Momentum & Impulse (Cambridge (CIE) O Level Physics): Revision Note

Exam code: 5054

Leander Oates

Written by: Leander Oates

Reviewed by: Caroline Carroll

Updated on

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Understand this topic with deeper explanations and understanding checks.

Momentum

  • An object with mass that is in motion has momentum which is defined by the equation:

momentum=mass×velocity

p=mv

  • Where:

    • p = momentum in kilogram metre per second (kg m/s)

    • m = mass in kilograms (kg)

    • v = velocity in metres per second (m/s)

  • This means that an object at rest (i.e v = 0) has no momentum

  • Momentum keeps an object moving in the same direction, making it difficult to change the direction of an object with a large momentum

  • Since velocity is a vector this means that the momentum of an object also depends on its direction of travel

  • This means that momentum can be either positive or negative

    • If an object travelling to the right has positive momentum, an object travelling in the opposite direction (to the left) will have negative momentum

Momentum of a Tennis Ball

A 60 g tennis ball moving at 2 m/s towards a wall, in the positive direction, has momentum p = 60 × 10⁻³ × 2 = 0.12 kg m/s. After bouncing back at 2 m/s in the opposite direction, its velocity is negative, so its momentum is p = 60 × 10⁻³ × −2 = −0.12 kg m/s

The tennis ball's momentum is negative when it moves in the opposite direction to which it initially was travelling in

  • Therefore, the momentum of an object will change if:

    • The object accelerates (speeds up) or decelerates (slows down)

    • Changes direction

    • Its mass changes

Worked Example

Which object has the most momentum?

A 60 g tennis ball hit by a racket and moving at 75 m/s, and a 3 kg brick moving at 1.5 m/s

Answer:

  • Momentum of tennis ball

p = mv

p = 0.06 × 75

p = 4.5 kg m/s

  • Momentum of brick

p = mv

p = 3 × 1.5

p = 4.5 kg m/s

  • Both the tennis ball and the brick have the same momentum

  • Even though the brick is much heavier than the ball, the ball is travelling much faster than the brick

  • This means that on impact, they would both exert a similar force (depending on the time it takes for each to come to rest)

Examiner Tips and Tricks

You can remember momentum as mass in motion. The units of momentum are kg m/s which is the product of the units of mass (kg) and velocity (m/s).

Which direction is taken as positive is completely up to you in the exam. In general, the right and upwards are taken as positive, and down or to the left as negative.

Conservation of Momentum

  • The principle of conservation of momentum states that:

In a closed system, the total momentum before an event is equal to the total momentum after the event

  • A closed system means there are no external forces (e.g. friction) acting on the system

  • In other words:

The total momentum before a collision = The total momentum after a collision

  • A system is a certain number of objects under consideration

    • This can be just one object or multiple objects

  • Since momentum is a vector quantity, a system of objects moving in opposite directions (e.g. towards each other) at the same speed will have an overall momentum of 0 since they will cancel out

    • Momentum is always conserved over time

  • The diagram below shows two masses m with velocity u and M at rest (ie. zero velocity)

Momentum of Masses Before and After a Collision

Before: mass m moving to the right with velocity u towards mass M at rest, with momentum = m × u. After: mass m moves to the left with velocity v and mass M moves to the right with velocity V, with momentum = M × V − m × v

The momentum of a system before and after a collision

  • Before the collision:

    • The momentum is only of mass m which is moving

    • If the right is taken as the positive direction, the total momentum of the system is m × u

  • After the collision:

    • Mass M also now has momentum

    • The velocity of m is now -v (since it is now travelling to the left) and the velocity of M is V

    • The total momentum is now the momentum of M + momentum of m

    • This is (M × V) + (m × -v) or (M × V) – (m × v)

Worked Example

The diagram shows a car and a van, just before and just after the car collided with the van, which is initially at rest.

Before the collision, a car of mass 990 kg moves at 10 m/s towards a van of mass 4200 kg at rest. After the collision, the car moves forward at 2 m/s and the van moves forward with an unknown velocity

Use the idea of conservation of momentum to calculate the velocity of the van when it is pushed forward by the collision.

Answer:

Step 1: State the principle of conservation of momentum

total momentum before=total momentum after

Step 2: Calculate the total momentum before the collision

p = mv

  • Momentum of the car

p = 990 × 10

p = 9900 kg m/s

  • Momentum of the van

    • The van is at rest

    • Therefore, v = 0 m/s

    • Therefore, p = 0 kg m/s

  • Total momentum before collision

pbefore=9900+0=9900 kg m/s

Step 3: Calculate the total momentum after the collision

  • Momentum of the car

p = 990 × 2

p = 1980 kg m/s

  • Momentum of the van

p = 4200 × v

  • Total momentum after collision

pafter=1980+4200v

Step 4: Rearrange the conservation of momentum equation to solve for v

pbefore=pafter

9900 = 1980 + 4200v

9900 − 1980 = 4200v

v = 9900 − 19804200

v = 1.9 m/s

Examiner Tips and Tricks

If it is not given in the question already, drawing a diagram of before and after helps keep track of all the masses and velocities (and directions) in the conservation of momentum questions.

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Leander Oates

Author: Leander Oates

Expertise: Development Editor

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.