Internal Resistance (Cambridge (CIE) AS Physics): Revision Note

Exam code: 9702

Ashika

Written by: Ashika

Reviewed by: Caroline Carroll

Updated on

Internal resistance

  • All power supplies have some resistance between their terminals

    • This is called internal resistance (r)

  • This internal resistance causes the charge circulating to dissipate some energy from the power supply itself

    • This is why the cell becomes warm after a period of time

  • The internal resistance therefore causes a loss of voltage or energy loss in a power supply

  • A cell can be thought of as a source of e.m.f with an internal resistance connected in series. This is shown in the circuit diagram below:

Circuit with e.m.f

Internal resistance circuit, downloadable AS & A Level Physics revision notes

Circuit showing the e.m.f and internal resistance of a power supply

 

  • VR is the terminal potential difference

    • This is the voltage available in the circuit itself

    • Terminal p.d = I × R (Ohm’s law)

  • When a load resistor is connected, current flows through the cell and a potential difference develops across the internal resistance. This voltage is not available to the rest of the circuit so is called the ‘lost volts’

  • Vr is the lost volts

    • This is the voltage lost in the cell due to internal resistance, so, from conservation of energy:

    • Lost volts = e.m.f − terminal p.d

    • Lost volts = I × r (Ohm’s law)

  • The e.m.f is the sum of these potential differences, giving the equation below:

thin space E equals space I R space plus thin space I r space equals space I open parentheses R space plus thin space r close parentheses

  • Where:

    • E = e.m.f (V)

    • I = current (A)

    • R = load resistance (Ω)

    • r = internal resistance (Ω)

  • IR is collectively known as the 'terminal potential difference'

  • Ir is collectively known as the 'lost volts'

Worked Example

A battery of e.m.f 7.3 V and internal resistance r of 0.3 Ω is connected in series with a resistor of resistance 9.5 Ω.

WE - internal resistance question image, downloadable AS & A Level Physics revision notes

Determine:

a) The current in the circuit

b) Lost volts from the battery

Answer:

a)

Step 1: List the known quantities:

  • E.m.f, E = 7.3 V

  • Load resistance, R = 9.5 Ω

  • Internal resistance, r = 0.3 Ω

Step 2: Use the e.m.f equation to determine the current I

E thin space equals space I open parentheses R space plus thin space r close parentheses

I space equals space fraction numerator space E over denominator R thin space plus thin space r end fraction

Step 3: Substitute the values

I space equals space fraction numerator 7.3 space over denominator 9.5 space plus thin space 0.3 end fraction space equals space 0.745 space equals space 0.7 space straight A

b)

Step 1: State the equation for lost volts

  • The lost volts are the voltage lost due to internal resistance

l o s t space v o l t s space equals space I r

Step 2: Substitute the values

0.7 space cross times space 0.3 space equals space 0.21 space equals space 0.2 space straight V

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Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.