Biological Membranes (OCR A Level Biology): Flashcards

Exam code: H420

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  • What is the role of the cell surface membrane?

    It creates an enclosed space that separates the internal cell environment from the external environment.

  • What is the role of intracellular (internal) membranes?

    They form compartments within the cell, such as organelles (e.g. the nucleus, mitochondria and RER) and vacuoles.

  • Partially permeable membrane

    A membrane that acts as a barrier but controls the exchange of materials passing through it, allowing only some substances to cross.

  • By which four processes can substances cross membranes?

    • Diffusion

    • Facilitated diffusion

    • Osmosis

    • Active transport

  • How do membranes contribute to cell signalling?

    They act as an interface for communication between cells.

  • The fluid mosaic model describes membranes as 'fluid' because the phospholipids and can move around within the bilayer via diffusion.

    The fluid mosaic model describes membranes as 'fluid' because the phospholipids and proteins can move around within the bilayer via diffusion.

  • In the fluid mosaic model, why are membranes described as a 'mosaic'?

    The scattered pattern produced by the proteins within the phospholipid bilayer looks like a mosaic when viewed from above.

  • What are the four main components of the fluid mosaic model of membranes?

    • Phospholipids

    • Cholesterol

    • Glycoproteins and glycolipids

    • Transport proteins

  • Why do phospholipid bilayers act as a barrier to most water-soluble substances?

    The non-polar (hydrophobic) fatty acid tails form the core and prevent polar molecules or ions from passing across the membrane.

    This ensures water-soluble molecules such as sugars, amino acids and proteins cannot leak out of (or into) the cell.

  • How does cholesterol affect membrane fluidity at low and high temperatures?

    At low temperatures it increases fluidity by stopping the phospholipid tails packing too closely together.

    At high temperatures it stabilises the membrane by stopping it becoming too fluid.

  • Other than affecting fluidity, what does cholesterol do for the membrane?

    It increases the mechanical strength and stability of membranes (without it membranes would break down and cells would burst).

  • What are the roles of glycolipids and glycoproteins in the cell surface membrane?

    Their carbohydrate chains allow them to act as receptor molecules and as cell markers/antigens for cell-to-cell recognition.

    Receptor types include:

    • Signalling receptors for hormones and neurotransmitters

    • Receptors involved in endocytosis

    • Receptors involved in cell adhesion and stabilisation

  • What are the two types of transport protein?

    The two types are:

    • Channel (pore) proteins

    • Carrier proteins

    Each is specific to a particular ion or molecule.

  • How do transport proteins allow substances to cross the membrane?

    They create hydrophilic channels that allow ions and polar molecules to pass through.

    • Channel (pore) proteins form a hydrophilic channel

    • Carrier proteins change shape to move a substance across

  • True or False: In the fluid mosaic model, every protein is free to move and none are held in a fixed position.

    False — although many proteins move within the bilayer, some are fixed in position.

  • True or False: Cholesterol increases the membrane's permeability to ions.

    False — cholesterol decreases the membrane's permeability to ions.

  • Name two factors that affect the permeability of cell membranes.

    • Temperature

    • Solvent concentration

  • Explain how increasing temperature affects the lipids in a cell membrane and its permeability.

    As temperature increases, the lipids become more fluid.

    This reduces the membrane's effectiveness as a barrier to polar molecules, so they can pass through more easily.

  • Why does diffusion through a cell membrane occur faster at higher temperatures?

    Molecules have more kinetic energy, so any diffusion taking place through the membrane occurs at a higher speed.

  • Are changes in membrane fluidity caused by temperature reversible or irreversible?

    Reversible — if the temperature decreases again, the lipids return to their normal levels of fluidity.

  • What happens to membrane proteins at high temperatures (often around 40°C), and what effect does this have?

    Many proteins begin to denature.

    This disrupts the membrane structure so it no longer forms an effective barrier, and substances can pass freely through the disrupted membrane. This change is irreversible.

