Manipulating Logarithmic Functions (College Board AP® Precalculus): Revision Note

Roger B

Written by: Roger B

Reviewed by: Mark Curtis

Updated on

Properties of logarithms

What is the product property for logarithms?

  • The product property for logarithms states that

    • logb(xy)=logbx+logby

      • The logarithm of a product equals the sum of the logarithms

    • This works in reverse too: a sum of logarithms (with the same base) can be combined into a single logarithm of a product

      • E.g. log34+log37=log3(4·7)=log328

  • There is also a corresponding quotient property

    • logb(xy)=logbxlogby

      • The logarithm of a quotient equals the difference of the logarithms

    • This also works in reverse, to combine a difference of logarithms

      • E.g. ln15ln3=ln153=ln5

  • The product property has an important graphical implication

    • Every horizontal dilation of a logarithmic function,  f(x)=logb(kx)

    • is equivalent to a vertical translation

    • because logb(kx)=logbk+logbx

      • The constant logbk acts as a vertical shift of logbx

What is the power property for logarithms?

  • The power property for logarithms states that

    • logb(xn)=nlogbx

      • An exponent inside a logarithm can be brought out as a multiplier in front

      • E.g. log5(x2)=2log5x

    • This works in reverse too: a coefficient in front of a logarithm can be moved inside as an exponent

      • E.g. 3log2x=log2(x3)

      • E.g. 12lnx=ln(x1/2)=lnx

  • This also has an important graphical implication

    • Raising the input of a logarithmic function to a power,  f(x)=logb(xk)

    • is equivalent to a vertical dilation by a factor of k

    • because logb(xk)=klogbx

What is the change of base property?

  • The change of base property for logarithms states that

    • logbx=logaxlogab

      • where a>0 and a1

  • This allows you to convert a logarithm from one base to another

    • E.g. log512=ln12ln5=log12log5

    • You can use any base for the conversion

      • e and 10 are both commonly-used 'standard' bases

  • An important graphical implication of this is that all logarithmic functions are vertical dilations of each other

    • Since logbx=1logab·logax

      • the function logbx is just a constant multiple of logax

    • This means changing the base of a logarithmic function only stretches or compresses the graph vertically

      • It doesn't change the overall shape

How do you use these properties to rewrite expressions?

  • On the exam, you are frequently asked to combine multiple logarithmic terms into a single logarithm

    • or to expand a single logarithm into multiple terms

  • For combining (multiple terms → single logarithm):

    • First use the power property to move any coefficients inside as exponents

      • E.g.  2log3x+log353log3y=log3(x2)+log35log3(y3)

    • Then use the product property (for addition) and quotient property (for subtraction) to combine into one logarithm

      • =log3(5x2)log3(y3) 

      • =log3(5x2y3) 

  • When combining terms, make sure all logarithms have the same base before applying the product or quotient properties

    • If the bases differ, use the change of base property first

  • For expanding (single logarithm → multiple terms):

    • Apply the product/quotient/power properties in reverse

    • E.g.  log2(x3yz)=log2(x3)+log2(y)log2z=3log2x+12log2ylog2z

Examiner Tips and Tricks

A common error with these types of questions is applying the power property incorrectly

  • Remember,  logb(xn)=nlogbx

  • but  (logbx)nnlogbx

The exponent must be on the input, not on the whole logarithm.

Show every step clearly, both to assure you score all possible points, but also to help you avoid errors.

Worked Example

The function  j is given by  j(x)=5log5x+log5(3x)2log5(x2).

Rewrite  j(x) as a single logarithm of the form log5(expression).

Answer:

First apply the power property to move the coefficients inside

 j(x)=5log5x+log5(3x)2log5(x2)=log5(x5)+log5(3x)log5((x2)2)=log5(x5)+log5(3x)log5(x4)

Then use the product property to combine the first two terms

=log5(x5·3x)log5(x4)=log5(3x6)log5(x4)

  • and the quotient property to combine into a single logarithm

=log5(3x6x4) 

Simplify by cancelling common factors

 j(x)=log5(3x2)

Worked Example

Let a, b, and c be positive constants. Which of the following is equivalent to log10(a2cb3)?

(A)  log10(a2+c)log10(3b)

(B)  12log10a+log10c13log10b

(C)  2log10alog10c+3log10b

(D)  2log10a+log10c3log10b

Answer:

You could try combining the terms in all the answer options, to see which one is equal to log10(a2cb3)

  • But it is quicker to expand log10(a2cb3) into separate terms

First use the quotient property

log10(a2cb3)=log10(a2c)log10(b3)

Then use the product property

=log10(a2)+log10clog10(b3)

Then use the power property to bring the powers out front as multipliers

=2log10a+log10c3log10b

That is option (D)

(D) 2log10a+log10c3log10b

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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Mark Curtis

Reviewer: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.