Speed-Time Graphs (Cambridge (CIE) O Level Physics): Revision Note

Exam code: 5054

Ashika

Written by: Ashika

Reviewed by: Caroline Carroll

Updated on

Speed-Time Graphs

  • A speed-time graph shows how the speed of a moving object varies with time

    • The red line represents an object with increasing speed

    • The green line represents an object with decreasing speed

Increasing and decreasing speed

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Increasing and decreasing speed represented on a speed-time graph

Acceleration on a Speed-Time Graph

  • Speed-time graphs also show the following information:

    • If the object is moving with a constant acceleration or deceleration

    • The magnitude of the acceleration or deceleration

  • A straight line represents constant acceleration

  • The slope of the line represents the magnitude of acceleration

    • A steep slope means large acceleration (or deceleration) - i.e. the object's speed changes very quickly

    • A gentle slope means small acceleration (or deceleration) - i.e. the object's speed changes very gradually

    • A flat line means the acceleration is zero - i.e. the object is moving with a constant speed

Acceleration, deceleration and constant speed

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This image shows how to interpret the slope of a speed-time graph

Using Speed-Time Graphs

  • The distance travelled by an object can be found by determining the area beneath the graph

Area under a velocity-time graph

velocity-time-graphs-3, IGCSE & GCSE Chemistry revision notes

The distance travelled can be found from the area beneath the graph

 

  • If the area beneath the graph forms a triangle (the object is accelerating or decelerating) then the area can be determined using the formula:

 area = 12× base × height

  • If the area beneath the graph is a rectangle (constant velocity) then the area can be determined using the formula:

 area = base × height

Worked Example

The speed-time graph below shows a car journey which lasts for 160 seconds.

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Calculate the total distance travelled by the car on this journey.

Answer:

Step 1: Recall that the area under a velocity-time graph represents the distance travelled

  • In order to calculate the total distance travelled, the total area underneath the line must be determined

Step 2: Identify each enclosed area

  • In this example, there are five enclosed areas under the line

  • These can be labelled as areas 1, 2, 3, 4 and 5, as shown in the image below:

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Step 3: Calculate the area of each enclosed shape under the line

  • Area 1 = area of a triangle = ½ × base × height = ½ × 40 × 17.5 = 350 m

  • Area 2 = area of a rectangle = base × height = 30 × 17.5 = 525 m

  • Area 3 = area of a triangle = ½ × base × height = ½ × 20 × 7.5 = 75 m

  • Area 4 = area of a rectangle = base × height = 20 × 17.5 = 350 m

  • Area 5 = area of a triangle = ½ × base × height = ½ × 70 × 25 = 875 m

Step 4: Calculate the total distance travelled by finding the total area under the line

  • Add up each of the five areas enclosed:

total distance = 350 + 525 + 75 + 350 + 875

total distance = 2175 m

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Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.