifting a mass, m, to a height, h, above the ground. It labels mass and height and states the relationship “GPE equals m times g times h”.
An object gains gravitational potential energy when it is lifted higher
  • The potential energy on the Earth’s surface at ground level is usually taken to be equal to zero

    • However, any position can be taken as zero when calculating the change in gravitational potential energy

  • This equation is only relevant for energy changes in a uniform gravitational field (such as near the Earth’s surface)

Gravitational potential energy v height graphs

  • The two graphs below show how the gravitational potential energy changes with height for a ball being thrown up in the air and then falling down (ignoring air resistance)

Two line graphs of gravitational potential energy against height. For an object thrown upwards, gravitational potential energy increases linearly from zero. For a falling object, gravitational potential energy decreases linearly to zero. Axes are GPE in joules and height in metres.
Graphs showing the linear relationship between gravitational potential energy and height
  • Since the graphs are straight lines, gravitational potential energy and height are said to have a linear relationship

  • These graphs would be identical for gravitational potential energy against time instead of height

Worked Example

To get to their apartment, a person has to climb five flights of stairs.

The height of each flight is 3.7 m and the person has a mass of 74 kg.

What is the approximate change in the person's gravitational potential energy during the climb?

A.     13 000 J               B.     2700 J               C.     1500 J               D.     12 500 J

[1]

Answer:

  • Calculate the change in height:

∆h = 5 × 3.7 = 18.5 m

  • Calculate the change in gravitational potential energy:

∆Ep = mg∆h = 74 × 9.81 × 18.5 = 13 400 J = 13 000 J (2 s.f.)

  • Therefore, the correct answer is A [1 mark]

Examiner Tips and Tricks

This equation only works for objects close to the Earth’s surface, where we can consider the gravitational field to be uniform.

At A level, you might have to consider examples where the gravitational field is not uniform, such as in space, where this equation will not be relevant.

Gravitational potential energy is often shortened to GPE for ease. In your equations, you should stick to the correct symbol, which is ∆Ep.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.