Acceleration (College Board AP® Physics 1: Algebra-Based): Revision Note

Leander Oates

Written by: Leander Oates

Reviewed by: Caroline Carroll

Updated on

Average acceleration

Acceleration

  • Acceleration is defined as:

The rate of change in an object's velocity

  • Therefore, acceleration describes how an object's velocity changes over time

  • Any change in velocity is an acceleration

  • Velocity is a vector quantity with both magnitude and direction

  • Therefore, an acceleration can be:

    • a change in the magnitude of an object's velocity (its speed)

    • a change in direction

  • Acceleration itself is a vector quantity with both magnitude and direction

Average and instantaneous acceleration

  • Instantaneous acceleration is the acceleration of an object at a specific instant of time

  • Average acceleration describes a whole period of acceleration

    • For example, a train travels at a steady speed for most of its journey, but it accelerates as it leaves a station

  • Average acceleration considers the initial and final states of an object over an interval of time

  • In other words, the change in velocity over the time interval for which the acceleration occurred

aavg = vt

  • Where:

    • aavg = average acceleration, measured in m/s2

    • v = change in velocity, measured in m/s2

    • t = time interval, measured in s

  • If the train had an initial velocity of zero at the station, a final velocity of 50 meters per second in the positive direction, and the period of that acceleration was 60 seconds, then its average acceleration would be 0.83 meters per second squared

aavg = 5060 = 0.83 m/s2

  • Calculating the average acceleration over a very small time interval yields a value that is very close to the instantaneous acceleration

Negative acceleration

  • Since acceleration is a vector quantity, it can have a positive or negative value

  • The negative or positive value of acceleration does not always describe whether the object is speeding up or slowing down

    • The ± sign of a position value describes where the object is

    • The ± sign of a velocity value describes the direction in which the object is moving

    • The ± sign of an acceleration value only consistently describes the direction of the acceleration vector

Diagram showing force, velocity, and acceleration vectors for a ball thrown vertically at 0, 0.5, 1, 1.5, and 2 seconds. Arrows indicate direction.
When a ball is thrown vertically into the air, the only force acting on the ball is weight, therefore the acceleration is constant (if air resistance is ignored) even though the magnitude and direction of the velocity vector changes
  • When a ball is thrown vertically into the air, the only force acting on the ball is weight, the product of its mass and the acceleration due to gravity at Earth's surface

  • Neither the mass of the ball nor the acceleration due to gravity change during the ball's journey

  • The velocity, however, does change both in magnitude and direction

    • The direction of the initial motion is in an upward, positive direction

    • As the ball gains height, it loses speed, so the magnitude of its velocity decreases

    • At the instant that the ball changes direction, its speed is zero

    • As the ball falls, the direction of motion is in a downward, negative direction

    • As the ball loses height, it gains speed, so the magnitude of its velocity increases

  • The direction of the acceleration is constant in the downward, negative direction

  • The magnitude of the acceleration is constant (if air resistance is ignored)

  • This example highlights a case in which the ± sign of the acceleration value does not describe the speeding up and slowing down of the object

Worked Example

A car begins at rest and accelerates for 3.7 s at an average of 7.1 m/s2.

What speed does it reach during this time?

A: 26 m/s

B: 27 m/s

C: 28 m/s

D: 29 m/s

The correct answer is A

Answer:

Step 1: List the known quantities

  • Average acceleration, aavg = 7.1 m/s

  • Time interval, t = 3.7 s

  • Initial velocity, v0 = 0 m/s

Step 2: State the equation for average acceleration using initial velocity

aavg = vt = v  v0t

Step 3: Rearrange the equation to make final velocity the subject

v = v0 + aavgt

Step 4: Substitute in the known values to calculate

v = 0 + (7.1 · 3.7)

v = 26 m/s (2 s.f.)

  • This is answer A

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Leander Oates

Author: Leander Oates

Expertise: Development Editor

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.