Hooke's Law (AQA GCSE Combined Science: Synergy: Physical Sciences): Revision Note

Exam code: 8465

What is Hooke's Law

  • The relationship between the extension of an elastic object and the applied force is defined by Hooke's Law

  • Hooke's Law states that:

The extension of an elastic object is directly proportional to the force applied, up to the limit of proportionality

  • Directly proportional means that as the force is increased, the extension increases 

    • If the force is doubled, then the extension will double

    • If the force is halved, then the extension will also halve

  • The limit of proportionality is the point beyond which the relationship between force and extension is no longer directly proportional 

    • This limit varies according to the material

Two springs hang from a horizontal bar; a load is attached to the second spring, causing an extension. Arrows indicate force and extension direction.
Hooke's Law states that a force applied to a spring will cause it to extend by an amount proportional to the force, this can be tested by this Hooke's Law experiment

Using Hooke's Law

Hooke's Law Equation

  • Hooke's Law is defined by the equation:

F = k × e

  • Where:

    • F = force in newtons (N)

    • k = spring constant in newtons per metres (N/m)

    • e = extension in metres (m)

  • The symbol e can represent either the extension or compression of an elastic object

  • The spring constant represents how stiff a spring is

    • The higher the spring constant, the higher the stiffness

  • The extension of an object can be calculated by:

final length – original length

  • The extension of the spring can be measured by marking the position of bottom of the unstretched spring

  • When the spring is stretched the final length must be measured from the bottom of the spring

Diagram showing a spring system with extension calculation. Includes original and final lengths, spring constant, and force, with ruler for measurement.
Force, extension and spring constant are used to define Hooke's Law
  • The Hooke's Law equation can be rearranged with the help of the following equation triangle:

Hookes Law Formula Triangle

Worked Example

The figure below shows the forces acting on a child who is balancing on a pogo stick. The child and pogo stick are not moving.

Person on a pogo stick with a compressed spring, arrows showing downward and upward forces, illustrating energy transfer in motion.

The spring constant of the spring on the pogo stick is 4900 N/m. The weight of the child causes the spring to compress elastically from a length of 40 cm to a new length of 33 cm. Calculate the weight of the child.

Answer:

Step 1: List the known quantities

  • Spring constant, k = 4900 N/m

  • Original length = 40 cm

  • Final length = 33 cm

Step 2: Write the relevant equation

F = k x e

Step 3: Calculate the compression, e

e = original length - final length

e = 40 - 33 = 7 cm

Step 4: Convert any units

  • Since the spring constant is given in N/m, x must be in metres (m)

e equals 7 over 100 equals 0.07 space straight m

Step 5: Substitute the values into the Hooke's Law equation

F = 4900 x 0.07

F = 343 N

  • The child's weight is 343 N

Examiner Tips and Tricks

Look out for unit conversions! Unless the spring constant is given in N/cm, make sure the extension is converted into metres (÷ 100) before substituting values into the Hooke's Law equation

Linear & Non-Linear Extension

  • Hooke’s law is the linear relationship between force and extension

    • This is represented by a straight line on a force-extension graph

  • Materials that do not obey Hooke's law, i.e force and extension are no longer directly proportional; they have a non-linear relationship

    • This is represented by a curve on a force-extension graph

Graph showing force versus extension with a linear region, a marked limit of proportionality, and a non-linear region.
Linear and non-linear regions of a force-extension graph

Calculating Spring Constant

  • The spring constant can be calculated by rearranging the Hooke's law equation for k:

k = F over e

  • Where:

    • k = spring constant in newtons per metres (N/m)

    • F = force in newtons (N)

    • e = extension in metres (m)

  • This equation shows that the spring constant is equal to the force per unit extension needed to extend the spring, assuming that its limit of proportionality is not reached

  • The stiffer the spring, the greater the spring constant and vice versa

    • This means that more force is required per metre of extension compared to a less stiff spring

Two springs, A and B, with weights. Spring A has a small constant; spring B has a large constant, requiring more force for the same extension.
A spring with a larger spring constant needs more force per unit extension (it is stiffer)
  • The spring constant is also used in the equation for elastic potential energy

Worked Example

A mass of 0.6 kg is suspended from a spring, where it extends by 2 cm. Calculate the spring constant of the spring.

