Determining Concentrations (Edexcel International AS Chemistry): Revision Note

Exam code: XCH11

Richard Boole

Written by: Richard Boole

Reviewed by: Caroline Carroll

Updated on

Core Practical 3: Hydrochloric Acid Concentration

Performing the Titration

  • The key piece of equipment used in the titration is the burette

  • Burettes are usually marked to a precision of 0.10 cm3

    • Since they are analogue instruments, the uncertainty is recorded to half the smallest marking, in other words to ±0.05 cm3

  • The equivalence point occurs when the two solutions have reacted completely; the end point is when the indicator changes colour, and a suitable indicator changes colour at (or very close to) the equivalence point

Steps of a titration: a pipette delivers solution into a conical flask with a few drops of indicator, and the second solution is added from a burette until the indicator just changes colour

The steps in a titration

  • A white tile is placed under the conical flask while the titration is performed, to make it easier to see the colour change

Titration apparatus: a burette held in a clamp on a stand above a conical flask of solution standing on a white tile

Titrating 

  • The steps in a titration are:

    • Measuring a known volume (usually 20 or 25 cm3) of one of the solutions with a volumetric pipette and placing it into a conical flask

    • The other solution is placed in the burette

      • To start with, the burette will usually be filled to 0.00 cm3

    • A few drops of the indicator are added to the solution in the conical flask

    • The tap on the burette is carefully opened and the solution added, portion by portion, to the conical flask until the indicator starts to change colour

    • As you start getting near to the end point, the flow of the burette should be slowed right down so that the solution is added dropwise

      • You should be able to close the tap on the burette after one drop has caused the colour change

    • Multiple runs are carried out until concordant results are obtained

      • Concordant results are within 0.1 cm3 of each other

Recording and processing titration results

  • Both the initial and final burette readings should be recorded and shown to a precision of  ±0.05 cm3, the same as the uncertainty

Titration results table (Rough, Run 1, Run 2, Run 3) with initial and final burette readings and volumes delivered of 23.75, 22.80, 22.80 and 23.10 cm3; Runs 1 and 2 are ticked as concordant

A typical layout and set of titration results

  • The volume delivered (titre) is calculated and recorded to an uncertainty of ±0.10 cm3

    • The uncertainty is doubled, because two burette readings are made to obtain the titre (V final – V initial), following the rules for propagation of uncertainties

  • Concordant results are then averaged, and non-concordant results are discarded

  • The appropriate calculations are then done

Worked Example

25.0 cm3 of hydrochloric acid was titrated with a 0.200 mol dm-3 solution of sodium hydrogencarbonate, NaHCO3. 

NaHCO3 + HCl → NaCl + H2O + CO2 

Use the following results to calculate the concentration of the acid, to 3 significant figures.

Rough

Run 1

Run 2

Run 3

Initial burette reading / cm3 (±0.05)

0.00

23.15

0.20

23.00

Final burette reading / cm3 (±0.05)

23.75

45.95

23.00

46.10

Volume delivered / cm3 (±0.10)

23.75

22.80

22.80

23.10

Runs 1 and 2 are concordant; the rough titre and Run 3 are not used.

Titration results table: initial readings 0.00, 23.15, 0.20 and 23.00 cm3, final readings 23.75, 45.95, 23.00 and 46.10 cm3, volumes delivered 23.75, 22.80, 22.80 and 23.10 cm3

Answer

Step 1: Calculate the average titre

  • Average titre= 22.80 + 22.802 =22.80 cm3

Step 2: Calculate the number of moles of sodium hydrogencarbonate

  • Moles = 22.801000 x 0.200 = 4.56 x 10-3 moles

Step 3: Calculate (or deduce) the number of moles of hydrochloric acid

  • The stoichiometry of NaHCO3 : HCl is 1 : 1

    • Therefore, the number of moles of hydrochloric acid is also 4.56 x 10-3 moles

Step 4: Calculate the concentration of hydrochloric acid

  • Concentration = = molesvolume =4.56 × 10−3(25.0 / 1000) = 0.182 mol dm-3 

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Richard Boole

Author: Richard Boole

Expertise: Curriculum Expert

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.