Anomalous Readings (Edexcel International A Level (IAL) Physics): Revision Note

Exam code: YPH11

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

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Anomalous Readings

  • Experimental errors (also known as operator errors or 'one-off' errors) will affect the results of an experiment and can produce anomalies

    • These anomalies should be identified during the evaluation of results and before drawing conclusions

  • Anomalies can be identified by looking for results or data points on a graph that do not fit with the trend or with other repeat readings carried out during the experiment

    • These anomalous results will show a much larger difference from the mean than the rest of the results — there is no fixed percentage test

    • A value is anomalous only when the gap between it and the other readings is much larger than the spread of those readings among themselves

    • If that spread can be explained by how the measurement was taken, e.g. hand-timed values that differ by less than a typical reaction time of about 0.2 s, there is no anomaly, and every value goes into the mean

  • The results or ‘data’ collected from an experiment can be made more precise if the experiment is repeated several times and anomalies are removed

    • This, in turn, allows more valid conclusions to be drawn

  • Anomalous results are always inconsistent with other readings, e.g., a point that is not on the line of best fit of a graph

Scatter graph with a line of best fit and one point lying clearly off the line, marked as the anomalous result

Identifying an anomalous result from a graph

  • If an anomaly occurs in the experiment:

    • Exclude this value when calculating the mean

    • Repeat this measurement

  • Note: In the exam, only leave a value out of the mean when it is clearly anomalous — otherwise you should use all the tabulated readings

Worked Example

A student achieves a set of repeat readings for the current through a bulb.

2.5 mA

2.8 mA

6.1 mA

2.0 mA

2.3 mA

Calculate the mean current through the bulb.

Answer:

Step 1: Identify the anomalous result

  • The only result that doesn't fit with the rest of the data is 6.1 mA

  • It is more than twice any of the other readings, which all lie within 0.8 mA of each other, so it is clearly anomalous and is left out of the mean

Step 2: Calculate the mean current

Mean current = 2.5 + 2.8 + 2.0 + 2.34  = 2.4 mA

Examiner Tips and Tricks

When calculating a mean from repeat readings given in the practical paper, you are not expected to identify and remove anomalous values — the mark schemes state this explicitly, and a mean calculated using all the tabulated readings is credited. Do not discard a reading unless there is clear evidence it is anomalous; wrongly excluding a genuine reading can cost the calculation mark. If you suspect an anomaly in your own practical work, either repeat that measurement or report it in your write up of the investigation rather than discarding it without acknowledgment.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.