Second Derivatives (AQA GCSE Further Maths): Revision Note

Exam code: 8365

Dan Finlay

Written by: Dan Finlay

Reviewed by: Lucy Kirkham

Updated on

Second derivatives

What is the second order derivative of a function?

  • If you differentiate the derivative of a function (i.e. differentiate the function a second time) you get the second order derivative of the function

    • The second order derivative can be referred to simply as the second derivative

  • We can write the second derivative as d2ydx2

  • Note the position of the powers of 2

    • differentiating twice (so d2) with respect to x twice (so x2)

  • A first derivative is the rate of change of a function (the gradient)

    • second order derivative is the rate of change of the rate of change of a function

      • i.e. the rate of change of the function’s gradient

    • A positive second derivative means the gradient is increasing

      • For instance in a u-shape, where the gradient is changing from negative to positive

    • A negative second derivative means the gradient is decreasing

      • For instance in an n-shape, where the gradient is changing from positive to negative

  • Second order derivatives can be used to test whether a point is a minimum or maximum

  • To find a second derivative, you simply differentiate twice!

    • It is important to write down your working with the correct notation, so you know what each expression means

    • For example

      • y=5x3+10x2

      • dydx=15x2+20x

      • d2ydx2=30x+20

Examiner Tips and Tricks

  • Even if you think you can find the second derivative in your head and write it down, make sure you write down the first derivative as well

    • If you make a mistake, you will most likely get marks for finding the first derivative

Worked Example

Work out d2ydx2 when

(a) y=x52x3+7x2+9x18

 Find the first derivative of the function first by considering each term in turn.

dydx= 5x4  6x2 + 14x + 9 

Find the second derivative, d2ydx2 by differentiating each term in the first derivative.

d2ydx2= 20x3  12x + 14

(b)y=3x+7x4

 To find the first derivative of the function, begin by separating the terms in the fraction.

y = 3xx4 + 7x4  

Rewrite each term using index notation so that they are in a form that can be differentiated. 

y = 3x(x4) + 7x4 = 3x3 + 7x4 

Find the first derivative of the function first by differentiating each term in turn.

dydx= 9x4  28x5 

Find the second derivative, d2ydx2 by differentiating each term in the first derivative.

d2ydx2= 9(4)x5  28(5)x6 = 36x5 + 140x6

You can turn the second derivative back into the same format as the original function by rewriting as a fraction.

d2ydx2= 36x5+ 140x6 = 36x + 140x6

d2ydx2= 36x + 140x6

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Dan Finlay

Author: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.

Lucy Kirkham

Reviewer: Lucy Kirkham

Expertise: Content Creator

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.