Ar & Mr (Cambridge (CIE) O Level Chemistry): Revision Note

Exam code: 5070

Caroline Carroll

Written by: Caroline Carroll

Reviewed by: Lucy Kirkham

Updated on

Relative Masses

Relative Atomic Mass

  • The symbol for the relative atomic mass is Ar

  • The relative atomic mass for each element can be found in the Periodic Table along with the atomic number

  • The relative atomic mass is shown underneath the atomic symbol and is larger than the atomic number (except for hydrogen where they are the same)

  • Atoms are too small to accurately weigh but scientists needed a way to compare the masses of atoms 

  • The carbon-12 is used as the standard atom and has a fixed mass of 12 units 

  • The masses of all other atoms are compared against this atom

  • Relative atomic mass (Ar) can therefore be defined as:

    • The average mass of the isotopes of an element compared to 1/12th of the mass of an atom of 12C 

  • The relative atomic mass of carbon is 12

    • The relative atomic mass of magnesium is 24 which means that magnesium is twice as heavy as carbon 

    • The relative atomic mass of hydrogen is 1 which means it has one twelfth the mass of one carbon-12 atom 

Relative molecular (formula) mass

  • The symbol for the relative molecular mass is Mr and it refers to the total mass of the molecule

    • The symbol Mr is used for both

      • Relative molecular mass and relative formula mass are the same quantity, and only the name changes with the type of substance

    • Both Ar and Mr are ratios, so they never carry a unit

  • To calculate the Mr of a substance, you have to add up the relative atomic masses of all the atoms present in the formula

  • Relative formula mass is used when referring to the total mass of an ionic compound

Relative Formula Mass Calculations Table

Substance

Atoms present

Mr

Hydrogen (H2)

2 x H

(2 x 1) = 2

Water (H2O)

(2 x H) + (1 x O)

(2 x 1) + 16 = 18

Potassium carbonate (K2CO3)

(2 x K) + (1 x C) + (3 x O)

(2 x 39) + 12 + (3 x 16) = 138

Calcium hydroxide (Ca(OH)2)

(1 x Ca) + (2 x O) + (2 x H)

40 + (2 x 16) + (2 x 1) = 74

Ammonium sulfate ((NH4)2SO4)

(2 x N) + (8 x H) + (1 x S) + (4 x O)

(2 x 14) + (8 x 1) + 32 + (4 x 16) = 132

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Caroline Carroll

Author: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.

Lucy Kirkham

Reviewer: Lucy Kirkham

Expertise: Content Creator

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.