  • How do organic solvents increase cell membrane permeability?

    They dissolve the lipids in the membrane, causing it to lose its structure.

  • As temperature increases, the phospholipids in the cell membrane move more because they have more energy, so they are not as together, increasing membrane permeability.

    As temperature increases, the phospholipids in the cell membrane move more because they have more energy, so they are not as tightly packed together, increasing membrane permeability.

  • Why is beetroot used to investigate factors affecting membrane permeability?

    Beetroot cells contain a dark purple-red pigment.

    The higher the permeability of the beetroot cell membrane, the more of this pigment leaks out of the cell.

  • In the beetroot practical, why must the beetroot pieces be cut to equal sizes?

    Equal sizes ensure they have equal surface areas and volumes, which could otherwise affect the rate at which the pigment leaks out.

  • How is a colorimeter used to measure membrane permeability in the beetroot practical, and how are the results interpreted?

    A colorimeter measures how much light is absorbed as it passes through each sample of coloured liquid.

    The higher the absorbance, the more pigment was released, indicating a greater membrane permeability.

  • State the general pattern seen between temperature and beetroot membrane permeability.

    As temperature increases, membrane permeability also increases.

  • Explain how temperatures below 0°C can increase beetroot membrane permeability.

    • Channel or carrier proteins can deform at these low temperatures

    • Ice crystals that form can pierce the cell membrane, making it highly permeable (permeability is seen once the cells have thawed)

  • Give one limitation of using a colorimeter with cuvettes in the beetroot practical, and how to reduce its effect.

    Cuvettes may differ slightly in thickness, or be scratched, so a thicker or scratched cuvette absorbs slightly more light.

    Solution: use the same cuvette for every reading, or repeat the investigation and find a mean.

  • In the beetroot practical, why must the beetroot pieces be rinsed before the investigation?

    Rinsing removes any pigment released during cutting.

  • Explain why beetroot membrane permeability increases as temperature increases.

    The phospholipids gain more energy and move more, so they are less tightly packed.

    At high temperatures the bilayer may begin to melt and break down, and channel/carrier proteins deform, further increasing permeability.

  • True or False: changes in membrane fluidity caused by high temperature are always reversible.

    False — increased fluidity is reversible, but once proteins denature at high temperatures the change is irreversible.

  • True or False: organic solvents reduce cell membrane permeability.

    False — organic solvents increase permeability by dissolving the membrane lipids.

  • Colorimeter

    A machine that passes light through a liquid sample and measures how much of that light is absorbed.

  • Cuvette

    The small cuboid container that holds the liquid sample to be measured in a colorimeter.

  • Diffusion

    The net movement, as a result of the random motion of its molecules or ions, of a substance from a region of its higher concentration to a region of its lower concentration.

  • Facilitated diffusion

    The diffusion of substances across a membrane with the help of specific transport proteins (channel or carrier proteins), used by substances that cannot pass directly through the phospholipid bilayer.

  • In which direction do molecules or ions move during diffusion?

    Down a concentration gradient (from a region of higher concentration to a region of lower concentration).

  • What provides the energy for the random movement of molecules or ions during diffusion?

    The natural kinetic energy of the molecules or ions. Diffusion is a passive process and does not require metabolic energy (ATP).

  • What eventually happens to the distribution of molecules or ions as a result of diffusion?

    Given sufficient time, the molecules or ions reach an equilibrium, where they are evenly spread within a given volume of space.

  • State factors that affect the rate at which a substance diffuses across a membrane.

    • The steepness of the concentration gradient

    • The temperature

    • The surface area of the membrane

    • The diffusion distance (membrane thickness)

    • The size of the diffusing molecules or ions

  • Which types of substance cannot diffuse directly through the phospholipid bilayer and therefore require facilitated diffusion?

    • Large polar molecules, such as glucose and amino acids

    • Ions, such as sodium ions (Na⁺) and chloride ions (Cl⁻)

  • Which two types of protein enable facilitated diffusion?

