Using Hess Cycles (Edexcel International AS Chemistry): Revision Note

Exam code: XCH11

Richard Boole

Written by: Richard Boole

Reviewed by: Caroline Carroll

Updated on

Hess Cycles - Construction

  • In 1840, the Russian chemist Germain Hess formulated a law which went on to be known as Hess’s Law

  • This went on to form the basis of one of the laws of thermodynamics. The first law of thermodynamics relates to the Law of Conservation of Energy

  • It is sometimes expressed in the following form:

Energy cannot be created or destroyed, it can only change form

  • This means that in an isolated system, the total amount of energy present is always constant

  • Hess’s law can be used to calculate the standard enthalpy change of a reaction from known standard enthalpy changes

  • Hess’s Law states that:

"The total enthalpy change in a chemical reaction is independent of the route by which the chemical reaction takes place as long as the initial and final conditions are the same."

  • This means that whether the reaction takes place in one or two steps, the total enthalpy change of the reaction will still be the same

Hess cycle: direct route from A + B to C, and two indirect routes, one via F + G and one via X then Y + Z

According to Hess’ Law, the enthalpy change of the direct route, going from reactants (A+B) to product (C), is equal to the enthalpy change of the indirect routes

  • Hess’ Law is used to calculate enthalpy changes which can’t be found experimentally using calorimetry, e.g.:

3C (s) + 4H2 (g) → C3H8(g)

  • ΔfH (propane) can’t be found experimentally as hydrogen and carbon don’t react under standard conditions

Calculating ΔHr from ΔHf using Hess’s Law energy cycles

  • You can see the relationships on the following diagram:

    Enthalpy cycle: direct route from elements to products (delta H2); indirect route from elements to reactants (delta H1) then reactants to products (delta Hr)

The enthalpy change from elements to products (direct route) is equal to the enthalpy change of elements forming reactants and then products (indirect route)

  • The products can be formed:

    • Directly from the elements = ΔH2
      OR
      Indirectly from the elements = ΔH1 + ΔHr

  • Equation

ΔH2 = ΔH1 + ΔHr

  • Therefore for energy to be conserved,

ΔHr = ΔH2 – ΔH1

Examiner Tips and Tricks

You do not need to learn Hess's Law word for word, but you do need to know it and be able to apply it: it provides the foundation for all the problem solving in Chemical Energetics

Hess Cycles - Calculations

Calculating ΔHr  from ΔHf using Hess’s Law energy cycles

  • Knowing the enthalpy change of formation, ΔHf, allows us to determine the overall enthalpy change of a reaction, ΔHr

  • To do this, we follow these steps:

    1. Write the equation for the reaction

    2. Write the elements with the correct number of moles and state symbols underneath

    3. Draw upwards pointing arrows to each compound

    4. Write the appropriate values on the arrows and multiply by the number of moles

    5. In a cycle, go from the reactants to the products, changing the sign of the value if the arrow points in the opposite direction

Worked Example

Calculating the enthalpy change of reaction

Use the information in the table to calculate the enthalpy change for this reaction:

NH4NO3 (s)  +  ½C (s)  →  N2 (g)  +  2H2O (g)  +  ½CO2 (g)

Substance

C (s)

N2 (g)

H2O(g)

CO2 (g)

NH4NO3 (s)

∆Hfө / kJ mol–1

0

0

–242

–394

–365

Answer:

 Step 1: Write the balanced equation

Balanced equation: NH4NO3(s) + 1/2 C(s) goes to N2(g) + 2H2O(g) + 1/2 CO2(g)

Step 2: Write the elements with the correct number of moles and state symbols underneath

The elements, in their standard states, go beneath the equation: N2 (g) + 1.5O2 (g) + ½C (s) + 2H2 (g).

The same equation with the elements in their standard states written beneath it: N2(g) + 1.5 O2(g) + ½C(s) + 2H2(g)

Step 3: Draw upwards pointing arrows to each compound

Upward arrows from the elements to NH4NO3, to N2 + 2H2O, and to 1/2 CO2 in the equation

Step 4: Write the appropriate values on the arrows and multiply by the number of moles

Cycle with the values on the arrows: -365 to NH4NO3, 2 x -242 = -484 to 2H2O, 0.5 x -394 = -197 to 1/2 CO2

Step 5: In a cycle, go from the reactants to the products, changing the sign of the value if the arrow points in the opposite direction

Completed cycle: the route from reactants to elements is +365 (sign reversed) and from elements to products is -484 - 197

ΔHrө = +365 - 484 - 197 = -316 kJ mol-1

  • The sign on -365 needs reversing as the cycle goes in the opposite direction to the arrow pointing upwards

  • There is no need to draw arrows from the elements to carbon and nitrogen as ΔHfө is 0 for elements

Examiner Tips and Tricks

Keep your enthalpy values inside their own brackets so that you don't accidentally lose a minus sign

Calculating ΔHf from ΔHc using Hess’s Law energy cycles

  • It can be difficult to find the enthalpy change of formation of compounds experimentally

  • However, many enthalpy changes of combustion can be measured experimentally so these can be used to find the enthalpy of formation

  • To do this, we follow these steps:

    1. Write the equation for the formation of the compound

    2. Write the combustion products below the equation

    3. Draw downward pointing arrows from each substance to its combustion products

    4. Write values on the arrows and multiply by the number of moles

    5. In a cycle, go from the reactants to the products, changing the sign of the value if the arrow points in the opposite direction

Worked Example

Calculating the enthalpy change of formation

Using the data provided, calculate the standard enthalpy change of formation, ΔHf, of propanone.

3C (s)  +     3H2 (g)   +      ½ O2 (g)       →        CH3COCH3 (l)

Substance

C (s)

H2 (g)

CH3COCH3 (l)

∆HCө / kJ mol–1

-394

-286

-1821

Answer:

  • Step 1: Write the balanced equation

Balanced equation: 3C(s) + 3H2(g) + 1/2 O2(g) goes to CH3COCH3(l)
  • Step 2:Write the combustion products below the equation

The combustion products are written beneath the equation: 3CO2 + 3H2O.

The same equation with the combustion products 3CO2 + 3H2O drawn beneath it
  • Step 3: Draw downward pointing arrows from each substance to its combustion product

Downward arrows from 3C(s), 3H2(g) and CH3COCH3(l) to the combustion products 3CO2 + 3H2O
  • Step 4: Write the appropriate values on the arrows and multiply by the number of moles

Cycle with values on the arrows: 3 x -394 = -1182 from carbon, 3 x -286 = -858 from hydrogen, -1821 from propanone
  • Step 5: In a cycle, go from the reactants to the products, changing the sign of the value if the arrow points in the opposite direction

Completed cycle: -1182 - 858 from the elements to the combustion products, then +1821 (sign reversed) from the combustion products to propanone

ΔHfө = -1182 - 858 + 1821 = -219 kJ mol-1

  • The sign on -1821 needs reversing as the cycle goes in the opposite direction to the arrow pointing to the combustion products

Examiner Tips and Tricks

Don't forget to make sure the number of atoms for each element is balanced when drawing your cycle.

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Richard Boole

Author: Richard Boole

Expertise: Curriculum Expert

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.