Young’s Double-Slit Experiment (DP IB Physics: SL): Revision Note

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Reviewed by: Caroline Carroll

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Young's Double Slit Experiment

  • Young's double-slit experiment produces a diffraction and an interference pattern using either:

    • The interference of two coherent wave sources 

    • A single wave source passing through a double slit

  • Lasers are the most common sources used in Young's double slit experiment because the waves must be:

    • Coherent (have a constant phase difference and frequency)

    • Monochromatic (have the same wavelength)

  • In this typical set up for Young's double slit experiment:

    • The light source is placed behind the single slit

    • The light is then diffracted to produce two sources in the double slit at A and B

    • The light from the double slits is then diffracted, producing a diffraction pattern made up of bright and dark fringes on a screen

A laser light source shines through a single slit and then a double slit with openings A and B; the diffracted light from slits A and B spreads out and overlaps to form an interference pattern

The typical arrangement of Young's double slit experiment

Diffraction Pattern

  • The diffraction pattern from the interference of the two sources can be seen on the screen when it is placed far away

    • Constructive interference between light rays forms bright strips, also called fringes, interference fringes or maxima, on the screen

    • Destructive interference forms dark strips, also called dark fringes or minima, on the screen

Light from a monochromatic source passes through a single slit and then a double slit (A and B) and produces a pattern of alternating bright and dark fringes on a screen

Young's double slit experiment and the resulting diffraction pattern

  • In the ideal two-source model, each bright fringe has the same width and intensity

Wavefronts of coherent light pass through two slits; crests and troughs from the two slits overlap, giving alternating bright and dark fringes on the screen where they meet in phase and in antiphase

The constructive and destructive interference of laser light through a double slit creates bright and dark strips called fringes on a screen placed far away

Interference Pattern

  • The Young's double slit interference pattern shows the regions of constructive and destructive interference:

    • In the ideal two-source model, each bright fringe is a peak of equal maximum intensity

    • Each dark fringe is a trough or minimum of zero intensity

  • The maxima are formed by the constructive interference of light

  • The minima are formed by the destructive interference of light

Waves from slits S₁ and S₂ meet at a screen, with the path difference marked; the intensity pattern on the screen shows maxima at n = 0 (central), n = 1 and n = 2 on each side, with minima between them

The interference pattern of Young's double slit diffraction of light

  • When two waves interfere, the resultant wave depends on the path difference between the two waves

  • The wave from slit S2 has to travel slightly further than that from S1 to reach the same point on the screen

    • This extra distance is the path difference

Rays from slits S₁ and S₂ meet at a point on the screen, with the extra distance travelled from S₂ marked as the path difference; constructive interference: path difference = nλ; destructive interference: path difference = (n + ½)λ, where n = 0, 1, 2, 3…

The path difference between two waves is determined by the number of wavelengths that cover their difference in length

  • Remember the conditions for interference as explained in the previous revision note on double source interference

    • For constructive interference (or maxima):

path difference = nλ

  • For destructive interference (or minima):

path difference = (n + 12)λ

  • For the maxima in the interference pattern: 

    • There is usually more than one produced

    • n is the order of the maxima or minima; which represents the position of the maxima away from the central maximum

    • n = 0 is the central maximum

    • n = 1 represents the first maximum on either side of the central, n = 2 the next one along....

Double Slit Equation

  • The spacing between the bright or dark fringes in the diffraction pattern formed on the screen can be calculated using the double-slit equation:

s = λDd

  • Where:

    • s = separation between successive fringes on the screen (m)

    • λ = wavelength of the waves incident on the slits (m)

    • D = distance between the screen and the slits (m)

    • d = separation between the slits (m)

Double slit diagram: the slit separation d, the distance D from the slits to the screen and the fringe spacing w between neighbouring bright fringes, with the intensity pattern drawn beside the screen

Double slit interference equation with w, d and D represented on a diagram

  • The above equation shows that the separation between the fringes, s will increase if:

    • The wavelength of the incident light increases

    • The distance between the screen and the slits increases

    • The separation between the slits decreases

Worked Example

Two coherent sources of sound waves S1 and S2 are situated 65 cm apart in air as shown below.

Two sound sources S₁ and S₂ are 65 cm apart; a microphone M is 150 cm from S₁ along the line at right angles to S₁S₂

The two sources vibrate in phase but have different amplitudes of vibration. A microphone M is situated 150 cm from S1 along the line normal to S1. The microphone detects maxima and minima of the intensity of the sound. The wavelength of the sound from S1 to S2 is decreased by increasing the frequency.

Determine which orders of maxima are detected at M as the wavelength is increased from 3.5 cm to 12.5 cm.

Answer:

Worked solution: by Pythagoras, distance S₂M = √(65² + 150²) = 163 cm, so path difference = 163 − 150 = 13 cm; maxima are caused by constructive interference, path difference = nλ, so λ = 13/n: n = 1 gives 13 cm, n = 2 gives 6.5 cm, n = 3 gives 4.3 cm, n = 4 gives 3.3 cm; only n = 2 and n = 3 (6.5 cm and 4.3 cm) are within the range, so these maxima are detected

Worked Example

A laser is placed in front of a double-slit as shown in the diagram below.

A laser shines on a double slit 4.5 m from a screen; on the screen, bright fringes P and Q are 15 mm apart

The laser emits light of frequency 750 THz. The separation of the maxima P and Q observed on the screen is 15 mm. The distance between the double slit and the screen is 4.5 m.

Calculate the separation of the two slits.

Answer:

Worked solution: v = fλ, so λ = 3 × 10⁸ / 750 × 10¹² = 4 × 10⁻⁷ m = 400 nm; fringe spacing w = λD/s, so slit separation s = λD/w = (4 × 10⁻⁷ × 4.5) / (15 × 10⁻³ ÷ 9) = 1.08 × 10⁻³ m = 1.1 mm (2 s.f.), where 9 is the number of fringe spacings between P and Q

Examiner Tips and Tricks

The path difference is more specifically how much longer, or shorter, one path is than the other. In other words, the difference in the distances. Make sure not to confuse this with the distance between the two paths.

Since d, s and D are all distances, it's easy to mix up which they refer to. Labelling the double-slit diagram as shown in the notes above will help to remember the order i.e. d and s in the numerator and D underneath in the denominator.

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Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.