Time Period of a Simple Pendulum (DP IB Physics: SL): Revision Note

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Updated on

Time Period of a Simple Pendulum

  • A simple pendulum consists of a string and a bob at the end

    • The bob is a weight, generally spherical and considered a point mass

    • The bob moves from side to side

    • The string is light and inextensible remaining in tension throughout the oscillations

    • The string is attached to a fixed point above the equilibrium position

  • The time period of a simple pendulum for small angles of oscillation is given by:

T = 2πLg

  • Where:

    • T = time period (s)

    • L = length of string (from the pivot to the centre of mass of the bob) (m)

    • g = gravitational field strength (N kg-1)

A simple pendulum

  • The time period of a pendulum depends on gravitational field strength

    • Therefore, the time for a pendulum to complete one oscillation would be different on the Earth and the Moon

Small Angle Approximation

  • This formula for time period is limited to small angles (θ < 10°) and therefore small amplitudes of oscillation from the equilibrium point

  • The restoring force of a pendulum is equal to the component of weight acting along the arc of the circle towards the equilibrium position

    • It is assumed to act at an angle θ to the horizontal

    • Using the small angle approximation: sin θθ 

9-1-4-pendulum-resolved-forces-v2

Forces on a pendulum when it is displaced. Assuming θ < 10°, the small angle approximation can be used to describe the time period of a simple pendulum

Worked Example

A swinging pendulum with a length of 80.0 cm has a maximum angle of displacement of 8°.

Determine the angular frequency of the oscillation.

Answer:

Step 1: List the known quantities

  • Length of the pendulum, L = 80 cm = 0.8 m

  • Acceleration due to gravity, g = 9.81 m s−2

Step 2: Write down the relationship between angular frequency, ω, and period, T

T = 2πω

Step 3: Write down the equation for the time period of a simple pendulum

T = 2πLg

  • This equation is valid for this scenario since the maximum angle of displacement is less than 10°

Step 4: Equate the two equations and rearrange for ω

2πω = 2πLg          ω = gL

Step 5: Substitute the values to calculate ω

ω = 9.810.8= 3.50 rad s−1

Angular frequency:  ω = 3.5 rad s−1

  • Note: angular frequency ω is also known as angular speed or velocity

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.