Hooke's Law (AQA GCSE Combined Science: Synergy: Physical Sciences): Revision Note
Exam code: 8465
Written by: Ashika
Updated on
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What is Hooke's Law
The relationship between the extension of an elastic object and the applied force is defined by Hooke's Law
Hooke's Law states that:
The extension of an elastic object is directly proportional to the force applied, up to the limit of proportionality
Directly proportional means that as the force is increased, the extension increases
If the force is doubled, then the extension will double
If the force is halved, then the extension will also halve
The limit of proportionality is the point beyond which the relationship between force and extension is no longer directly proportional
This limit varies according to the material

Using Hooke's Law
Hooke's Law Equation
Hooke's Law is defined by the equation:
F = k × e
Where:
F = force in newtons (N)
k = spring constant in newtons per metres (N/m)
e = extension in metres (m)
The symbol e can represent either the extension or compression of an elastic object
The spring constant represents how stiff a spring is
The higher the spring constant, the higher the stiffness
The extension of an object can be calculated by:
final length – original length
The extension of the spring can be measured by marking the position of bottom of the unstretched spring
When the spring is stretched the final length must be measured from the bottom of the spring

The Hooke's Law equation can be rearranged with the help of the following equation triangle:

Worked Example
The figure below shows the forces acting on a child who is balancing on a pogo stick. The child and pogo stick are not moving.

The spring constant of the spring on the pogo stick is 4900 N/m. The weight of the child causes the spring to compress elastically from a length of 40 cm to a new length of 33 cm. Calculate the weight of the child.
Answer:
Step 1: List the known quantities
Spring constant, k = 4900 N/m
Original length = 40 cm
Final length = 33 cm
Step 2: Write the relevant equation
F = k x e
Step 3: Calculate the compression, e
e = original length - final length
e = 40 - 33 = 7 cm
Step 4: Convert any units
Since the spring constant is given in N/m,
must be in metres (m)
Step 5: Substitute the values into the Hooke's Law equation
F = 4900 x 0.07
F = 343 N
The child's weight is 343 N
Examiner Tips and Tricks
Look out for unit conversions! Unless the spring constant is given in N/cm, make sure the extension is converted into metres (÷ 100) before substituting values into the Hooke's Law equation
Linear & Non-Linear Extension
Hooke’s law is the linear relationship between force and extension
This is represented by a straight line on a force-extension graph
Materials that do not obey Hooke's law, i.e force and extension are no longer directly proportional; they have a non-linear relationship
This is represented by a curve on a force-extension graph

Calculating Spring Constant
The spring constant can be calculated by rearranging the Hooke's law equation for k:
k =
Where:
k = spring constant in newtons per metres (N/m)
F = force in newtons (N)
e = extension in metres (m)
This equation shows that the spring constant is equal to the force per unit extension needed to extend the spring, assuming that its limit of proportionality is not reached
The stiffer the spring, the greater the spring constant and vice versa
This means that more force is required per metre of extension compared to a less stiff spring

The spring constant is also used in the equation for elastic potential energy
Worked Example
A mass of 0.6 kg is suspended from a spring, where it extends by 2 cm. Calculate the spring constant of the spring.
Answer:
Step 1: List the known quantities
Mass, m = 0.6 kg
Extension, e = 2 cm
Step 2: Write down the relevant equation
k =
Step 3: Calculate the force
The force on the spring is the weight of the mass
g is Earth's gravitational field strength (9.8 N/kg)
W = mg
W = 0.6 × 9.8 = 5.88 N
Step 4: Convert any units
The extension must be in metres
2 cm = 0.02 m
Step 5: Substitute values into the equation
k = = 294 N/m
Examiner Tips and Tricks
Remember the unit for the spring constant is Newtons per metres (N/m). This is commonly forgotten in exam questions
When asked to calculate the spring constant, use F = ke. A common mistake is using the elastic potential energy equation (Ee = ½ke2) instead but this cannot give you k directly without knowing the energy stored.
Interpreting Graphs of Force v Extension
The relationship between force and extension is shown on a force-extension graph
If the force-extension graph is a straight line, then the material obeys Hooke's law
Sometimes, this may only be a small region of the graph, up to the material's limit of proportionality

The symbol Δ means the 'change in' a variable
For example, ΔF and Δe are the 'change in' force and extension respectively
This is the same as rise ÷ run for calculating the gradient
The '∝' symbol means 'proportional to'
i.e. F ∝ e means the 'the force is proportional to the extension'

If the force is on the y axis and the extension on the x axis, the spring constant is the gradient of the straight line (Hooke's law) region of the graph
If the graph has a steep straight line, this means the material has a large spring constant
If the graph has a shallow straight line, this means the material has a small spring constant
If the force is on the x axis and the extension on the y axis, the spring constant is 1 ÷ gradient of the straight line (Hooke's law) region of the graph
If the graph has a steep straight line, this means the material has a small spring constant
If the graph has a shallow straight line, this means the material has a large spring constant
Worked Example
A student investigates the relationship between the force applied and extension for three springs K, L and M. The results are shown on the graph below:

Which of the statements is correct?
A. K has a higher spring constant than the other two springs
B. M has the same spring constant as K
C. L has a higher spring constant than M
D. K has a lower spring constant than the other two springs
Answer: D
The graph has the extension on the y axis and the weight (force) on the x-axis
This means that the spring constant is 1 ÷ gradient
Therefore the steeper the straight line, the lower the spring constant
K has the steepest gradient and therefore has a lower spring constant than L and M
Examiner Tips and Tricks
Make sure to always check which variables are on which axes to determine which line has a larger or smaller spring constant, as well as the units for calculations
The limit of proportionality is the point where the straight line starts to curve, not the last data point on the graph. When identifying it, look for where the graph first deviates from a straight line.
If a graph shows a spring being unloaded (force decreasing after the limit of proportionality has been exceeded), the extension decreases but does not return to zero, then the spring has been permanently deformed.
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