Upper & Lower Bounds (Cambridge (CIE) IGCSE Maths: Extended): Revision Note

Exam code: 0580 & 0980

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Bounds & error intervals

What are bounds?

  • Bounds are the values that a rounded number can lie between

    • The smallest value that a number can take is the lower bound (LB)

    • The largest value that a number must be less than is the upper bound (UB)

  • The bounds for a number, x, can be written as LB≤x<UB

    • Note that the lower bound is included in the range of values x but the upper bound is not

How do I find the upper and lower bounds for a rounded number?

  • Identify the degree of accuracy to which the number has been rounded

    • E.g. 24 800 has been rounded correct to the nearest 100

  • Divide the degree of accuracy by 2

    • E.g. If an answer has been rounded to the nearest 100, half the value is 50

  • Add this value to the number to find the upper bound

    • E.g. 24 800 + 50 = 24 850

  • Subtract this value from the number to find the lower bound

    • E.g. 24 800 - 50 = 24 750

  • The error interval is the range between the upper and lower bounds

    • Error interval: LB ≤ x < UB

    • E.g. 24 750 ≤ 24 800 < 24 850

Examiner Tips and Tricks

It can help to draw a number line. Identify the numbers with the same accuracy that come immediately before and after the rounded number.

  • The lower bound is the midpoint between the rounded number and the previous number at that accuracy

  • The upper bound is the midpoint between the rounded number and the next number at that accuracy

Number line showing rounding of a number to 24,800, with previous 100 at 24,700 and next 100 at 24,900. Bounds are 24,750 to 24,850.

Worked Example

The length of a road, l, is given as l=3.6 km, correct to 1 decimal place.

Find the lower and upper bounds for l.

Answer:

The degree of accuracy is 1 decimal place, or 0.1 km
Divide this value by 2

0.1 ÷ 2 = 0.05

The true value could be up to 0.05 km above or below the given value

Upper bound:  3.6 + 0.05 = 3.65 km

Lower bound:  3.6 - 0.05 =  3.55 km

Upper bound: 3.65 km
Lower bound: 3.55 km

This could also be written as  3.55 ≤ l < 3.65

Calculations using bounds

How do I find the bounds of a calculation?

  • To find the upper bound of a calculation, consider how the result can be made as large as possible

  • To find the lower bound of a calculation, consider how the result can be made as small as possible

  • E.g. For an addition, a+b

    • The upper bound will be when both a and b are at their upper bounds

    • The lower bound will be when both a and bare at their lower bounds

  • Sometimes you need different bounds in the same question

    • The upper bound of ab is the upper bound of a divided by the lower bound of b

      • Increasing the numerator makes the fraction bigger, 21<31<41<...

      • But increasing the denominator make the fraction smaller, 12>13>14>...

  • How to find the upper and lower bound for each operation is summarised in the table below

Upper Bound

Lower Bound

a+b

Upper + Upper

Lower + Lower

a−b

Upper - Lower

Lower - Upper

a×b

Upper × Upper

Lower × Lower

ab

Upper ÷ Lower

Lower ÷ Upper

  • You will need to use more than one of these if the expression includes multiple operations

    • E.g. consider the upper bound for ab−c

      • You need the upper bound for a and lower bound for b−c

      • This means you need the lower bound for b and upper bound for c

    • E.g. consider the lower bound for ab−c

      • You need the lower bound for ab and upper bound for c

      • This means you need the lower bound for a and upper bound for b

How do I use upper and lower bounds in contexts?

  • Questions often give real-life contexts and ask about bounds

    • For example

      • To see if two cars will fit on the back of a truck

      • Use the upper bounds of the lengths of the two cars

      • This is like finding the upper bound of a+b

    • For example

      • To find the minimum speed (speed = distance ÷ time)

      • Divide the lower bound of the distance by the upper bound of the time

      • This is like finding the lower bound of ab

How can bounds help with calculations?

  • You can use bounds to determine the level of accuracy of a calculation

    • E.g. If a value has a upper bound of 8.33217... and lower bound of s 8.33198...

      • The true value is between 8.33198... and 8.33217...

    • Find the level of accuracy for which both bounds round to the same number

      • This happens at 4 sf (rounding to 8.332)

      • To 5 sf they are different (lower is 8.3320 and upper is 8.3322)

    • Therefore you know the original value rounds to 8.332 to 4 significant figures

Worked Example

A room measures 4 m by 7 m, where each measurement is made to the nearest metre.

Find the upper and lower bounds for the area of the room.