    • Channel proteins

    • Carrier proteins

  • Describe how channel proteins allow facilitated diffusion.

    Channel proteins are water-filled pores that allow charged substances (e.g. ions) to diffuse across the membrane.

    Most are 'gated' — part of the protein on the inside surface of the membrane can move to open or close the pore, allowing the protein to control the exchange of ions.

  • Describe how carrier proteins carry out facilitated diffusion.

    Unlike channel proteins, carrier proteins can switch between two shapes.

    The binding site is first open to one side of the membrane, then open to the other side once the protein changes shape, moving the molecule across.

    The direction of net movement depends on the relative concentrations on each side — it occurs down the concentration gradient.

  • What is the key difference between simple diffusion and facilitated diffusion?

    Both involve net movement of substances down a concentration gradient.

    Facilitated diffusion requires the aid of a transport protein (e.g. because the substance is charged or too large to cross the phospholipid bilayer directly), whereas simple diffusion passes straight through the bilayer.

  • The two types of transport protein involved in facilitated diffusion are channel proteins and proteins.

    The two types of transport protein involved in facilitated diffusion are channel proteins and carrier proteins.

  • proteins are water-filled pores that are often 'gated' to control the exchange of ions.

    Channel proteins are water-filled pores that are often 'gated' to control the exchange of ions.

  • What key property do the transport proteins used in facilitated diffusion share?

    They are highly specific — each protein only allows one type of molecule or ion to pass through.

  • True or False: Diffusion requires ATP (metabolic energy).

    False — diffusion is a passive process, driven by the random kinetic energy of the molecules or ions.

  • True or False: Carrier proteins switch between two shapes to move molecules across the membrane.

    True — carrier proteins change shape to move the molecule across, whereas channel proteins are fixed water-filled pores.

  • Visking (dialysis) tubing

    A non-living, partially permeable membrane made from cellulose whose pores are small enough to stop large molecules passing but allow smaller molecules through by diffusion.

  • In the Visking tubing practical, why does glucose diffuse out of the tubing but starch does not?

    The pores are small enough to stop large molecules (starch and sucrose) passing through, but allow smaller molecules like glucose to diffuse out.

  • Describe how to set up a practical using Visking tubing to demonstrate the diffusion of glucose.

    • Fill a section of Visking tubing with a mixture of starch and glucose solutions

    • Suspend the tubing in a boiling tube of water for a set period of time

    • Test the water outside the tubing at regular intervals for starch and glucose

    • The results should show that glucose, but not starch, diffuses out

  • How can the effect of concentration gradient on the rate of diffusion be investigated quantitatively using Visking tubing?

    • Estimate the concentration of glucose that has diffused into the surrounding water at each time interval (separate boiling tubes per interval) using the semi-quantitative Benedict's test

    • Compare glucose concentrations between intervals using colour standards (from known glucose concentrations) or a colorimeter

    • Draw a graph of how the rate of diffusion changes with the concentration gradient between the inside and outside of the tubing

  • Which factor affecting the rate of diffusion is investigated using different sized cubes of agar?

    The effect of surface area to volume ratio, investigated by timing the diffusion of ions (acid) through different sized agar cubes.

  • Describe how to investigate the effect of surface area to volume ratio on the rate of diffusion using agar.

    • Cut coloured agar (made with Universal Indicator, sometimes with dilute sodium hydroxide) into cubes of different sizes

    • Place the cubes into boiling tubes containing a diffusion solution such as dilute hydrochloric acid

    • The acid should have a higher molarity than the sodium hydroxide so its diffusion shows as a colour change

    • Measure the time taken for the acid to change the indicator colour, or the distance travelled into the block in a given time

  • In the agar practical, why should the diffusing acid have a higher molarity than the sodium hydroxide used to make the agar?

    So that the acid's diffusion into the agar can be monitored by a colour change of the indicator (the acid overwhelms the alkali).

