Stoke's Law (DP IB Physics: SL): Revision Note

Ashika

Written by: Ashika

Reviewed by: Caroline Carroll

Updated on

Stoke's Law

Viscous drag

  • Viscous drag is defined as:

The frictional force between an object and a fluid which opposes the motion between the object and the fluid

  • In air, the drag force is air resistance

Stoke's law equation

  • Viscous drag force can be calculated using Stoke’s law equation:

Fd = 6πηrv

  • Where

    • Fd = viscous drag force (N)

    • η = fluid viscosity (N s m−2 or Pa s)

    • r = radius of the sphere (m)

    • v = velocity of the sphere through the fluid (ms−1)

1-2-9-stokes-law

A sphere travelling through air will experience a drag force that depends on its radius, velocity and the viscosity of the fluid

  • The viscosity of a fluid can be thought of as its thickness, or how much it resists flowing

    • Fluids with low viscosity are easy to pour, while those with high viscosity are difficult to pour

4-3-viscous-drag-water-ketchup_edexcel-al-physics-rn

Water has a lower viscosity than ketchup as it is easier to pour and flow

  • The coefficient of viscosity is a property of the fluid (at a given temperature) that indicates how much it will resist flow

    • The rate of flow of a fluid is inversely proportional to the coefficient of viscosity

  • The size of the force depends on the:

    • Speed of the object

    • Size of the object

    • Shape of the object

Worked Example

A spherical stone of volume 2.7 × 10–4 m3 falls through the air and experiences a drag force of 3 mN at a particular instant. Air has a viscosity of 1.81 × 10-5 Pa s. Calculate the speed of the stone at that instant.

Answer:

Step 1: List the known quantities

  • Volume of stone, V = 2.7 × 10–4 m3

  • Drag force, Fd = 3 mN = 3 × 10–3 N

  • Viscosity of air, η = 1.81 × 10-5 Pa s

Step 2: Calculate the radius of the sphere, r

  • The volume of a sphere is

V =43πr3

  • Therefore, the radius, r is:

r = 3V4π3 = 3 × (2.7 × 104) 4π3 = 0.04 m

Step 3: Rearrange the Stoke's law equation for the velocity, v

Fd = 6πηrv

v =  Fd 6πηr

Step 4: Substitute in the known values

v = 3 × 103 6π × (1.81 × 105) × 0.04 =  220 m s1

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Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.