Answer:

Find the bounds for each dimension, you could write these as error intervals, or just write down the upper and lower bounds

As they have been rounded to the nearest metre, the true values could be up to 0.5 m bigger or smaller

3.5 ≤ 4 < 4.5
6.5 ≤ 7 < 7.5

Calculate the lower bound of the area, using the two smallest measurements

3.5 × 6.5

Lower Bound = 22.75 m2

Calculate the upper bound of the area, using the two largest measurements

4.5 × 7.5

Upper Bound = 33.75 m2

Worked Example

David is trying to work out how many fencing panels he needs to buy in order to construct a fence along one side of his garden path.

Fencing panels are 50 cm long, measured to the nearest 10 cm.

The length of the path is 6 m, measured to the nearest 10 cm.

Find the minimum number of fencing panels David will need to buy.

Answer:

Find the bounds for each measurement

As they have been rounded to the nearest 10 cm, the true values could be up to 5 cm bigger or smaller

Change quantities into the same units

Length of the fencing panels: 45 ≤ 50 < 55 cm
or in metres: 0.45 ≤ 0.5 < 0.55 m

Length of the path: 5.95 ≤ 6 < 6.05 m

The minimum number of fencing panels needed will be when the path is as short as possible (5.95 m), and the panels are as long as possible (0.55 m)

Minimum number of fencing panels = 5.950.55=10.8181...

Assuming we can only purchase a whole number of fencing panels, round up to nearest integer

The minimum number of fencing panels to be bought is 11

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Questions students ask about Upper & Lower Bounds

Real questions from students revising this topic on Save My Exams

How do you know whether to use the upper or lower bound in calculations?

Decide whether the question wants the result as large as possible or as small as possible, then pick the bound of each value that pushes it that way.

  • a + b: upper = upper + upper; lower = lower + lower
  • a − b: upper = upper − lower; lower = lower − upper
  • a × b: upper = upper × upper; lower = lower × lower
  • a ÷ b: upper = upper ÷ lower; lower = lower ÷ upper, because a bigger denominator makes a fraction smaller

In context:

  • Will two cars fit on a truck? Add the upper bounds of both lengths
  • Minimum speed? Lower bound of distance ÷ upper bound of time

Example from this page: panels are 50 cm to the nearest 10 cm, so 0.45 ≤ panel < 0.55 m, and the path is 6 m to the nearest 10 cm, so 5.95 ≤ path < 6.05 m. The minimum number of panels uses the shortest path and the longest panel:

5.95 ÷ 0.55 = 10.818…, so David needs 11 panels.

Why do you divide the degree of accuracy by 2 to find upper and lower bounds?

You halve the degree of accuracy because a rounded number could have come from anything up to halfway to the next rounded value on either side.

  • Rounding sends a number to whichever value at that accuracy it is closest to
  • The switch-over point is exactly halfway between two neighbouring values
  • So the lower bound is the midpoint below and the upper bound is the midpoint above — half a step each way

Example from this page: x rounds to 24 800 to the nearest 100.

  • The values either side are 24 700 and 24 900
  • Half of 100 is 50
  • Lower bound: 24 800 − 50 = 24 750, the midpoint down
  • Upper bound: 24 800 + 50 = 24 850, the midpoint up
  • So 24 750 ≤ x < 24 850

The upper bound uses < rather than ≤ because 24 850 itself would round up to 24 900.

How do you know if an exam question requires you to calculate bounds?

If a question says values have been rounded or measured to some accuracy and then asks for a greatest, least, maximum or minimum result, it is a bounds question even if the word “bounds” never appears.

Clues to look for:

  • Accuracy wording: “correct to 1 decimal place”, “to the nearest metre”, “measured to the nearest 10 cm”
  • Size wording: maximum, minimum, greatest possible, least possible, smallest number of
  • Real-life checks, such as whether two things will fit or how many items you must buy
  • Being asked how accurate an answer is, or to give it to a suitable degree of accuracy

Example from this page: “Fencing panels are 50 cm long, measured to the nearest 10 cm. The length of the path is 6 m, measured to the nearest 10 cm. Find the minimum number of fencing panels.”

  • “Measured to the nearest 10 cm” tells you to find bounds
  • “Minimum” tells you which ones: shortest path ÷ longest panel
  • 5.95 ÷ 0.55 = 10.818…, so 11 panels
Naomi C

Author: Naomi C

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Naomi graduated from Durham University in 2007 with a Masters degree in Civil Engineering. She has taught Mathematics in the UK, Malaysia and Switzerland covering GCSE, IGCSE, A-Level and IB. She particularly enjoys applying Mathematics to real life and endeavours to bring creativity to the content she creates.

Dan Finlay

Reviewer: Dan Finlay

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Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.