Stefan-Boltzmann Law (DP IB Physics: SL): Revision Note

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Updated on

Stefan-Boltzmann Law

  • The total power P radiated by a perfect black body depends on two factors:

    • Its absolute temperature

    • Its surface area

  • The relationship between these is known as Stefan's Law or the Stefan-Boltzmann Law, which states:

The total energy emitted by a black body per unit area per second is proportional to the fourth power of the absolute temperature of the body

  • The Stefan-Boltzmann Law can be calculated using:

P = σAT4

  • Where:

    • P = total power emitted across all wavelengths (W)

    • σ = the Stefan-Boltzmann constant

    • A = surface area of the body (m2)

    • T = absolute temperature of the body (K)

  • The Stefan-Boltzmann law is often used to calculate the luminosity of celestial objects, such as stars

    • Stars can be approximated as black bodies, as almost all radiation incident on a star is absorbed

    • The power emitted across all wavelengths, P, for a star is just its luminosity, L

  • The surface area of a star (or other spherical object) is equal to A = r2

    • Where r = radius of the star (m)

  • Substituting the above for area, A, the Stefan-Boltzmann equation then becomes:

L = 4πr2σT4

  • Where:

    • L = luminosity of the star (W)

    • r = radius of the star (m)

    • σ = the Stefan-Boltzmann constant

    • T = surface temperature of the star (K)

Worked Example

The surface temperature of Proxima Centauri, the nearest star to Earth, is 3000 K and its luminosity is 6.506 × 1023 W.

Calculate the radius of Proxima Centauri in solar radii. 

Solar radius R = 6.96 × 108 m

Answer:

Step 1: List the known quantities: 

  • Surface temperature, T = 3000 K

  • Luminosity, = 6.506 × 1023 W

  • Stefan's constant, σ = 5.67 × 10−8 W m−2 K−4

  • Radius of the Sun, R = 6.96 × 108 m

Step 2: Write down the Stefan-Boltzmann equation and rearrange for radius r

L = 4πR2σT4

R = L4πσT4

Step 3: Substitute the values into the equation 

R = 6.506×10234π×(5.67×108)×30004

Radius of Proxima Centauri:  R = 1.061 × 108 m

Step 4: Divide the radius of Proxima Centauri by the radius of the Sun

RR = 1.061 × 1086.96 × 108 = 0.152 R

  • Proxima Centauri has a radius which is about 0.152 times that of the Sun

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.