Anomalous Readings (Edexcel International A Level (IAL) Physics): Revision Note
Exam code: YPH11
Anomalous Readings
Experimental errors (also known as operator errors or 'one-off' errors) will affect the results of an experiment and can produce anomalies
These anomalies should be identified during the evaluation of results and before drawing conclusions
Anomalies can be identified by looking for results or data points on a graph that do not fit with the trend or with other repeat readings carried out during the experiment
These anomalous results will show a much larger difference from the mean than the rest of the results — there is no fixed percentage test
A value is anomalous only when the gap between it and the other readings is much larger than the spread of those readings among themselves
If that spread can be explained by how the measurement was taken, e.g. hand-timed values that differ by less than a typical reaction time of about 0.2 s, there is no anomaly, and every value goes into the mean
The results or ‘data’ collected from an experiment can be made more precise if the experiment is repeated several times and anomalies are removed
This, in turn, allows more valid conclusions to be drawn
Anomalous results are always inconsistent with other readings, e.g., a point that is not on the line of best fit of a graph

Identifying an anomalous result from a graph
If an anomaly occurs in the experiment:
Exclude this value when calculating the mean
Repeat this measurement
Note: In the exam, only leave a value out of the mean when it is clearly anomalous — otherwise you should use all the tabulated readings
Worked Example
A student achieves a set of repeat readings for the current through a bulb.
2.5 mA | 2.8 mA | 6.1 mA | 2.0 mA | 2.3 mA |
Calculate the mean current through the bulb.
Answer:
Step 1: Identify the anomalous result
The only result that doesn't fit with the rest of the data is 6.1 mA
It is more than twice any of the other readings, which all lie within 0.8 mA of each other, so it is clearly anomalous and is left out of the mean
Step 2: Calculate the mean current
Mean current = = 2.4 mA
Examiner Tips and Tricks
When calculating a mean from repeat readings given in the practical paper, you are not expected to identify and remove anomalous values — the mark schemes state this explicitly, and a mean calculated using all the tabulated readings is credited. Do not discard a reading unless there is clear evidence it is anomalous; wrongly excluding a genuine reading can cost the calculation mark. If you suspect an anomaly in your own practical work, either repeat that measurement or report it in your write up of the investigation rather than discarding it without acknowledgment.
Unlock more, it's free!
Was this revision note helpful?
Build on this topic