  • How are the timings from the agar diffusion practical converted into a rate of diffusion?

    Rate = 1 ÷ time taken. A graph can then be drawn showing how the rate of diffusion changes with the surface area to volume ratio of the agar cubes.

  • Explain why a larger agar cube changes colour more slowly than a smaller one.

    As a cube gets bigger, its volume increases faster than its surface area (volume is cubed, surface area is squared).

    With proportionately less surface area per unit volume, diffusion to the centre takes longer.

  • The greater the surface area to volume ratio, the the rate of diffusion.

    The greater the surface area to volume ratio, the faster the rate of diffusion.

  • can be added to make purple agar, allowing the diffusion of acid into the cube to be monitored by a colour change.

    Universal Indicator can be added to make purple agar, allowing the diffusion of acid into the cube to be monitored by a colour change.

  • Name two types of apparatus that can be used to investigate factors affecting the rate of diffusion.

    • Visking tubing (to investigate the effect of concentration gradient)

    • Cubes of agar (to investigate the effect of surface area to volume ratio)

  • True or False: In the Visking tubing practical, starch diffuses out of the tubing along with glucose.

    False — starch molecules are too large to fit through the pores, so only glucose diffuses out.

  • True or False: In the agar practical, the diffusing acid must have a higher molarity than the sodium hydroxide used to make the agar.

    True

  • Active transport

    The movement of molecules and ions through a cell membrane from a region of lower concentration to a region of higher concentration, using energy from respiration.

  • In which direction does active transport move molecules and ions relative to the concentration gradient?

    From a region of lower concentration to a region of higher concentration (i.e. against the concentration gradient).

  • What type of membrane protein is required for active transport?

    Carrier proteins.\n\nEach carrier protein is specific for a particular type of molecule or ion.

  • How does active transport differ from facilitated diffusion, given that both use carrier proteins?

    Active transport requires energy, whereas facilitated diffusion does not.\n\nThis allows active transport to move substances against the concentration gradient.

  • What is the energy in active transport used to do to the carrier protein?

    The energy is used to make the carrier protein change shape, allowing it to transfer the molecules or ions across the cell membrane.

  • Where does the energy for active transport come from?

    The energy is provided by ATP (adenosine triphosphate), produced during respiration.

  • The energy required for active transport is provided by ATP, which is to release energy.

    The energy required for active transport is provided by ATP, which is hydrolysed to release energy.

  • Why is it important to use the term 'carrier proteins' rather than 'channel proteins' when describing active transport?

    Carrier proteins undergo a conformational (shape) change to move substances across the membrane.\n\nChannel proteins do not change shape and are not used in active transport.

  • Give two roles of active transport in animals.

    • The reabsorption of useful molecules and ions into the blood after filtration into the kidney tubules\n\n- The absorption of some products of digestion from the digestive tract

  • Give two roles of active transport in plants.

    • The loading of sugar from the photosynthesising cells of leaves into the phloem tissue for transport around the plant\n\n- The loading of inorganic ions from the soil into root hairs

  • Each carrier protein used in active transport is for a particular type of molecule or ion.

    Each carrier protein used in active transport is specific for a particular type of molecule or ion.

  • How is the energy for active transport released from ATP?

    The ATP is hydrolysed to release the energy.

  • True or False: Active transport moves substances down the concentration gradient.

    False — active transport moves substances against the concentration gradient, from lower to higher concentration.

  • True or False: Active transport requires energy released from respiration.

    True

  • Endocytosis

    The process by which the cell surface membrane engulfs material, forming a small sac (an endocytic vacuole) around it, allowing bulk transport of larger quantities of material into the cell.

  • Exocytosis

    The process by which materials are transported out of cells, when secretory vesicles fuse with the cell surface membrane and release their contents outside the cell. It is the reverse of endocytosis.

  • Why is bulk transport (endocytosis and exocytosis) needed in addition to diffusion, osmosis and active transport?

