Kilowatt-Hours (Oxford AQA IGCSE Physics): Revision Note

Exam code: 9203

Dan Mitchell-Garnett

Written by: Dan Mitchell-Garnett

Reviewed by: Caroline Carroll

Updated on

Units of Energy

Energy measured in joules

  • Electrical energy transferred is often calculated with units of joules

    • One joule is equivalent to one-watt second

  • Consider an average lightbulb with a power of 60 W, which is left on for 6 hours in a house

    • 1 hour is 3600 s

    • The electrical energy transferred over this time is 1.296 × 106 J

  • This number is large and that is one lightbulb for a single day

    • A household uses many appliances all year round – the energy transferred per month in joules would be inconveniently large

Energy measured in kilowatt-hours

  • To make these large values more relatable to daily use:

    • Power can be measured in kilowatts (kW)

    • Time can be measured in hours (h)

  • In this case, energy has units of kilowatt-hours (kW h)

    • The lightbulb from before receives 3.6 kW h of energy over the 6 hours

    • This value is much easier to understand for consumers and energy providers – thinking in terms of hours of use is more practical than seconds

Kilowatt-Hours

  • As has been stated previously, the equation for energy transferred is:

E = P × t

  • But here we consider different units:

    • E = energy transferred measured in kilowatt-hours (kW h)

    • P = power of the appliance measured in kilowatts (kW)

    • t = time measured in hours (h)

  • The usual unit of energy is joules (J), which is one watt-second

  • To find the number of joules in 1 kW h, convert the power and time to watts and seconds

1 kW h = 1000 W × 3600 s = 3.6 × 106 J

  • 1000 watts multiplied by 3600 seconds is equal to 1000 multiplied by 3600, in watt-seconds

1000 W × 3600 s = 1000 × 3600 W s = 3.6 × 106 J

  • Therefore, 1 kWh = 3.6 × 106 J

  • To convert from kW h to J:

 E (kW h)  × (3.6 × 106) = E(J)

  • To convert from J to kW h:

E(J)  ÷ (3.6 × 106) = E(kW h)

  • The kW h is a large unit of energy, and is mostly used for energy in homes, businesses and factories

Worked Example

A cooker transfers 1.2 × 109 J of electrical energy to heat.

Calculate the cost of this if 1 kW h costs 14.2 p.

Here, 100 p = £1 (100 pence = 1 pound).

Answer:

Step 1: List the known quantities

  • Energy in joules, E (J) = 1.2 × 109 J

  • Cost per kW h = 14.2 p

Step 2: Convert from J to kW h

(1.2 × 109) ÷ (3.6 × 106) = 333.333 kW h

Step 3: Calculate the price

1 kW h = 14.2 p

333.333 × 14.2 = 4733 p = £47.33

Examiner Tips and Tricks

The equation for energy in kilowatt-hours, with the units of each variable, is given to you on your equation sheet.

You can either memorise the conversions between J and kW h or convert manually, but ensure you are confident in this conversion.

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Dan Mitchell-Garnett

Author: Dan Mitchell-Garnett

Expertise: Physics Content Creator

Dan graduated with a First-class Masters degree in Physics at Durham University, specialising in cell membrane biophysics. After being awarded an Institute of Physics Teacher Training Scholarship, Dan taught physics in secondary schools in the North of England before moving to Save My Exams. Here, he carries on his passion for writing challenging physics questions and helping young people learn to love physics.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.