Answer:

Step 1: List the known quantities

  • Mass, m = 0.6 kg

  • Extension, e = 2 cm

Step 2: Write down the relevant equation

k = F over e

Step 3: Calculate the force

  • The force on the spring is the weight of the mass

  • is Earth's gravitational field strength (9.8 N/kg)

W = mg

W = 0.6 × 9.8 = 5.88 N

Step 4: Convert any units

  • The extension must be in metres

2 cm = 0.02 m

Step 5: Substitute values into the equation

k = fraction numerator 5.88 over denominator 0.02 end fraction = 294 N/m

Examiner Tips and Tricks

Remember the unit for the spring constant is Newtons per metres (N/m). This is commonly forgotten in exam questions

When asked to calculate the spring constant, use F = ke. A common mistake is using the elastic potential energy equation (Ee = ½ke2) instead but this cannot give you k directly without knowing the energy stored.

Interpreting Graphs of Force v Extension

  • The relationship between force and extension is shown on a force-extension graph

  • If the force-extension graph is a straight line, then the material obeys Hooke's law

    • Sometimes, this may only be a small region of the graph, up to the material's limit of proportionality

Graph showing Hooke's Law, with force on the y-axis and extension on the x-axis. Line is linear then curves at limit of proportionality.
The Hooke's law region on a force-extension graph is where the graph is a straight line
  • The symbol Δ means the 'change in' a variable

    • For example, ΔF and Δe are the 'change in' force and extension respectively

    • This is the same as rise ÷ run for calculating the gradient

  • The '∝' symbol means 'proportional to'

    • i.e. F e means the 'the force is proportional to the extension'

Two graphs show force vs extension. Left: steep line, "large k"; shallow line, "small k". Right: steep line, "small k"; shallow line, "large k".
The spring constant is the gradient, or 1 ÷ gradient of a force-extension graph depending on which variable is on which axis 
  • If the force is on the y axis and the extension on the x axis, the spring constant is the gradient of the straight line (Hooke's law) region of the graph

    • If the graph has a steep straight line, this means the material has a large spring constant

    • If the graph has a shallow straight line, this means the material has a small spring constant

  • If the force is on the x axis and the extension on the y axis, the spring constant is 1 ÷ gradient of the straight line (Hooke's law) region of the graph

    • If the graph has a steep straight line, this means the material has a small spring constant

    • If the graph has a shallow straight line, this means the material has a large spring constant

Worked Example

A student investigates the relationship between the force applied and extension for three springs K, L and M. The results are shown on the graph below:

Graph showing three lines, K, L, and M, representing extension in cm versus weight in newtons, with K having the steepest slope. Grid background with labels.

Which of the statements is correct?

A. K has a higher spring constant than the other two springs

B. M has the same spring constant as K

C. L has a higher spring constant than M

D. K has a lower spring constant than the other two springs

Answer: D

  • The graph has the extension on the y axis and the weight (force) on the x-axis

    • This means that the spring constant is 1 ÷ gradient

  • Therefore the steeper the straight line, the lower the spring constant

  • K has the steepest gradient and therefore has a lower spring constant than L and M

Examiner Tips and Tricks

Make sure to always check which variables are on which axes to determine which line has a larger or smaller spring constant, as well as the units for calculations

The limit of proportionality is the point where the straight line starts to curve, not the last data point on the graph. When identifying it, look for where the graph first deviates from a straight line.

If a graph shows a spring being unloaded (force decreasing after the limit of proportionality has been exceeded), the extension decreases but does not return to zero, then the spring has been permanently deformed.

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