    Diffusion, osmosis and active transport only move individual molecules or ions across the membrane.

    Bulk transport allows larger quantities of material to cross the membrane, such as:

    • Large molecules (e.g. proteins or polysaccharides)

    • Parts of cells

    • Whole cells (e.g. bacteria)

  • Why are endocytosis and exocytosis classed as forms of active transport?

    Both processes require energy.

    This energy is provided by ATP produced during respiration.

  • Phagocytosis

    A form of endocytosis involving the bulk intake of solid material by a cell. Cells specialising in this process are called phagocytes, and the vacuoles formed are called phagocytic vacuoles (e.g. the engulfing of bacteria by phagocytic white blood cells).

  • Pinocytosis

    A form of endocytosis involving the bulk intake of liquids by a cell. If the vesicle formed is extremely small, the process is called micropinocytosis.

  • What is the difference between phagocytosis and pinocytosis?

    • Phagocytosis = bulk intake of solid material

    • Pinocytosis = bulk intake of liquids

  • Describe how a secretory cell releases a substance by exocytosis.

    • The substance to be released is packaged into secretory vesicles formed from the Golgi body

    • These vesicles travel to the cell surface membrane

    • The vesicles fuse with the cell surface membrane

    • Their contents are released outside the cell

  • Give examples of substances that may be released from cells by exocytosis.

    • Enzymes (e.g. digestive enzymes secreted from pancreatic cells)

    • Hormones

    • Cell wall building materials

  • Bulk transport into cells is called endocytosis, whereas bulk transport out of cells is called .

    Bulk transport into cells is called endocytosis, whereas bulk transport out of cells is called exocytosis.

  • is the form of endocytosis in which a cell engulfs solid material, such as a phagocytic white blood cell engulfing bacteria.

    Phagocytosis is the form of endocytosis in which a cell engulfs solid material, such as a phagocytic white blood cell engulfing bacteria.

  • In an exam, why is it not enough to simply state 'bulk transport' when describing movement into or out of a cell?

    The examiner wants to know what type of bulk transport is occurring, so you must state the specific scientific name.

    • For transport out of the cell, state exocytosis

    • For transport into the cell, state endocytosis (or, better, phagocytosis, pinocytosis or micropinocytosis)

  • True or False: Endocytosis and exocytosis both require ATP.

    True — both are forms of active transport, using ATP produced during respiration.

  • True or False: Pinocytosis is the bulk intake of solid material by a cell.

    False — pinocytosis is the bulk intake of liquids; phagocytosis is the intake of solid material.

  • Osmosis

    The net movement of water from a region of higher water potential (dilute solution) to a region of lower water potential (concentrated solution), across a partially permeable membrane.

  • Water potential

    The tendency of water to move out of a solution. It is used to avoid confusion between water concentration and the concentration of a solution.

  • Partially permeable membrane

    A membrane that allows small molecules (such as water) through but not larger molecules (such as solute molecules).

  • In which direction does water move during osmosis, in terms of water potential?

    From a region of higher water potential to a region of lower water potential, through a partially permeable membrane.

  • How does the water potential of a dilute solution compare with that of a concentrated solution?

    • A dilute solution has a high water potential

    • A concentrated solution has a low water potential

  • What is the water potential of pure water at atmospheric pressure?

    0 kPa.

    Any solution containing solutes will have a water potential lower than 0 kPa (a negative value).

  • Explain why adding solutes to pure water gives the solution a negative water potential.

    Pure water has the highest water potential, defined as 0 kPa.

    Adding solutes lowers the water potential below that of pure water, so any solution with solutes has a negative water potential.

  • Which has the lower water potential: a solution with a water potential of -50 kPa or one of -200 kPa?

    The solution at -200 kPa has the lower water potential.

    The more negative the water potential, the lower it is (the further it is from pure water at 0 kPa).

  • Why are water molecules able to pass through the phospholipid bilayer of the cell membrane?

