Algebraic Roots & Indices (Edexcel IGCSE Maths A: Higher): Exam Questions

Exam code: 4MA1

2 hours49 questions
1
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1 mark

Simplify      (m2)5

2a
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1 mark

Simplify   m5 ÷ m3

2b
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2 marks

Simplify    5x4y3 × x2y

3a
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1 mark

Simplify    m5 × m3

3b
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1 mark

Simplify      p6p2

4a
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1 mark

Simplify      p2 × p5

4b
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1 mark

Simplify      g6 ÷ g4

4c
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1 mark

Simplify       (k3)2

5
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1 mark

Simplify    t8 ÷ t3

6a
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1 mark

Simplify      (t3)2

6b
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1 mark

Simplify     w9w4

7
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1 mark

Write down the value of g0

8
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1 mark

Simplify  e8÷e2

9
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1 mark

Simplify  (3x2 y)0

10
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1 mark

Simplify  x9x2

11
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1 mark

Simplify w1 × w0

Circle your answer.

1

0

w

w2

12
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1 mark

Given that y18 ÷ y6 = yk , find the value of k.

k = ...................

13
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1 mark

Simplify.

a6 ÷ a2

14
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1 mark

Simplify.

(b5)3

15
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1 mark

Simplify.

3y3y4

16a
1 mark

Simplify (b11)3

16b
2 marks

Simplify 5g2h3×6g3h7

1
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2 marks

Simplify     5u2w4 × 7uw3

2
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2 marks

Simplify     (9x8y3)12

3a
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1 mark

Simplify       a4 × a5

3b
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2 marks

Simplify           45e6f85ef2

3c
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1 mark

Write down the value of   912

4a
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1 mark

Simplify        x7 × x3

4b
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1 mark

Simplify       (m4)3

4c
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2 marks

Simplify    36af812a5f2

5
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2 marks

Simplify      (3x2y4)3

6a
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1 mark

Simplify      (p3)2

6b
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1 mark

Simplify     t8t3

6c
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1 mark

23 × 2n = 29

Work out the value of n.

6d
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1 mark

2x3 = 128

Work out the value of x.

7
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2 marks

Simplify fully    p3 × p4p2

8a
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2 marks

Solve     3x2 = 147

8b
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1 mark

Work out the value of 23

8c
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2 marks

Simplify    (3x2)3

8d
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2 marks

w = 4p  16

Make p the subject of this formula.

9
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2 marks

Simplify       2a3b × 5a2b3

10
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2 marks

Simplify fully    n7 × n3n6

11a
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1 mark

Simplify    m3 × m4

11b
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2 marks

Simplify     (5np3)3

11c
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2 marks

Simplify       32q9r44q3r

12
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2 marks

Simplify  (2x3y5 )4

13
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2 marks

Simplify   (16e10 f6 )12

14
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2 marks

Show that a5× (a3)2 can be expressed as a11.

15a
2 marks

Simplify (2c4d7)3

15b
1 mark

Find the value of 5y0 where y>0

16a
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1 mark

Simplify h15÷h3

16b
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2 marks

Simplify fully (2g3k5)4

16c
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2 marks

Given that y5×yny7=y12, work out the value of n.

1
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3 marks

1615 × 2x = 834

Work out the exact value of x.

2a
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1 mark

p3 × px = p9

Find the value of x.

2b
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1 mark

(72)y = 710

Find the value of y.

2c
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2 marks

100a × 1000b can be written in the form 10w

Show that w = 2a + 3b

3a
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1 mark

Simplify fully    (3e)0

3b
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2 marks

Simplify fully      (64x625y2)12

4
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2 marks

Given that  7206×7m7214=73

find the value of m

m = ................................................

5
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1 mark

Given that  (1x3)4=xm

find the value of m

m = .................................................

6
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2 marks

Given that  y5 × yny6=y13

work out the value of n.

n = ........................................... 

7
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1 mark

Simplify fully  (9t4w918t6w10)2

8
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4 marks

Given that  4k+3 = 16×2k

find the value of k.

Show your working clearly.

k = ..................................................

9
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3 marks

Simplify completely      (16w8y20)34

10
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4 marks

Given that  n(45)=(12)4 where n>0

find the value of n.

n = ..............................................

11
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1 mark

The nth term of a sequence is  4(2n + 2n1)

Circle the expression that is equivalent to 4(2n + 2n1)

2n+2 + 2n+1

22n + 22(n1)

8n + 8n1

2n+2 + 2n1

12
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3 marks

Simplify fully   a3b2cd×cab5

13
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2 marks

(arb)4=16r20  where a and b are positive integers.

Work out a and b

a=......................b=......................

14
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3 marks

Show that  (a3)13×(a2)12=1.

15
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3 marks

2÷831632=2n

Work out the value of n. Show your working clearly.

16a
2 marks

Simplify fully (32a15)35

16b
2 marks

Express (110x)3 in the form pxn where p and n are integers.

17a
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2 marks

27×45=4x

Calculate the value of x

17b
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2 marks

Simplify fully (125 p6 y24)23