Comparing Series & Parallel Circuits (AQA GCSE Combined Science: Trilogy: Physics): Revision Note
Exam code: 8464
Comparing Series & Parallel Circuits
Current in Series & Parallel
In a series circuit, the current is the same at all points
In a parallel circuit, the current splits at junctions – some of it going one way and the rest going the other
The total current from the supply is the sum of the currents in the branches
With identical components and the same supply, the total current is lower in a series circuit than in a parallel circuit, because the total resistance is greater

Diagram showing the behaviour of current in series and parallel circuits
Potential Difference in Series & Parallel
In a series circuit, the voltage of the power supply is shared between the components
In a parallel circuit, the voltage across each component is the same

Diagram showing the behaviour of voltage in series and parallel circuits
Resistors in Series & Parallel
In a series circuit, the total resistance is the sum of the resistance in each component
Two resistors in series will have a larger overall resistance than just one
This is because the charge has to push through multiple components when flowing around the circuit
The more components the charge has to travel through, the higher the number of collisions that occur
In a parallel circuit, the total resistance decreases and is less than the resistance of any of the individual components
Two resistors in parallel will have a smaller overall resistance than just one
This is because the charge has more than one pathway to take
For the same potential difference, more charge can flow each second, so the total current from the supply is larger
The more pathways there are, the larger the total current and the smaller the total resistance
Series and Parallel Circuit Summary Table

Worked Example
A circuit was set up as shown in the diagram.

Calculate the resistance of the bulb.
Answer:
Step 1: Determine the voltage across the bulb
The components share the potential difference of the power supply, so:
12 V – 8 V = 4 V
Step 2: Write down the equation for voltage, current and resistance
V = IR
Step 3: Calculate the current through the resistor
I = V / R = 8 / 6 = 1.33 A
Step 4: Calculate the resistance of the bulb
In a series circuit, the current is the same everywhere, so:
R = V / I = 4 / 1.33 = 3.0 Ω
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