    Water molecules are small enough to pass between the phospholipids in the membrane.

    Although water molecules are polar, their small size still allows them to cross the bilayer.

  • Osmosis is the diffusion of water molecules across a membrane.

    Osmosis is the diffusion of water molecules across a partially permeable membrane.

  • describes the tendency of water to move out of a solution.

    Water potential describes the tendency of water to move out of a solution.

  • True or False: During osmosis, water moves from a region of lower water potential to a region of higher water potential.

    False — water moves from a region of higher water potential to a region of lower water potential.

  • True or False: Pure water at atmospheric pressure has a water potential of 0 kPa.

    True

  • Why are the effects of gaining or losing water by osmosis more severe in animal cells than in plant cells?

    Animal cells do not have a supporting cell wall (unlike plant cells), so there is nothing to withstand the pressure changes caused by water entering or leaving the cell.

  • Describe what happens to an animal cell placed in a solution with a lower water potential than the cell (e.g. a concentrated sucrose solution).

    Water leaves the cell through its partially permeable cell surface membrane by osmosis.

    The cell shrinks and shrivels up (becomes crenated), which is usually fatal for the cell.

  • Crenation

    The shrinking and shrivelling of an animal cell when it loses water by osmosis in a hypertonic environment (a solution with a higher solute concentration than the inside of the cell).

  • Describe what happens to an animal cell placed in pure water or a dilute solution.

    Water enters the cell by osmosis, because the surrounding solution has a higher water potential.

    The cell continues to gain water until the membrane is stretched too far and the cell bursts (cytolysis), as it has no cell wall to withstand the pressure. This is fatal for the cell.

  • Cytolysis (lysis)

    The bursting of an animal cell when it gains too much water by osmosis in a hypotonic environment (a solution with a lower solute concentration than the inside of the cell), because it has no cell wall to withstand the increased pressure.

  • What happens to an animal cell in an isotonic environment?

    The solution outside has the same solute concentration as the inside of the cell.

    Water moves into and out of the cell at the same rate (no net movement of water), so there is no change to the cell.

  • Describe what happens to a plant cell placed in a solution with a lower water potential than the cell.

    • Water leaves the cell by osmosis through the partially permeable cell surface membrane

    • As water leaves the vacuole, the volume of the cell decreases

    • The protoplast shrinks and pulls away from the cell wall

    • The cell becomes plasmolysed

  • Plasmolysis

    The process in which the protoplast of a plant cell shrinks and pulls away from the cell wall as water leaves the cell by osmosis in a solution with a lower water potential than the cell.

  • Describe what happens to a plant cell placed in pure water or a dilute solution.

    • Water enters the cell by osmosis, as the surrounding solution has a higher water potential

    • Water enters the vacuole, so the cell volume increases

    • The expanding protoplast pushes against the cell wall and pressure builds up

    • The inelastic cell wall prevents the cell from bursting and the cell becomes turgid

  • Turgid

    The state of a plant cell that is fully inflated with water and has become rigid and firm, because the protoplast pushes against the inelastic cell wall.

  • Animal cells do not plasmolyse; in a solution with a lower water potential than the cell, they instead .

    Animal cells do not plasmolyse; in a solution with a lower water potential than the cell, they instead shrink (become crenated).

  • Why is turgidity important for plants?

    When all the cells are firm (turgid), they provide support and strength, keeping the plant upright with its leaves held out to catch sunlight.

    If plants do not receive enough water, the cells cannot stay turgid and the plant wilts.

  • In terms of permeability, contrast the plant cell membrane with the plant cell wall.

    • The cell membrane is a phospholipid bilayer and is partially permeable (only certain molecules can cross)

    • The cell wall is made of cellulose and is freely (fully) permeable

  • True or False: Animal cells can become plasmolysed in a solution with a lower water potential than the cell.

    False — only plant cells plasmolyse; animal cells have no cell wall, so they shrink (become crenated) instead.

