Operations with Numbers & Decimals (Cambridge (CIE) IGCSE Maths: Core): Exam Questions

Insert one pair of brackets into this statement to make it correct.

7   ×   5   –   2   +   3   =   42

Put one pair of brackets into the calculation to make it correct.

8  +  6  -  2  $\times$  5  =  28

Put one pair of brackets into the calculation to make it correct.

8  +  6  -  2  $\times$ 5  =  60

Insert one pair of brackets to make this statement correct.

$4\times 6-2+1=17$

Subtract 123 from 1 million.

Subtract 9 from 2.

i) Two numbers are added together to give the number in the box immediately above.

Complete the diagram.

[2]

ii) Two numbers are multiplied together to give the number in the box immediately above.

Complete the diagram.

[3]

Insert one pair of brackets to make this statement correct.

$3+2\times 12-4=19$

Work out $\left(9+2^2-4\times 2\right)+\sqrt{144}$

Insert one pair of brackets to make this statement correct.

$9+4-3\times 7=70$

Work out

$6\times 3+24÷4$

Work out

$4+\left(-11\right)$

Put one pair of brackets in each statement to make it correct.

$16÷8+4\times 2=1$

$16÷8+4\times 2=12$

Put one pair of brackets into each calculation to make it correct.

i) $24÷6+2\times 3=9$

[1]

ii) $24÷6+2\times 3=2$

[1]

Insert one pair of brackets in the following to make the statement correct.

$5+3\times 10-1=32$

Insert one pair of brackets in the following to make the statement correct.

$3\times 2-4-7=9$

Calculate $18÷\left(10-4\right)-11\times 4+9\times \left(6+1\right)$

Jamie has incorrectly tried to calculate: $3\times 2^3+\sqrt{25}\times \left(3^2\times 2+3\right)$

His working is shown below.

$$\begin{gathered} 3\times 2^3+\sqrt{25}\times \left(3^2\times 2+3\right) \\ 3\times 2^3+\sqrt{25}\times \left(40\right) \\ {6}^3+5\times \left(40\right) \\ 216+200 \\ 416 \end{gathered}$$

Identify the two mistakes that have been made, and find the correct final answer.