Polynomial Inequalities (DP IB Analysis & Approaches (AA)): Revision Note

Lucy Kirkham

Written by: Lucy Kirkham

Reviewed by: Mark Curtis

Updated on

Polynomial inequalities

What is a polynomial inequality?

  • A polynomial inequality is an inequality where both sides are polynomials

    • i.e. have constant terms or positive integer powers of x

      • e.g. x to the power of 4 minus x squared greater than x plus 6

  • The following are not polynomial inequalities

    • square root of x greater than 4

    • 1 over x greater or equal than 3 x

      • x to the power of 1 half end exponent and x to the power of negative 1 end exponent are not positive integer powers

How do I solve polynomial inequalities?

  • STEP 1
    Rearrange the inequality so that one of the sides is equal to zero

    • For example: P open parentheses x close parentheses less or equal than 0

  • STEP 2
    Find the roots of the polynomial

    • You can do this by

      • factorising

      • or using your GDC to solve P open parentheses x close parentheses equals 0

  • STEP 3
    Choose one of the following methods:

  • Graph method

    • Sketch a graph of the polynomial

      • with or without a GDC

    • Choose the intervals (ranges) of x corresponding to the sections of the graph that satisfy the inequality

      • For P open parentheses x close parentheses less or equal than 0 you want sections below the x-axis

      • For P open parentheses x close parentheses greater or equal than 0 you want sections above the x-axis

  • Sign table method

    • If you are unsure how to sketch a polynomial graph then this method is best

    • Split the real numbers into the possible intervals using the roots

      • e.g. for two roots a and b the intervals are x less than a, a less than x less than b and x greater than b

    • Choose a numerical value from each interval

    • Substitute the numerical values into the original inequality (e.g. P open parentheses x close parentheses less or equal than 0 or P open parentheses x close parentheses greater or equal than 0) to see if it is true

      • The solutions are the intervals in which it is true

  • Alternatively if the polynomial is factorised you can determine the sign of each factor in each interval

    • e.g. for open parentheses x minus 2 close parentheses open parentheses x minus 4 close parentheses open parentheses x minus 6 close parentheses greater than 0 the intervals are x less than 2, 2 less than x less than 4, 4 less than x less than 6 and x greater than 6

    • For x less than 2, the expression open parentheses x minus 2 close parentheses open parentheses x minus 4 close parentheses open parentheses x minus 6 close parentheses is

      • negative × negative × negative = negative

      • so open parentheses x minus 2 close parentheses open parentheses x minus 4 close parentheses open parentheses x minus 6 close parentheses greater than 0 is not true for x less than 2

    • Repeat this for the other intervals

      • The solution will be the intervals in which it is true

Examiner Tips and Tricks

In the exam, most solutions will be intervals, but some could be a single point if the graph only touches the x-axis, e.g. solving left parenthesis x minus 3 right parenthesis squared less or equal than 0 gives x equals 3 only.

Worked Example

Solve the inequality x cubed plus 2 x squared greater than x plus 2 using an algebraic method.

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Lucy Kirkham

Author: Lucy Kirkham

Expertise: Head of Content Creation

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.

Mark Curtis

Reviewer: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.