  • True or False: A plant cell placed in pure water bursts, just like an animal cell does.

    False — the inelastic cell wall prevents bursting, so the plant cell becomes turgid instead.

  • What is the aim of the potato cylinder osmosis practical?

    To investigate the effect of immersing plant tissue in solutions of different water potentials, and to use the results to estimate the water potential of the plant tissue itself.

  • Outline the method for investigating water potential using potato cylinders.

    • Cut potato cylinders to the same length (one per solution, or more for repeats)

    • Blot dry, then measure and record the initial mass of each

    • Place each cylinder into a sucrose solution of a different concentration (at least 5 concentrations, giving a range of water potentials)

    • Leave for a set time (e.g. 30 minutes), often in a water bath

    • Remove, dry off excess liquid, then measure and record the final mass and length

  • How is the percentage change in mass of each potato cylinder calculated?

    \text{percentage change in mass} = \frac{\text{change in mass}}{\text{initial mass}} \times 100

    The change in mass is divided by the initial mass and then multiplied by 100.

  • What does a positive percentage change in mass indicate about the solution's water potential?

    The potato has gained water by osmosis, so the solution had a higher water potential than the potato.

    The cells become turgid and the potato feels hard.

  • What does a negative percentage change in mass indicate about the solution's water potential?

    The potato has lost water by osmosis, so the solution had a lower water potential than the potato.

    The cells become flaccid and the potato feels floppy.

  • Why does the potato cylinder in the strongest sucrose concentration decrease in mass the most?

    There is the greatest concentration gradient between the potato cells (higher water potential) and the sucrose solution (lower water potential).

    So the most water moves out of the cells by osmosis, making them flaccid and reducing the cylinder's mass the most.

  • What does it mean if a potato cylinder shows no change in mass?

    There was no net movement of water into or out of the cells.

    The solution had the same water potential as the cytoplasm of the potato cells, so there was no concentration gradient.

  • How can the sucrose concentration inside the potato cylinders be estimated from a graph of percentage change in mass against sucrose concentration?

    It is the concentration at which the line of best fit crosses the x-axis (where the percentage change in mass is zero).

    At this point there is no net movement of water, so the water potential of the solution equals that of the potato cells.

  • Plasmolysis

    The process in which the protoplast (the living part of a plant cell) shrinks and pulls away from the cell wall as water leaves the cell by osmosis when it is placed in a solution of lower water potential.

  • Describe how plasmolysis occurs when a plant cell is placed in a solution with a lower water potential than the cell.

    • Water leaves the cell through the partially permeable cell surface membrane by osmosis

    • As water leaves the vacuole, the volume of the cell decreases

    • The protoplast gradually shrinks and stops exerting pressure on the cell wall

    • As it continues to shrink, the protoplast pulls away from the cell wall — the cell is now plasmolysed

  • In the onion epidermal strip practical, how is the degree of plasmolysis measured?

    Epidermal strips are placed in sucrose (or sodium chloride) solutions of decreasing water potential and viewed under a light microscope.

    The percentage of cells that have plasmolysed is then counted.

  • When potato cells gain water by osmosis they become , exerting turgor pressure on the cell walls so the potato feels hard.

    When potato cells gain water by osmosis they become turgid, exerting turgor pressure on the cell walls so the potato feels hard.

  • To find the percentage change in mass, divide the change in mass by the and then multiply by 100.

    To find the percentage change in mass, divide the change in mass by the initial mass and then multiply by 100.

  • In the onion epidermal strip practical, why are plants with coloured sap used?

    Plants with coloured sap (e.g. red onion, rhubarb, red cabbage) make the plasmolysed cells easier to see under the microscope.

  • True or False: A potato cylinder that increases in mass was placed in a solution with a lower water potential than the potato.

    False — an increase in mass means the solution had a higher water potential, so water moved into the potato by osmosis.

  • True or False: The sucrose concentration inside the potato is found where the line of best fit crosses the x-axis.

    True

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